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c: \(=\dfrac{3}{2}-1-21=\dfrac{3}{2}-21=\dfrac{-39}{2}\)
c: \(=\dfrac{3}{2}\cdot1-1-20=\dfrac{3}{2}-21=\dfrac{-39}{2}\)
a, \(-\frac{187}{70}\)
b,\(\frac{27}{70}\)
c,\(\frac{53}{14}\)
d,\(\frac{27}{4}\)
e,1
f,\(\frac{23}{4}\)
g,-1
i,6
k,315
l,\(\frac{9}{2}\)
\(a.=\frac{16}{21}+\left(\frac{5}{21}-\frac{5}{21}\right)+\left(\frac{4}{23}-\frac{4}{23}\right).\)
\(=\frac{16}{21}+0+0=\frac{16}{21}\)
\(b.=\left(\frac{3}{4}\right)^{3-2}=\left(\frac{3}{4}\right)^1=\frac{3}{4}\)
\(c.=\frac{1}{3}.\left(\frac{-4}{5}+\frac{-6}{5}\right)\)
\(=\frac{1}{3}.\left(-2\right)=\frac{-2}{3}\)
Nhớ k cho mình nhé! Thank you!!!
\(3\frac{1}{2}-\frac{1}{2}.\left(-4,25-\frac{3}{4}\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.\left(-4,25-0,75\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.\left(-5\right)^2:\frac{5}{4}\)
\(=\frac{7}{2}-\frac{1}{2}.5.\frac{4}{5}\)
\(=\frac{7}{2}-2\)
\(=\frac{7}{2}-\frac{4}{2}\)
\(=\frac{3}{2}\)
\(\frac{3}{7}.1\frac{1}{2}+\frac{3}{7}.0,5-\frac{3}{7}.9\)
\(=\frac{3}{7}.\left(\frac{3}{2}+\frac{1}{2}-9\right)\)
\(=\frac{3}{7}.\left(2-9\right)\)
\(=\frac{3}{7}.\left(-7\right)\)
\(=-3\)
\(\frac{125^{2016}.8^{2017}}{50^{2017}.20^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^2\right)^{2017}.2^{2017}.\left(2^2\right)^{2018}.5^{2018}}=\frac{\left(5^3\right)^{2016}.\left(2^3\right)^{2017}}{\left(5^3\right)^{2017}.\left(2^3\right)^{2017}.2.5}=\frac{1}{5^4.2}=\frac{1}{1250}\)( tính nhẩm, ko chắc đúng )
1
a) \(3\frac{1}{2}-\frac{1}{2}\cdot\left(-4,25-\frac{3}{4}\right)^2\) : \(\frac{5}{4}\)
= \(3\cdot25:\frac{5}{4}\)
= \(3\cdot\left(25:\frac{5}{4}\right)\)
=\(3\cdot20\)
=60
b)=\(\frac{3}{7}\cdot\left(1\frac{1}{2}+0,5-9\right)\)
=\(\frac{3}{7}\cdot\left(-7\right)\)
=\(-3\)
c) =
2)
a) \(\frac{1}{3}x-\left(-\frac{2}{3}\right)^2=\sqrt{\frac{16}{81}}\)
\(\Rightarrow\frac{1}{3}x-\frac{4}{9}=\frac{4}{9}\)
\(\Rightarrow\frac{1}{3}x=\frac{4}{9}+\frac{4}{9}\)
\(\Rightarrow\frac{1}{3}x=\frac{8}{9}\)
\(\Rightarrow x=\frac{8}{9}:\frac{1}{3}\)
\(\Rightarrow x=\frac{8}{3}\)
Vậy \(x=\frac{8}{3}.\)
b) \(4x-\frac{2}{5}+\frac{3}{4}=\frac{11}{4}\)
\(\Rightarrow4x-\frac{2}{5}=\frac{11}{4}-\frac{3}{4}\)
\(\Rightarrow4x-\frac{2}{5}=2\)
\(\Rightarrow4x=2+\frac{2}{5}\)
\(\Rightarrow4x=\frac{12}{5}\)
\(\Rightarrow x=\frac{12}{5}:4\)
\(\Rightarrow x=\frac{3}{5}\)
Vậy \(x=\frac{3}{5}.\)
Chúc bạn học tốt!
b: \(=2^5-1-9+21=53-10=43\)