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\(\left(25-x\right).2=18.1\)
\(\left(25-x\right).2=18\)
\(\left(25-x\right)=18:2\)
\(25-x=9\)
\(x=25-9\)
\(x=16\)
vậy x = 16
nha
\(\frac{25-x}{18}=\frac{1}{2}\)
\(=>\left(25-x\right).2=18\)
\(=>50-2x=18\)
\(\Rightarrow-2x=50-18\)
\(\Rightarrow-2x=32\)
\(\Rightarrow x=-16\)
vay \(x=-16\)
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
a) X = 15
b) X = 4
c ) X= 23
d) X= 11
( Chỉ là ý kiến riêng thôi nhé, nhận gạch đá )
a) \(\frac{6+x}{33}=\frac{7}{11}\)
=> (6 + x). 11 = 33.7
=> 66 + 11x = 231
=> 11x = 231 - 66
=> 11x = 165
=> x = 165 : 11
=> x = 15
b) 15/26 + x/13 = 46/52
=> x/13 = 23/26 - 15/26
=> x/13 = 4/13
=> x = 4
c) 121/27 x 54/11 < x < 100/21 : 25/126
=> 22 < x < 24
=> x = 23 (vì x là số tự nhiên)
d) 1 < 11/x < 12
=> 11/x \(\in\){2; 3; 4 ; ...; 11}
=> x \(\in\) {11/2; 11/3; ...; 1}
Vì x là số tự nhiên => x = 1
Xx11/5-Xx4/7=5/77
Xx(11/5-4/7)=5/77
Xx57/35=5/77
x=5/77:57/35=25/627
\(\dfrac{x-25-124}{2015}\) + \(\dfrac{x-124-2015}{25}\) + \(\dfrac{x-2015-25}{124}\) = 3
\(\dfrac{x-15-124}{2015}\) - 1 + \(\dfrac{x-124-2015}{25}\) - 1 + \(\dfrac{x-2015-25}{124}\) - 1 = 0
\(\dfrac{x-15-124-2015}{2015}\)+\(\dfrac{x-124-2015-25}{25}\)+\(\dfrac{x-2015-25-124}{124}\) = 0
\(\dfrac{x-\left(15+124+2015\right)}{2015}\)+\(\dfrac{x-\left(124+2015+25\right)}{25}\)+\(\dfrac{x-\left(2015+25+124\right)}{124}\) = 0
(\(x\) - 2164).(\(\dfrac{1}{2015}\)+\(\dfrac{1}{25}\)+\(\dfrac{1}{124}\)) = 0
\(x-2164\) = 0
\(x\) = 2164
\(\frac{4\sqrt{7}-5}{20}\)
\(\left(x+\frac{1}{4}\right)^2+\frac{11}{25}=\frac{18}{25}\)
\(\Rightarrow\left(x+\frac{1}{4}\right)^2=\frac{7}{25}\)
\(\Rightarrow x+\frac{1}{4}=\hept{\begin{cases}\sqrt{\frac{7}{25}}\\-\sqrt{\frac{7}{25}}\end{cases}}\)
\(\Rightarrow x=\hept{\begin{cases}\sqrt{\frac{7}{25}}-\frac{1}{4}\\-\sqrt{\frac{7}{25}}-\frac{1}{4}\end{cases}}\)