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21 tháng 7 2023
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
21 tháng 7 2023
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
7 tháng 10 2021
Bài 1:
a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)
b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)
Bài 2:
\(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)
Bài 3:
\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)
29 tháng 6 2015
-15/12. x+3/7=6/5.x-1/2
=> -15/12 . x +3/7+1/2 = 6/5 .x
=> -15/12 .x + 13/14= 6/5 .x
=> 49/20 .x = 13/14 => x= 130/343
PT
16 tháng 8 2021
a) \(-\dfrac{2}{5}+\dfrac{5}{6}x=-\dfrac{4}{15}\\ \Leftrightarrow\dfrac{5}{6}x=\dfrac{2}{15}\\ \Leftrightarrow x=\dfrac{4}{25}\)
b) \(\dfrac{2}{3}+\dfrac{7}{4}\div x=\dfrac{5}{6}\\ \Leftrightarrow\dfrac{7}{4}\div x=\dfrac{1}{6}\\ \Leftrightarrow x=\dfrac{7}{24}\)
16 tháng 8 2021
a: Ta có: \(-\dfrac{2}{5}+\dfrac{5}{6}x=\dfrac{-4}{15}\)
\(\Leftrightarrow x\cdot\dfrac{5}{6}=\dfrac{2}{15}\)
hay \(x=\dfrac{4}{25}\)
b: Ta có: \(\dfrac{7}{4}:x+\dfrac{2}{3}=\dfrac{5}{6}\)
\(\Leftrightarrow\dfrac{7}{4}:x=\dfrac{1}{6}\)
hay \(x=\dfrac{21}{2}\)
HQ
Hà Quang Minh
Giáo viên
16 tháng 9 2023
a)
\(\begin{array}{l}x - \left( { - \frac{7}{9}} \right) = - \frac{5}{6}\\x + \frac{7}{9} = - \frac{5}{6}\\x = - \frac{5}{6} - \frac{7}{9}\\x = - \frac{{15}}{{18}} - \frac{{14}}{{18}}\\x = \frac{{ - 29}}{{18}}\end{array}\)
Vậy \(x = \frac{{ - 29}}{{18}}\).
b)
\(\begin{array}{l}\frac{{15}}{{ - 4}} - x = 0,3\\x = \frac{{15}}{{ - 4}} - 0,3\\x = - 3,75 - 0,3\\x = - 4,05\end{array}\)
Vậy \(x = - 4,05\).
CD
2
BH
26 tháng 7 2019
\(a,\left|x\right|=15-5=10\Leftrightarrow\orbr{\begin{cases}x=10\\x=-10\end{cases}}\)
\(b,\left|x-2\right|+3x=7\)
*) Với x<2\(pt\Leftrightarrow2-x+3x=7\Leftrightarrow2x=5\Leftrightarrow x=\frac{5}{2}\)(loại )
*) Với \(x\ge2\Leftrightarrow x-2+3x=7\)\(\Leftrightarrow4x=9\Leftrightarrow x=\frac{9}{4}\)(thỏa mãn x>=2)
\(c,\left|x-1\right|+2x=6\)
*) Với x<1\(pt\Leftrightarrow1-x+2x=6\Leftrightarrow x=5\)(loại)
*) Với\(x\ge1\Leftrightarrow x-1+2x=6\Leftrightarrow3x=5\)\(\Leftrightarrow x=\frac{5}{3}\)(thỏa mãn x>=1)
26 tháng 7 2019
\(\text{a)}\left|x\right|+5=15\)
\(\Rightarrow\left|x\right|=10\)
\(\Rightarrow x=10\text{ hay }x=-10\)
\(\text{b)}\left|x-2\right|+3x=7\)
\(\Rightarrow\left|x-2\right|=7-3x\)
\(\text{TH1:}x-2\ge0\Rightarrow x\ge2\)
\(\Rightarrow x-2=7-3x\)
\(\Rightarrow x+3x=7+2\)
\(\Rightarrow4x=9\)
\(\Rightarrow x=\frac{9}{4}\left(\text{Nhận}\right)\)
\(\text{TH2:}x-2< 0\Rightarrow x< 2\)
\(\Rightarrow x-2=-\left(7-3x\right)\)
\(\Rightarrow x-2=-7+3x\)
\(\Rightarrow x-3x=-7+2\)
\(\Rightarrow-2x=-5\)
\(\Rightarrow x=\frac{5}{2}\left(\text{Loại}\right)\)
Vậy \(x=\frac{9}{4}\)
\(\text{c)}\left|x-1\right|+2x=6\)
\(\Rightarrow\left|x-1\right|=6-2x\)
\(\text{TH1:}x-1\ge0\Rightarrow x\ge1\)
\(\Rightarrow x-1=6-2x\)
\(\Rightarrow x+2x=6+1\)
\(\Rightarrow3x=7\)
\(\Rightarrow x=\frac{7}{3}\left(\text{Nhận}\right)\)
\(\text{TH2:}x-2< 0\Rightarrow x< 2\)
\(\Rightarrow x-1=-\left(6-2x\right)\)
\(\Rightarrow x-1=-6+2x\)
\(\Rightarrow x-2x=-6+1\)
\(\Rightarrow-x=-5\)
\(\Rightarrow x=5\left(\text{loại}\right)\)
Vậy \(x=\frac{7}{3}\)
19 tháng 8 2021
a: Ta có: \(\dfrac{1}{4}:x=3\dfrac{4}{5}:40\dfrac{8}{15}\)
\(\Leftrightarrow x=\dfrac{1}{4}\cdot\dfrac{\dfrac{608}{15}}{3+\dfrac{4}{5}}\)
\(\Leftrightarrow x=\dfrac{152}{15}:\dfrac{19}{5}=\dfrac{8}{3}\)
b: Ta có: \(\left(x+1\right):\dfrac{5}{6}=\dfrac{20}{3}\)
\(\Leftrightarrow x+1=\dfrac{50}{9}\)
hay \(x=\dfrac{41}{9}\)
c: Ta có: \(\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
\(\Leftrightarrow x^2-1=63\)
\(\Leftrightarrow x^2=64\)
hay \(x\in\left\{8;-8\right\}\)
NT
16 tháng 10 2022
c. \(\dfrac{7}{x-1}=\dfrac{x+1}{9}\)
\(7.9=\left(x-1\right).\left(x+1\right)\)
\(63=x^2-1\)
\(x^2=63+1\)
\(x^2=64\)
\(x^2=8^2\)
\(x=8\)
PP
0
\(\dfrac{x+6}{15}=\dfrac{5-x}{7}\Leftrightarrow7x+42=75-15x\Leftrightarrow22x=33\Leftrightarrow x=\dfrac{33}{22}=\dfrac{3}{2}\)
x=161/40