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\(\dfrac{x^2}{6}=\dfrac{24}{25}\)
\(\Leftrightarrow x^2=\dfrac{144}{25}\)
hay \(x\in\left\{\dfrac{12}{5};-\dfrac{12}{5}\right\}\)
\(\frac{x.x}{6}=\frac{24}{25}\Rightarrow25.x^2=24.6=144\Rightarrow x^2=\frac{144}{25}=\left(\frac{12}{5}\right)^2=\left(-\frac{12}{5}\right)^2\)
=> x =12/5 hoặc x = -12/5
\(x\times\frac{x}{6}=\frac{24}{25}\)
\(x=\frac{24}{25}:\frac{x}{6}\)
\(x=\frac{84}{25x}\)
\(25x^2=84\)
\(x^2=3,36\)
\(x=\frac{2\sqrt{21}}{5}\)
\(x^2=\frac{144}{25}=\left(\frac{12}{5}\right)^2\Leftrightarrow\orbr{\begin{cases}x=\frac{12}{5}\\x=-\frac{12}{5}\end{cases}}\)
\(\dfrac{x^2}{6}=\dfrac{24}{25}\)
\(\Rightarrow x^2=\dfrac{24.6}{25}=\dfrac{144}{25}\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
a) ĐKXĐ: \(x\ne-5\)
\(\Leftrightarrow7x-7=6x+30\\ \Leftrightarrow x=37\)
b) \(\Leftrightarrow25x^2=144\\ \Leftrightarrow x^2=\dfrac{144}{25}\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)
Ta có : 2516 = (52)16 = 532 = (54)8 = 6258
Lại có 624 = (63)8 = 2168
Vì 6258 > 2168
=> 2516 > 624
a: \(12\cdot25=15\cdot20\)
=>\(\dfrac{12}{15}=\dfrac{20}{25};\dfrac{12}{20}=\dfrac{15}{25};\dfrac{15}{12}=\dfrac{25}{20};\dfrac{20}{12}=\dfrac{25}{15}\)
b: \(3\cdot\left(-24\right)=6\cdot\left(-12\right)\)
=>\(\dfrac{3}{6}=\dfrac{-12}{-24};\dfrac{3}{-12}=\dfrac{6}{-24};\dfrac{6}{3}=\dfrac{-24}{-12};\dfrac{-12}{3}=\dfrac{-24}{6}\)
c: \(2,5\cdot3,5=7\cdot1,25\)
=>\(\dfrac{2.5}{7}=\dfrac{1.25}{3.5};\dfrac{2.5}{1.25}=\dfrac{7}{3.5};\dfrac{7}{2.5}=\dfrac{3.5}{1.25};\dfrac{1.25}{2.5}=\dfrac{3.5}{7}\)
x2/6= 24/25
=> x2.25=6.24
=> x2.25=144
=> x2 =144: 25
=> x2 =5,76
=> x =2,4
Vậy x=2,4
x=-2*căn bậc hai(6)/5
Lấy mẫu số chung là `150`
Nhân vs tử số kia là `x^2 . 25 = 24`