\(x+1,5=\dfrac{5}{3}\)

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7 tháng 6 2022

x + 1,5 = \(\dfrac{5}{3}\)

x   = \(\dfrac{5}{3}\) -  1,5

x = \(\dfrac{5}{3}\) - \(\dfrac{3}{2}\)

x = \(\dfrac{10}{6}\) - \(\dfrac{9}{6}\)

x = \(\dfrac{1}{6}\)

\(x+1,5=\dfrac{5}{3}\)

  \(x+\dfrac{3}{2}=\dfrac{5}{3}\)

          \(x=\dfrac{5}{3}-\dfrac{3}{2}\)

          \(x=\dfrac{1}{6}\)

19 tháng 9 2017

\(\dfrac{5}{6}x-\dfrac{3}{4}=\dfrac{-1}{4}+\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{5}{6}x=\dfrac{7}{6}\)

\(\Rightarrow x=\dfrac{7}{5}\)

b) \(-1\dfrac{1}{2}-\dfrac{2}{3}x=\dfrac{5}{6}-\left(\dfrac{-2}{5}\right)\)

\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{41}{15}\)

\(\Rightarrow x=-\dfrac{41}{10}\)

c) \(\left(\dfrac{4}{5}:x+1,5\right):\dfrac{2}{3}=-1,5\)

\(\Leftrightarrow\dfrac{8+15x}{10x}.\dfrac{3}{2}=\dfrac{-3}{2}\)

\(\Leftrightarrow\dfrac{24+45x}{20x}=\dfrac{-3}{2}\)

\(\Leftrightarrow-60x=48+90x\)

\(\Rightarrow x=-0,32\)

d) \(\dfrac{4}{3}x-\dfrac{2}{3}=\dfrac{1}{4}-x\)

\(\Leftrightarrow\dfrac{4x-2}{3}=\dfrac{1-4x}{4}\)

\(\Rightarrow16x-8=3-12x\)

\(\Rightarrow x=\dfrac{11}{28}\)

29 tháng 10 2017

a) \(\dfrac{1,2}{x+3}=\dfrac{5}{4}\)

\(\Rightarrow\left(x+3\right).5=1,2.4\)

\(\Rightarrow\left(x+3\right).5=4,8\)

\(\Rightarrow x+3=4,8:5\)

\(\Rightarrow x+3=0,96\)

\(\Rightarrow x=-2,04\)

vậy \(x=-2,04\)

b)\(\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{1}{2}:\dfrac{4}{5}\)

\(\Rightarrow\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{5}{8}\)

\(\Rightarrow\dfrac{2x}{15}=\dfrac{3}{5}:\dfrac{5}{8}\)

\(\Rightarrow\dfrac{2x}{15}=\dfrac{24}{25}\)

\(\Rightarrow15.24=\left(2x\right).25\)

\(\Rightarrow360=\left(2x\right).25\)

\(\Rightarrow360:25=2x\)

\(\Rightarrow14,4=2x\)

\(\Rightarrow x=7,2\)

vậy \(x=7,2\)

29 tháng 10 2017

\(a,\dfrac{1,2}{x+3}=\dfrac{5}{4}\\ \left(x+3\right).5=1,2.4\\ 5x+8=4,8\\ 5x=4,8-8\\ 5x=-3,2\\ x=-3,2:5=-0,64\)

\(b,\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{1}{2}:\dfrac{4}{5}\\ \dfrac{2x}{15}=\dfrac{3}{5}\cdot\dfrac{4}{5}:\dfrac{1}{2}\\ \dfrac{2x}{15}=\dfrac{12}{25}.2\\ \dfrac{2x}{25}=\dfrac{24}{25}\\ 2x=\dfrac{24}{25}.5\\ 2x=\dfrac{24}{5}\\ x=\dfrac{24}{5}\cdot\dfrac{1}{2}=\dfrac{12}{5}\)

\(c,-\dfrac{4}{2,5}:3,5=1,5:x\\ x=3,5.1,5:\left(-\dfrac{4}{25}\right)\\ x=\dfrac{21}{4}\cdot\left(-\dfrac{25}{4}\right)=-\dfrac{525}{16}\)

\(d,0,12:3=2x:\dfrac{3}{5}\\ 2x=0,12\cdot\dfrac{3}{5}:3\\ 2x=\dfrac{9}{125}\cdot\dfrac{1}{3}\\ 2x=\dfrac{3}{125}\\ x=\dfrac{3}{125}\cdot\dfrac{1}{2}=\dfrac{3}{250}\)

28 tháng 6 2017

a, \(\dfrac{5}{6}-\left|2-x\right|=\dfrac{1}{3}\Rightarrow\dfrac{5}{6}-\dfrac{1}{3}=\left|2-x\right|\)

<=> \(\dfrac{1}{2}=\left|2-x\right|\) \(\Leftrightarrow\left[{}\begin{matrix}2-x=\dfrac{1}{2}\\2-x=\dfrac{-1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)

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Mấy câu sau tương tự thôi

21 tháng 1 2018

a)\(\dfrac{3}{2}hay\dfrac{-3}{2}\)

b)\(\dfrac{13}{20}hay\dfrac{-13}{20}\)

c)\(\dfrac{11}{6}hay\dfrac{-11}{6}\)

d)\(\dfrac{4}{3}hay\dfrac{-4}{3}\)

e)\(\dfrac{1}{5}hay\dfrac{-1}{5}\)

Đây là câu trả lời của mình

Hay có nghĩa là hoặc

17 tháng 10 2022

a: \(\Leftrightarrow\dfrac{3}{5}-\dfrac{8}{5}\left(\dfrac{2}{3}x-\dfrac{3}{2}\right)=\dfrac{-17}{5}\)

=>8/5(2/3x-3/2)=3/5+17/5=4

=>2/3x-3/2=4:8/5=4*5/8=5/2

=>2/3x=4

=>x=4:2/3=6

b: =>x^2-4x-5=x^2-7x

=>-4x-5=-7x

=>3x=5

=>x=5/3

15 tháng 5 2017

a, \(\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\)

\(\Rightarrow\dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}\)

\(\Rightarrow\dfrac{x}{12}=\dfrac{11}{12}\)

\(\Rightarrow x=11\)

b, \(\dfrac{2}{3}-1\dfrac{4}{15}x=\dfrac{-3}{5}\)

\(\Rightarrow\dfrac{2}{3}-\dfrac{19}{15}x=\dfrac{-3}{5}\)

\(\Rightarrow\dfrac{19}{15}x=\dfrac{2}{3}+\dfrac{3}{5}\)

\(\Rightarrow\dfrac{19}{15}x=\dfrac{19}{15}\)

\(\Rightarrow x=1\)

c, \(-2^3+0,5x=1,5\)

\(\Rightarrow-8+\dfrac{1}{2}x=\dfrac{3}{2}\)

\(\Rightarrow\dfrac{1}{2}x=\dfrac{3}{2}+8\)

\(\Rightarrow\dfrac{1}{2}x=\dfrac{19}{2}\)

\(\Rightarrow x=19\)

15 tháng 5 2017

1) \(\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\) 2)\(\dfrac{2}{3}-1\dfrac{4}{15}x=\dfrac{-3}{5}\) \(\dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}\) \(\dfrac{2}{3}-\dfrac{19}{15}x=\dfrac{-3}{5}\) \(\dfrac{x}{12}=\dfrac{11}{12}\) \(\dfrac{19}{15}x=\dfrac{2}{3}-\left(\dfrac{-3}{5}\right)\) => \(x=11\) \(\dfrac{19}{15}x=\dfrac{19}{15}\) => \(x=1\) 3) -23 + 0,5x = 1,5 -8 + 0,5x = 1,5 0,5x = 1,5 - (-8) 0,5x = 9,5 x = 9,5 : 0,5 x = 19

20 tháng 12 2017

a. \(\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}\Rightarrow2x=\dfrac{1}{5}\Rightarrow x=\dfrac{1}{5}:2=0,1\)

Vậy \(x=0,1\)

b. \(\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}\Rightarrow-1\dfrac{3}{5}+x=\dfrac{13}{6}\cdot\dfrac{12}{13}=2\Rightarrow x=2+1\dfrac{3}{5}=3,6\)

Vậy \(x=3,6\)

c. \(-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)\Rightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}\Rightarrow-\dfrac{4}{7}x=-\dfrac{3}{40}-\dfrac{7}{5}=-\dfrac{59}{40}\Rightarrow x=\left(-\dfrac{59}{40}\right):\left(-\dfrac{4}{7}\right)=2,58125\)

Vậy \(x=2,58125\)

a: =>x/3=-5/2

hay x=-15/2

b: \(\Leftrightarrow\dfrac{7}{3}:x=\dfrac{1}{5}-\dfrac{4}{9}=\dfrac{9-20}{45}=\dfrac{-11}{45}\)

\(\Leftrightarrow x=\dfrac{7}{3}:\dfrac{-11}{45}=\dfrac{7}{3}\cdot\dfrac{-45}{11}=\dfrac{-105}{11}\)

c: \(\Leftrightarrow x=\dfrac{-7}{2}\cdot2=-7\)

d: =>x/27=-1/3+2/9=2/9-3/9=-1/9=-3/27

=>x=-3

21 tháng 11 2022

1: =>1/3:x=3/5-2/3=9/15-10/15=-1/15

=>x=-1/3:1/15=5

2: \(\Leftrightarrow x\cdot\dfrac{2}{3}-3=\dfrac{2}{5}\cdot\left(-10\right)=-4\)

=>x*2/3=-1

=>x=-3/2

3: \(\Leftrightarrow\dfrac{8}{3}:x=\dfrac{25}{12}:\dfrac{-3}{50}=\dfrac{25}{12}\cdot\dfrac{-50}{3}\)

hay x=-48/625

9: =>x=-2*3/1,5=-4

8: =>2/3:x=5/2:-3/10=5/2*(-10)/3=-50/6=-25/3

=>x=-2/3:25/3=-2/3*3/25=-2/25

24 tháng 7 2017

|2x-1|=1,5

TH(1)2x-1=1,5

2x =1,5+1

2x =2,5

x =2,5 :2

x =1,25

TH(2) 2x-1=-1,5

2x =-1,5+1

2x =-0,5

x =-0,5:2

x =-0,25

các câu khác cứ tương tự bạn nhé

24 tháng 7 2017

b) \(7,5-\left|5-2x\right|=-4,5\)

\(\left|5-2x\right|=7,5+4,7\)

\(\left|5-2x\right|=12\)

th1 :\(5-2x=12\)

\(2x=5-12\)

\(2x=-7\)

\(x=-7:2\)

\(x=-3,5\)

th2: \(5-2x=-12\)

\(2x=5+12\)

\(2x=17\)

\(x=17:2\)

\(x=8,5\)

c) \(-3+\left|x\right|=-1\)

\(\left|x\right|=-1+3\)

\(\left|x\right|=2\)

th1: \(x=-2\)

th2 : \(x=2\)

d)\(\left|2\dfrac{1}{3}-x\right|=\dfrac{1}{6}\)

\(\left|\dfrac{7}{3}-x\right|=\dfrac{1}{6}\)

th1 :\(\dfrac{7}{3}-x=\dfrac{1}{6}\)

\(x=\dfrac{7}{3}-\dfrac{1}{2}\)

\(x=\dfrac{11}{6}\)

th2: \(\dfrac{7}{3}-x=\dfrac{-1}{6}\)

\(x=\dfrac{7}{3}+\dfrac{1}{6}\)

\(x=\dfrac{-5}{2}\)

e) \(\dfrac{5}{7}-\left|x+1\right|=\dfrac{1}{14}\)

\(\left|x+1\right|=\dfrac{5}{7}-\dfrac{1}{14}\)

\(\left|x+1\right|=\dfrac{9}{14}\)

th1 :\(x+1=\dfrac{9}{14}\)

\(x=\dfrac{9}{14}-1\)

\(x=\dfrac{-5}{14}\)

th2 : \(x+1=\dfrac{-9}{14}\)

\(x=\dfrac{-9}{14}-1\)

\(x=\dfrac{-5}{14}\)

\(K=5\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{45\cdot46}\right)\)

\(=5\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{45}-\dfrac{1}{46}\right)\)

=5*45/46=225/46

\(T=\dfrac{1}{5}\cdot\sqrt{6\cdot\dfrac{2}{3}}-\dfrac{3}{2}\cdot\sqrt{\dfrac{2}{3}\cdot\dfrac{8}{75}}+\dfrac{1}{2}\cdot\sqrt{6\cdot\dfrac{8}{75}}\)

\(=\dfrac{1}{5}\cdot2-\dfrac{3}{2}\cdot\dfrac{4}{15}+\dfrac{1}{2}\cdot\dfrac{4}{5}\)

=2/5-12/30+4/10

=2/5