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7 tháng 3 2022
\(a,x-\dfrac{1}{4}=\dfrac{7}{2}.\dfrac{-3}{5}\\ \Rightarrow x-\dfrac{1}{4}=\dfrac{-21}{10}\\ \Rightarrow x=\dfrac{-21}{10}+\dfrac{1}{4}\\ \Rightarrow x=\dfrac{-37}{20}\\ b,\dfrac{x}{134}=\dfrac{9}{7}.\dfrac{5}{-11}\\ \Rightarrow\dfrac{x}{134}=\dfrac{-45}{77}\\ \Rightarrow x=\dfrac{-45}{77}.134\\ \Rightarrow x=\dfrac{-6030}{77}\)
O
7 tháng 3 2022
\(x-\dfrac{1}{4}=\dfrac{7}{2}\cdot\dfrac{-3}{5}\)
\(x-\dfrac{1}{4}=\dfrac{-21}{10}\)
\(x=\dfrac{-21}{10}+\dfrac{1}{4}\)
\(x=\dfrac{-37}{20}\)
b ) \(\dfrac{x}{134}=\dfrac{9}{7}\cdot\dfrac{5}{-11}\)
\(\dfrac{x}{134}=\dfrac{9}{7}\cdot\dfrac{-5}{11}\)
\(\dfrac{x}{134}=\dfrac{-45}{77}\)
\(x=\dfrac{-45}{77}\cdot134\)
\(x=-\dfrac{6034}{77}\)
NH
4
19 tháng 8 2023
a: =>7(135:x-13)=14
=>135:x-13=2
=>135:x=15
=>x=9
b: =>11x-66-4x=11
=>7x=77
=>x=11
H9
HT.Phong (9A5)
CTVHS
19 tháng 8 2023
\(120+\left(135:x-13\right)\cdot7=134\)
\(\Rightarrow\left(135:x-13\right)\cdot7=134-120\)
\(\Rightarrow\left(135:x-13\right)\cdot7=14\)
\(\Rightarrow135:x-13=14:7\)
\(\Rightarrow135:x=2+13\)
\(\Rightarrow135:x=15\)
\(\Rightarrow x=135:15\)
\(\Rightarrow x=9\)
_______________
\(11\cdot\left(x-6\right)=4\cdot x+11\)
\(\Rightarrow11\cdot x-66=4\cdot x+11\)
\(\Rightarrow11\cdot x-4\cdot x=11+66\)
\(\Rightarrow7\cdot x=77\)
\(\Rightarrow x=77:7\)
\(\Rightarrow x=11\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 10 2023
4.\(x\) + 2.[3.\(x\) - 11] = 134
4.\(x\) + 6.\(x\) - 22 = 134
10\(x\) = 134 + 22
10\(x\) = 156
\(x\) = 156 : 10
\(x\) = 15,6
DD
2
26 tháng 12 2016
a) -175 - ( -7 . 5^2 + 4 . 2^3)
= -175 - ( -175 + 32 )
= -175 - -175 +32
= 0 +32
= 32
26 tháng 12 2016
b) (-27) + 20 + (-9) + 27 + (-11)
= (-27 + 27 ) + 20 + (-11) + (- 9)
= 0 + 9 + (-9)
= 0 + 0
= 0
SS
3 tháng 3 2023
3/7.9/11+3/7.5/11-3/7.25/11
=3/7.(9/11+5/11-25/11)
=3/7.(-1)
=-3/7
LM
Lê Minh Vũ
CTVHS
14 tháng 6 2023
\(\left(-\dfrac{1}{2}\right)^2\div\dfrac{1}{4}-2\times\left(-\dfrac{1}{2}\right)^2\\= \dfrac{1}{4}\div\dfrac{1}{4}-2\times\dfrac{1}{4}\\ =1-\dfrac{1}{2}\\ =\dfrac{1}{2}\)
\(\left(-2\right)^3\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right)\div\dfrac{5}{12}\)
= \(-6\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right)\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{1}{2}\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{6}{5}\)
= \(\dfrac{1}{4}-\dfrac{6}{5}\)
= \(-\dfrac{19}{20}\)
\(\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\\ =\dfrac{58}{9}+\dfrac{7}{11}-\dfrac{40}{9}+\dfrac{26}{11}\\ =\dfrac{58}{9}-\dfrac{40}{9}+\dfrac{7}{11}+\dfrac{26}{11}\\ =12+3\\ =15\)
TA
14 tháng 6 2023
\(a,\left(\dfrac{-1}{2}\right)^2:\dfrac{1}{4}-2\left(-\dfrac{1}{2}\right)^2\)
\(=\left(-\dfrac{1}{2}\right)^2\left(4-2\right)\)
\(=\dfrac{1}{4}.2=\dfrac{1}{2}\)
\(b,\left(-2\right)^3.\dfrac{-1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)
\(=\left(-8\right).\dfrac{-1}{24}+\left(-\dfrac{1}{2}\right).\dfrac{12}{5}\)
\(=\dfrac{1}{3}+\left(-\dfrac{1}{5}\right)=\dfrac{2}{15}\)
\(c,\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\)
\(=\dfrac{701}{99}-\dfrac{206}{99}=\dfrac{495}{99}=5\)
\(d,10\dfrac{1}{5}-5\dfrac{1}{2}.\dfrac{60}{11}+\dfrac{3}{15\%}\)
\(=\dfrac{51}{5}-30+20=\dfrac{1}{5}\)
\(e,\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}.\left(-\dfrac{7}{11}\right)\)
\(=-\dfrac{5}{11}\)
\(f,\dfrac{-5}{7}.\dfrac{2}{11}+\left(-\dfrac{5}{7}\right).\dfrac{9}{11}+1\dfrac{5}{7}\)
\(=\left(-\dfrac{5}{7}\right)\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{12}{7}\)
\(=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=1\)
\(\frac{x}{134}=\frac{9}{7}\cdot\frac{5}{-11}\)
\(\frac{x}{134}=\frac{9\cdot\left(-5\right)}{7\cdot11}\)
\(\frac{x}{134}=\frac{-45}{77}\)