Câu hỏi của Trần Thị Thúy Cầm

Question

x+1/10+x+1/11+x+1/12=x+1/13+x+1/14

Nguyễn Hoàng Anh Phong · Accepted Answer

$\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}$$\Rightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0$$\Rightarrow\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0$mà 1/10 > 1/13; 1/11>1/14$\Rightarrow\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0$=> x + 1 = 0x = -1Câu trả lời: $\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}$$\Rightarrow\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}-\frac{x+1}{13}-\frac{x+1}{14}=0$$\Rightarrow\left(x+1\right).\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0$mà 1/10 > 1/13; 1/11>1/14$\Rightarrow\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0$=> x + 1 = 0x = -1

Anh Thu Tran · Answer

x+110+x+111+x+112=x+113+x+114x+110+x+111+x+112=x+113+x+114⇒x+110+x+111+x+112−x+113−x+114=0⇒x+110+x+111+x+112−x+113−x+114=0⇒(x+1).(110+111+112−113−114)=0⇒(x+1).(110+111+112−113−114)=0mà 1/10 > 1/13; 1/11>1/14⇒110+111+112−113−114≠0⇒110+111+112−113−114≠0=> x + 1 = 0x = -1Câu trả lời: x+110+x+111+x+112=x+113+x+114x+110+x+111+x+112=x+113+x+114⇒x+110+x+111+x+112−x+113−x+114=0⇒x+110+x+111+x+112−x+113−x+114=0⇒(x+1).(110+111+112−113−114)=0⇒(x+1).(110+111+112−113−114)=0mà 1/10 > 1/13; 1/11>1/14⇒110+111+112−113−114≠0⇒110+111+112−113−114≠0=> x + 1 = 0x = -1

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