\(^3\)-(x\(^3\)-y\(^3\))+6xy...">
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a: \(=x^3-3x^2+3x-1-x^3-64+3x^2-3x\)

=-65

\(=8x^3+27y^3-8x^3+27y^3-54y^3+27\)

=27

c: \(=y\left(x^4-y^4\right)-y\left(x^4-y^4\right)=0\)

d: \(=x^3-3x^2+3x-1-x^3+1-3x\left(1-x\right)\)

\(=-3x^2+3x-3x+3x^2=0\)

17 tháng 7 2018

1/ a/ \(\left(x+y\right)^3=\left(x+y\right)\left(x+y\right)^2=\left(x+y\right)\left(x^2+2xy+b^2\right)=x^3+2x^2y+x^2y+xy^2+2xy^2+y^3=x^3+3x^2y+3xy^2+y^3\)

b/ \(\left(x-y\right)^3=\left(x-y\right)\left(x-y\right)^2=\left(x-y\right)\left(x^2-2xy+y^2\right)=x^3-2x^2y-x^2y+2xy^2+xy^2-y^3=x^3-3x^2y+3xy^2+y^3\)2/

a/ \(x\left(8x-2\right)-8x^2+12=0\)

\(\Leftrightarrow8x^2-2x-8x^2+12=0\)

\(\Leftrightarrow-2x+12=0\)

\(\Leftrightarrow x=6\)

Vậy ...

b/ \(\left(x-1\right)^3-x\left(x^2-3x+1\right)=18\)

\(\Leftrightarrow x^3-3x^2+3x-1-x^3+3x^2-x=18\)

\(\Leftrightarrow2x-1=18\)

\(\Leftrightarrow x=\dfrac{19}{2}\)

Vậy...

3/ a, \(25-x^2=5^2-x^2=\left(5-x\right)\left(5+x\right)\)

b/ \(4x^2-4x+1=\left(2x\right)^2-2.2x.1+1^2=\left(2x-1\right)^2\)

c/ \(9x^2+6xy+y^2=\left(3x\right)^2+2.3x.y+y^2=\left(3x+y\right)^2\)

29 tháng 10 2017

1,Thực hiện phép tính :

a, (x + 2)9 : (x + 2)6

=(x+2)9-6

=(x+2)3

b, (x - y) 4 : (x - 2)3

=(x-y)4-3

=x-y

c, ( x2+ 2x + 4)5 : (x2 + 2x + 4)

=(x2+2x+4)5-1

=(x2+2x+4)4

d, 2(x2 + 1)3 : 1/3(x2 + 1)

=(2÷1/3).[(x2+1)3÷(x2+1)]

=6(x2+1)2

e, 5 (x - y)5 : 5/6 (x - y)2

=(5÷5/6).[(x-y)5÷(x-y)2]

=6(x-y))3

b: \(=3\left[\left(x+y\right)^2-2xy\right]-2\left[\left(x-y\right)^3+3xy\left(x-y\right)\right]\)

\(=3\left(1-2xy\right)-2\left(1+3xy\right)\)

\(=3-6xy-2-6xy=-12xy+1\)

c: \(=\left(x+y\right)^3-3\left(x^2+y^2+2xy\right)+3\left(x+y\right)+2012\)

\(=101^2-3\cdot101^2+3\cdot101+2012\)

=1002013

5 tháng 7 2017

a, = (x+3y)^2

b, = (x-1/2)(x+1/2)

c, = (x-5)^2

d, = (2x+3y)(4x^2-6xy+9y^2)

e, = (x^3-y)^2

f,= (x+3y)^3

19 tháng 7 2018

6)   \(9x^2+6xy+y^2=\left(3x+y\right)^2\)

7)   \(x^2-3x-y^2-3y=\left(x-y-3\right)\left(x+y\right)\)

8)   \(x^2-2xy+y^2-16=\left(x-y\right)^2-16=\left(x-y-4\right)\left(x-y+4\right)\)

9)   \(4x^2-y^2+4x+1=\left(2x+1\right)^2-y^2=\left(2x-y+1\right)\left(2x+y+1\right)\)

10)  \(x^3-x+y^3-y=\left(x+y\right)\left(x^2-xy+y^2+1\right)\)

6) = (3x)2 + 2.(3x)y +y2 = (3x + y)2

7) = (x-y)(x+y)- 3(x+y) = (x+y)(x-y-3)

8) = (x-y) - 4= (x-y-4)(x-y+4)

9) = ( 4x2 + 4x +1 ) - y2 = (2x+1)2 - y^2 = (2x+1-y)(2x+1+y)

10) =(x3+y3) - (x+y) = (x+y)(x2+xy+y2) - (x+y) = (x+y)(x2+xy+y2-1)

k mk đi nha

a: \(=\dfrac{5}{2}x-2x+\dfrac{7}{2}=\dfrac{1}{2}x+\dfrac{7}{2}\)

b: \(=\dfrac{-1}{4}x^4-3x^2+\dfrac{9}{4}x\)

c: \(=\dfrac{1}{5}x+\dfrac{1}{15}xy+\dfrac{7}{10}x^2\)

d: \(=-9x^3-1-12y+27xy\)