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a) \(6.8^{x-1}+8^{x+1}=6.8^{19}+8^{21}\)
\(\Rightarrow x-1+x+1=19+21\)
\(=2x=40\)
\(\Rightarrow x=20\)
b) \(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(\Rightarrow x-1+x+2=6+9\)
\(\Rightarrow2x+1=15\)
\(\Rightarrow2x=14\)
\(\Rightarrow x=7\)
a,
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Rightarrow5^{x+3}\left(5-3\right)=2.5^{11}\)
\(\Rightarrow5^{x+3}2=2.5^{11}\)
\(\Rightarrow5^{x+3}=5^{11}\)
\(\Rightarrow x+3=11\)
\(\Rightarrow x=8\)
b, (Check lai xem de sai o dau khong nhe)
\(3.5^{x+2}+4.5^{x+3}=19.5^{10}\)
Dat 5x ra ben ngoai
\(\Rightarrow5^x.5^23+5^x:5^{-3}.4\)
\(\Rightarrow5^x\left(5^2.3+5^{-3}.4\right)\)
\(\Rightarrow5^x\left(5^{-3}.5^5.3+5^{-3}.4\right)\)
\(\Rightarrow5^x[5^{-3}\left(5^53+4\right)\)
\(\Rightarrow5^x[5^{-3}\left(3125.3+4\right)\)
\(\Rightarrow5^x\left(5^{-3}\right).9379\)
=> Khong tim duoc gia tri cua x \(\Rightarrow x\in\varnothing\)
A)\(\left(4-\frac{8}{3}\right)x\frac{15}{7}-\frac{8}{5}:\frac{1}{10}\)
\(=\frac{4}{3}x\frac{15}{7}-\frac{8}{5}x\frac{1}{10}\)
\(=\frac{20}{7}-\frac{4}{25}\)
\(=\frac{222}{185}\)
B)\(\frac{7}{5}x\frac{3}{8}+\frac{7}{5}x\frac{5}{8}-\frac{37}{5}\)
\(=\frac{7}{5}x\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{37}{5}\)
\(=\frac{7}{5}x1-\frac{37}{5}\)
\(=\frac{7}{5}-\frac{37}{5}\)
\(=\frac{-30}{5}
\)
\(=-6\)
A =\(\left(4-\frac{8}{3}\right).\frac{15}{7}-\frac{8}{5}:\frac{1}{10}\)
\(=\frac{4}{3}.\frac{15}{7}-16\)
\(=\frac{20}{7}-\frac{112}{7}\)
\(=\frac{-92}{7}\)
B\(=\frac{7}{5}.\frac{3}{8}+\frac{7}{5}.\frac{5}{8}-\frac{37}{5}\)
\(=\frac{7}{5}.\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{37}{5}\)
\(=\frac{7}{5}-\frac{37}{5}\)
\(=-6\)
a)(x-8)(x3+8)=0
<=>x-8=0 hoặc x3+8=0
<=>x=8 hoặc x3=-8
<=>x=8 hoặc x=-2
b)(4x-3)-(x+5)=3(10-x)
<=>4x-3-x-5=30-3x
<=>(4x-x)+(-3-5)=30-3x
<=>3x-8=30-3x
<=>6x=38
<=>x=\(\frac{38}{6}=\frac{19}{3}\)
Bài 1:
a; \(\dfrac{7}{8}\) + \(x\) = \(\dfrac{4}{7}\)
\(x\) = \(\dfrac{4}{7}\) - \(\dfrac{7}{8}\)
\(x\) = \(\dfrac{32}{56}\) - \(\dfrac{49}{56}\)
\(x=-\) \(\dfrac{49}{56}\)
Vậy \(x=-\dfrac{49}{56}\)
b; 6 - \(x\) = - \(\dfrac{3}{4}\)
\(x\) = 6 + \(\dfrac{3}{4}\)
\(x\) = \(\dfrac{24}{4}+\dfrac{3}{4}\)
\(x=\dfrac{27}{4}\)
Vậy \(x=\dfrac{27}{4}\)
c; \(\dfrac{1}{-5}\) + \(x\) = \(\dfrac{3}{4}\)
\(x\) = \(\dfrac{3}{4}\) + \(\dfrac{1}{5}\)
\(x=\dfrac{15}{20}\) + \(\dfrac{4}{20}\)
\(x=\dfrac{19}{20}\)
Vậy \(x=\dfrac{19}{20}\)
Bài 1:
d; - 6 - \(x\) = - \(\dfrac{3}{5}\)
\(x\) = - 6 + \(\dfrac{3}{5}\)
\(x=-\dfrac{30}{5}\) + \(\dfrac{3}{5}\)
\(x=-\dfrac{27}{5}\)
Vậy \(x=-\dfrac{27}{5}\)
e; - \(\dfrac{2}{6}\) + \(x\) = \(\dfrac{5}{7}\)
\(x\) = \(\dfrac{5}{7}\) + \(\dfrac{2}{6}\)
\(x\) = \(\dfrac{15}{21}\) + \(\dfrac{1}{3}\)
\(x=\dfrac{15}{21}\) + \(\dfrac{7}{21}\)
\(x=\dfrac{22}{21}\)
Vậy \(x=\dfrac{22}{21}\)
f; - 8 - \(x\) = - \(\dfrac{5}{3}\)
\(x\) = \(-\dfrac{5}{3}\) + 8
\(x\) = \(\dfrac{-5}{3}\) + \(\dfrac{24}{3}\)
\(x\) = \(\dfrac{-19}{3}\)
Vậy \(x=-\dfrac{19}{3}\)
a) \(\frac{5}{6}\)x - \(\frac{3}{8}\)x - 10 = 12
=> \(\left(\frac{5}{6}-\frac{3}{8}\right)\)x = 12 + 10
=> \(\frac{11}{24}\)x = 22
=> x = 22 : \(\frac{11}{24}\)
=> x = 48
Vậy x = 48.
b) (\(\left|x\right|\) - \(\frac{1}{8}\)) . \(\left(-\frac{1}{8}\right)^5\) = \(\left(-\frac{1}{8}\right)^7\)
=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\left(-\frac{1}{8}\right)^7\) : \(\left(-\frac{1}{8}\right)^5\)
=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\left(-\frac{1}{8}\right)^{7-5}\)
=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\frac{1}{64}\)
=> \(\left|x\right|\) = \(\frac{1}{64}\) + \(\frac{1}{8}\)
=> \(\left|x\right|\) = \(\frac{9}{64}\)
=> x = \(\frac{9}{64}\) hoặc x = \(\frac{-9}{64}\)
Vậy x = \(\frac{9}{64}\) hoặc x = \(\frac{-9}{64}\)
hên quá làm đúng hì hì, cảm ơn nhen, hết sợ bị sai ồi