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\(2x+3=8\)
\(\Rightarrow2x=8-3\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\dfrac{5}{2}\)
\(x:5-2=3\)
\(\Rightarrow x:5=3+2\)
\(\Rightarrow x:5=5\)
\(\Rightarrow x=5\cdot5\)
\(\Rightarrow x=25\)
\(x:7-2=19\)
\(\Rightarrow x:7=19+2\)
\(\Rightarrow x:7=21\)
\(\Rightarrow x=21\cdot7\)
\(\Rightarrow x=147\)
Mình chưa rõ đề
\(20-\left(x+3\right)=5\)
\(\Rightarrow-x-3=5-20\)
\(\Rightarrow-x-3=-15\)
\(\Rightarrow-x=-15+3\)
\(\Rightarrow-x=-12\)
\(\Rightarrow x=12\)
A= 1/2 x 3 + 1/3 x 4 + 1/4 x 5 + 1/5 x 6 + 1/6 x 7 + ... + 1/19 x 20
--> A= 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 +...+ 1/19 - 1/20
= 1/2 - 1/20 = 10/20 - 1/20 = 9/20
7,5x . 519 = 5 20 . 511
7,5x . 519 = 531
7,5x =531:519
7,5x=512
Tìm x :
5x . 519 = 520 . 511
520 . 511 = 520 + 11
520 . 511 = 531
5x = 531 : 519
5x = 531 - 19
5x = 512
x = 12
Vậy : x = 12
2)
\(2+\dfrac{5}{7}+\left(\dfrac{\dfrac{3}{19}+\dfrac{3}{23}-\dfrac{3}{28}}{\dfrac{5}{19}+\dfrac{5}{23}-\dfrac{5}{28}}\right)\cdot x=\dfrac{20}{7}\\ \left[\dfrac{3\cdot\left(\dfrac{1}{19}+\dfrac{1}{23}-\dfrac{1}{28}\right)}{5\cdot\left(\dfrac{1}{19}+\dfrac{1}{23}-\dfrac{1}{28}\right)}\right]\cdot x=\dfrac{20}{7}-\dfrac{5}{7}-2\\ \dfrac{3}{5}x=\dfrac{15}{7}-2\\ \dfrac{3}{5}x=\dfrac{1}{7}\\ x=\dfrac{5}{21}\)
|x - 5| + 19 = 20
|x -5 | = 20 - 19
| x - 5| = 1
\(\left[{}\begin{matrix}x-5=1\\x-5=-1\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=6\\x=4\end{matrix}\right.\)
\(x\in\) { 4; 6}
\(|x-5|=1\)
\(\left\{{}\begin{matrix}x-5=1\\x-5=-1\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x=6\\x=4\end{matrix}\right.\)