Câu hỏi của đỗ ninh kiên

Question

(X-20).(X-8).(x-2022)=0

x=bao nhieu giup minh voi

Vũ Đức Thịnh · Accepted Answer

Ta có :

(x-20).(x-8).(x-2022) = 0

$\Rightarrow\left[{}\begin{matrix}x-20=0\x-8=0\x-2022=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=20\x=8\x=2022\end{matrix}\right.$

Vậy $\left[{}\begin{matrix}x=20\x=8\x=2022\end{matrix}\right.$

Câu trả lời:

Ta có :

(x-20).(x-8).(x-2022) = 0

$\Rightarrow\left[{}\begin{matrix}x-20=0\x-8=0\x-2022=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=20\x=8\x=2022\end{matrix}\right.$

Vậy $\left[{}\begin{matrix}x=20\x=8\x=2022\end{matrix}\right.$

Chuu · Answer

`(x-20).(x-8).(x-2022)=0`

`=>` $\left[{}\begin{matrix}x-20=0\x-8=0\x-2022=0\end{matrix}\right.$

`=>`$\left[{}\begin{matrix}x=0+20=20\x=0+8=8\x=0+2022=2022\end{matrix}\right.$

Vậy `x = {20;8;2022}`

Câu trả lời:

`(x-20).(x-8).(x-2022)=0`

`=>` $\left[{}\begin{matrix}x-20=0\x-8=0\x-2022=0\end{matrix}\right.$

`=>`$\left[{}\begin{matrix}x=0+20=20\x=0+8=8\x=0+2022=2022\end{matrix}\right.$

Vậy `x = {20;8;2022}`