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`@` `\text {Ans}`

`\downarrow`

\(x\div\dfrac{1}{5}+x\div\dfrac{1}{7}+x\div\dfrac{1}{9}=42\)

\(\Rightarrow x\cdot5+x\cdot7+x\cdot9=42\)

\(\Rightarrow x\cdot\left(5+7+9\right)=42\)

\(\Rightarrow x\cdot21=42\)

\(\Rightarrow x=42\div21\)

\(\Rightarrow x=2\)

Vậy, `x = 2.`

29 tháng 7 2018

A)  7/38 x 9/11 +7/38 x 4/11 -7/38 x 2/11

=7/38.(9/11+4/11-2/11)

=7/38

B) 5/31 x 21/25 + 5/31 x -7/10 - 5/31 x 9/20

=5/31.(21/25-7/10-9/20)

=5/31.(-31/100)

=-1/20

d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...

 

8 tháng 12 2015

e) x-[42+(-28)]=-8

=> x-14=-8

=> x=-8+14

=> x=-6

f) |x-3|=|5|+|-7|

=> |x-3|=5+7=12

=> x-3=12 hoặc x-3=-12

=> x=12+3 hoặc x=-12+3

=> =15 hoặc x=-9

h) 9x-1=9

=> 9x=9+1=10

=> x=10/9

g) 3x=9 

=> x=9:3=3

 

4 tháng 8 2018


\(a,-12\left(x-5\right)+7\left(3-x\right)=5\)
     \(-12x+60+21-7x=5\)
     \(-12x-7x+81=5\)
     \(-19x=5-81\)
     \(-19x=-76\)
      \(x=-76:\left(-19\right)\)
      \(x=4\)
\(Vậyx=4\)
\(b,30\left(x+2\right)-6\left(x-5\right)-24x=100\)
     \(30x+60-6x-30-24x=100\)
     \(30x-6x-24x+60-30=100\)
     \(0x+30=100\)
\(\Rightarrow Vôlý\)
Vậy không có giá trị nào của x thỏa mãn đề bài.
\(c,-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
     \(-5x-1-\frac{1}{2}x-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
      \(-5x-\frac{1}{2}x-1-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
      \(-\frac{11}{2}x-\frac{2}{3}=\frac{3}{2}x-\frac{5}{6}\)
       \(-\frac{2}{3}+\frac{5}{6}=\frac{3}{2}x+\frac{11}{2}x\)
        \(-\frac{4}{6}+\frac{5}{6}=\frac{14}{2}x\)
         \(\frac{1}{6}=7x\)
          \(x=\frac{1}{6}:7\)

         \(x=\frac{1}{6}.\frac{1}{7}\)
         \(x=\frac{1}{42}\)
\(Vậyx=\frac{1}{42}\)
\(d,-3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)

      \(-3x+\frac{3}{2}-5x-3=-x+\frac{1}{5}\)
      \(-3x-5x+\frac{3}{2}-3=-x+\frac{1}{5}\)
      \(-8x+\frac{3}{2}-\frac{6}{2}=-x+\frac{1}{5}\)
       \(-8x-\frac{3}{2}=-x+\frac{1}{5}\)
        \(-\frac{3}{2}-\frac{1}{5}=-x+8x\)
        \(\frac{15}{10}-\frac{2}{10}=7x\)

         \(7x=\frac{13}{10}\)
          \(x=\frac{13}{10}:7\)
          \(x=\frac{13}{10}.\frac{1}{7}\)
          \(x=\frac{13}{70}\)
\(Vậyx=\frac{13}{70}\)


 

19 tháng 5 2021

1. \(\dfrac{2019}{2020}-\left(\dfrac{2019}{2020}-\dfrac{2020}{2021}\right)\)

\(=\dfrac{2019}{2020}-\dfrac{2019}{2020}+\dfrac{2020}{2021}\)

\(=0+\dfrac{2020}{2021}=\dfrac{2020}{2021}\)

Giải:

1) \(\dfrac{2019}{2020}-\left(\dfrac{2019}{2020}-\dfrac{2020}{2021}\right)\)  

\(=\dfrac{2019}{2020}-\dfrac{2019}{2020}+\dfrac{2020}{2021}\) 

\(=\left(\dfrac{2019}{2020}-\dfrac{2019}{2020}\right)+\dfrac{2020}{2021}\) 

\(=0+\dfrac{2020}{2021}\) 

\(=\dfrac{2020}{2021}\) 

2) \(\dfrac{2}{9}+\dfrac{7}{9}:\left(\dfrac{42}{5}-\dfrac{7}{5}\right)\) 

\(=\dfrac{2}{9}+\dfrac{7}{9}:7\) 

\(=\dfrac{2}{9}+\dfrac{1}{9}\) 

\(=\dfrac{1}{3}\) 

3) \(\dfrac{3}{4}+\dfrac{x}{4}=\dfrac{5}{8}\) 

            \(\dfrac{x}{4}=\dfrac{5}{8}-\dfrac{3}{4}\) 

            \(\dfrac{x}{4}=\dfrac{-1}{8}\)  

\(\Rightarrow x=\dfrac{4.-1}{8}=\dfrac{-1}{2}\) 

4) \(\left|3x+1\right|-\dfrac{1}{4}=\dfrac{-1}{4}\) 

            \(\left|3x-1\right|=\dfrac{-1}{4}+\dfrac{1}{4}\) 

            \(\left|3x-1\right|=0\) 

             \(3x-1=0\) 

                    \(3x=0+1\) 

                    \(3x=1\) 

                      \(x=1:3\) 

                      \(x=\dfrac{1}{3}\) 

Chúc bạn học tốt!

6 tháng 7 2016

a)      43+(9-21)=317-(x+317)

     ->43+(-12)=317-(x+317)

    ->    31      =317-(x+317) 

     ->  317-(x+317)=31

     ->          x+317 =317-31=286

      ->        x          = 286 - 317

      ->        x          =  -31

Ung ho minh nha

6 tháng 7 2016

a)có người làm rồi

b)(15-x)+(x-12)=7-(-5+x)

=>15-x+x-12=7-(-5)-x

=>(-x+x)+15-12=12-x

=>3=12-x

=>-9=-x

=>x=9

c)đề sai x0 là sao

d)|x|+|y|=1

  • \(\hept{\begin{cases}-1< y\le0\\y=-1-x\end{cases}\Rightarrow}\hept{\begin{cases}0\le y< 1\\y=x-1\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=\pm1\\y=0\end{cases}}\).Vì x đạt GTTĐ

  • \(\hept{\begin{cases}-1< x\le0\\y=x+1\end{cases}}\Rightarrow\hept{\begin{cases}0\le x< 1\\y=1-x\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0\\y=\pm1\end{cases}}\).Vì y đạt GTTĐ

e)(x+1) +(x+3)+(x+5)+...+(x+99)=0

=>(x+x+...+x)+(1+3+...+99)=0

=>50x+2500=0

=>50x=-2500

=>x=-50

7 tháng 4 2019

\(-\frac{3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2.\frac{3}{7}\)\(=\frac{3}{7}\left(-\frac{5}{9}-\frac{4}{9}+2\right)=\frac{3}{7}\left(-1+2\right)=\frac{3}{7}\)

so sánh: \(\frac{21}{-42}=\frac{1}{-2}=\frac{2}{-4}\); vì \(\frac{2}{-4}>\frac{3}{-4}\)nên \(\frac{21}{-42}>\frac{3}{-4}\)

tìm x: a) \(x-\frac{2}{5}=\frac{1}{10}\)

             \(\Rightarrow x=\frac{1}{10}+\frac{2}{5}=\frac{1}{10}+\frac{4}{10}=\frac{5}{10}=\frac{1}{2}\)

b) \(\frac{4}{6}+\frac{5}{4}x=\frac{7}{6}\)

\(\Rightarrow\frac{5}{4}x=\frac{3}{6}=\frac{1}{2}\)

\(\Rightarrow x=\frac{2}{5}\)

tìm x biết:

1/3+2/5.(x-1) = 4

=> 2/5.(x-1) = 4 - 1/3 = 11/3

=> x-1 = 11/3 : 2/5 = 55/6

=> x= 55/6 + 1 = 61/6

1/2-1/3:3x0 = -5 

?????? đề hay thật