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1, <=>33+x=45
<=> x = 12
Vậy x=12
2, <=>x+73 =102
<=> x =29
3,x=2
4, -23+x=25<=>x=2
6, x-8=20<=>x=28
a) (x - 140) : 7 = 33 - 23 . 3
(x - 140) : 7 = 27 - 8 . 3 = 27 - 24 = 3
x - 140 = 3 x 7 = 21
x = 21 + 140 = 161
b) x3 . x2 = 28 : 23
x5 = 25
=> x = 2
c) (x + 2) . ( x - 4) = 0
x = -2 hoặc 4
d) 3x-3 - 32 = 2 . 32 =
3x-3 - 9 = 2 . 9 = 18
3x-3 = 18 + 9 = 27
3x-3 = 33
=> x - 3 = 3
x = 3 + 3 = 6
a) \(\Leftrightarrow-x+38=26\)
\(\Leftrightarrow x=12\)
b)\(\Leftrightarrow x+47=76\)
\(\Leftrightarrow x=29\)
c)\(\Leftrightarrow-x+36=6\)
\(\Leftrightarrow x=30\)
d)\(\Leftrightarrow x+16=20\)
\(\Leftrightarrow x=4\)
e)\(x-18=13\)
\(\Leftrightarrow x=31\)
f)\(-x+194=120\)
\(\Leftrightarrow x=74\)
g)\(\Leftrightarrow x-8=20\)
\(\Leftrightarrow x=28\)
h)\(\Leftrightarrow4x+84=400\)
\(\Leftrightarrow x=79\)
a) 71-(33+x)=26
33+x=71-26
33+x=45
x=45-33
x=12
Vậy x=12
b) ( x+73)-26=76
x+73=76+26
x+73=102
x=102-73
x=29
Vậy x=29
c)45-(x+9)=6
x+9=45-6
x+9=39
x=39-9
x=30
Vậy x=30
d) 89-(73-x)=20
73-x=89-20
73-x=69
x=73-69
x=4
Vậy x=4
e) ( x+7)-25=13
x+7=13+25
x+7=38
x=38-7
x=31
Vậy x=31
f)198-(x+4)=120
x+4=198-120
x+4=78
x=78-4
x=74
Vậy x=74
g)140:(x-8)=7
x-8=140:7
x-8=20
x=20+8
x=28
Vậy x=28
h) 4(x+41)=400
x+41=400:4
x+41=100
x=100-41
x=59
Vậy x=59
2x2 - (-6) = 23.3
2x2 + 6 = 8.3
2x2 + 6 = 24
2x2 = 24 - 6
2x2 = 18
x2 = 18 : 2
x2 = 9
x2 = 32
⇒ x = 3
a, 71 - ( 33 + x ) = 26
=> 33 + x = 71 - 26
=> 33 + x = 45
=> x = 45 - 33
=> x = 12
b, 140 : ( x - 8 ) = 7
=> x - 8 = 140 : 7
=> x - 8 = 20
=> x = 20 + 8
=> x = 28
c, 4 ( x + 41 ) = 22 . 102
=> 22 ( x + 41 ) = 202
=> x + 41 = 202 : 22
=> x + 41 = 102
=> x + 41 = 100
=> x = 100 - 41
=> x = 59
d, 11 ( x - 9 ) = 77
=> x - 9 = 77: 11
=> x - 9 = 7
=> x = 7 + 9
=> x 16
\(a.71-\left(33+x\right)=26\)
\(33+x=45\)
\(x=12\)
\(b.140:\left(x-8\right)=7\)
\(x-8=20\)
\(x=28\)
\(c.4\left(x+41\right)=2^2.10^2\)
\(4\left(x+41\right)=4.100\)
\(4\left(x+41\right)=400\)
\(x+41=100\)
\(x=59\)
\(d.11\left(x-9\right)=77\)
\(x-9=7\)
\(x=16\)
\(\Rightarrow2\cdot3^x=23\cdot3^{12}+31\cdot3^{12}=3^{12}\cdot54=2\cdot3^3\cdot3^{12}=2\cdot3^{15}\\ \Rightarrow x=15\)
\(\left(x-140\right):7=33-23.3\\ \left(x-140\right):7=33-69\\ \left(x-140\right):7=-36\\ x-140=-36.7\\ x-140=-252\\ x=-252+140\\ x=-112\)
\(\left(x-140\right):7=33-23.3\)
\(\left(x-140\right):7=33-69\)
\((x-140):7=-36\)
\(x-140=-252\)
\(x=-112\)