Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có:
\(A=3+3^2+3^3+...+3^{10}\)
\(\Rightarrow3A=3^2+3^3+3^4+...+3^{11}\)
\(\Rightarrow3A-A=\left(3^2+3^3+3^4+...+3^{11}\right)-\left(3+3^2+3^3+...+3^{10}\right)\)
\(\Rightarrow2A=3^{11}-3\)
\(\Rightarrow2A+3=3^{11}-3+3\)
\(\Rightarrow2A+3=3^{11}\)
Vậy \(2A+3=3^{11}\)
27 . 29 . 32
= 27+9 . 9
= 216 . 9
= 65536 .9
= 589824
Học tốt!!
1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)
b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)
c) \(10^8\div10^3=10^{8-3}=10^5\)
d) \(a^7\div a^2=a^{7-2}=a^5\)
2.
\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)
\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)
\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)
\(2^7\cdot2^9\cdot3^2=2^{7+9}\cdot3^2=2^{16}\cdot3^2\)
chỉ bt chừng đó thôi 😅
27.29.32 = 27+9.9 = 216.9 = 65536.9 = 589824