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a, ta có :
\(\hept{\begin{cases}\frac{6}{7}< 1\\\frac{11}{10}>1\end{cases}}\Rightarrow\frac{6}{7}< \frac{11}{10}\)
b, ta có :
\(\hept{\begin{cases}\frac{-5}{7}< 0\\\frac{2}{7}>0\end{cases}}\Rightarrow\frac{-5}{7}>\frac{2}{7}\)
c, ta có :
\(\hept{\begin{cases}\frac{419}{-723}< 0\\\frac{-697}{-313}>0\end{cases}}\Rightarrow\frac{419}{-723}< \frac{-679}{-313}\)
a,Ta có:
6/7< 1< 11/10
=> 6/7< 11/10
b,Ta có:
-5/17< 0< 2/7
=> -5/7< 2/7
1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)
b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)
c) \(10^8\div10^3=10^{8-3}=10^5\)
d) \(a^7\div a^2=a^{7-2}=a^5\)
2.
\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)
\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)
\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)
a) \(7^{15}\)
b)\(162^8\). 2
c)\(10^8\)
d) \(a^0\)
Xin lỗi nha mk hơi vội nên có sai thì bạn châm trc cho mk nha.
a. \(\frac{6}{7}=\frac{60}{70};\frac{11}{10}=\frac{77}{70}\)
\(\frac{77}{70}>\frac{60}{70}\rightarrow\frac{11}{10}>\frac{6}{7}\)
b. \(\frac{-5}{17}< 0;\frac{2}{7}>0\rightarrow\frac{2}{7}>\frac{-5}{17}\)
c. \(\frac{419}{-723}< 0;\frac{-697}{-313}=\frac{697}{313}>0\Rightarrow\frac{-697}{-313}>\frac{419}{-723}\)
a)Ta có : 6/7 < 1
11/10 >1
Suy ra : 6/7 < 11/10
B) -5/17 < 0 và 2/7 >0
Suy ra -5/17 < 2/7
c) câu c mk ko bt xl bn nha
1. a, \(\frac{6}{7}\)=\(\frac{60}{70}\);\(\frac{11}{10}\)=\(\frac{77}{70}\)
vì \(\frac{60}{70}\)<\(\frac{77}{70}\)nên \(\frac{6}{7}\)<\(\frac{11}{10}\)
b, \(\frac{-5}{17}\)<0<\(\frac{2}{7}\)
c, \(\frac{419}{-723}\)<0<\(\frac{-697}{-313}\)
2.
Ta có :\(\frac{2}{6}\)=\(\frac{20}{60}\);\(\frac{5}{12}\)=\(\frac{25}{60}\);\(\frac{4}{15}\)=\(\frac{16}{60}\);\(\frac{8}{20}\)=\(\frac{24}{60}\);\(\frac{10}{30}\)=\(\frac{20}{60}\)
Vì \(\frac{16}{60}\)<\(\frac{20}{60}\)<\(\frac{24}{60}\)<\(\frac{25}{60}\)nên \(\frac{4}{15}\)<\(\frac{2}{6}\)=\(\frac{10}{30}\)<\(\frac{8}{20}\)<\(\frac{5}{12}\)
Câu 1:
a)\(2^3.2^2.2^4=2^{\left(3+2+4\right)}=2^9\)
b)\(10^2.10^3.10^5=10^{\left(2+3+5\right)}=10^{10}\)
c)\(x.x^5=x^6\)
d)\(a^3.a^2.a^5=a^{\left(2+3+5\right)}=a^{10}\)
Đáp án: A
723 = 700 +20+3
= 7. 10 2 +2.10+3. . 10 0
đáp án A nha hok tốt