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a, Đề sai bạn ơi phải là cộng 16 chứ không phải cộng 4
b,B= (x-2y+1)^2
\(1,\)\(4x^2-4x+y^2+2y+2\)
\(=4x^2+4x+1+y^2+2y+1\)
\(=\left[\left(2x\right)^2-2.2x+1\right]+\left(y^2+2.y.1+1^2\right)\)
\(=\left(2x-1\right)^2+\left(y+1\right)^2\)
\(2,\)\(a^2-4ab+5b^2-4bc+4c^2\)
\(=a^2-4ab+4b^2+b^2-4bc+4c^2\)
\(=\left[a^2-2.a.2b+\left(2b\right)^2\right]+\left[b^2-2.b.2c+\left(2c\right)^2\right]\)
\(=\left(a-2b\right)^2+\left(b-2c\right)^2\)
\(3,\)\(16x^2+5+8x-4y+y^2\)
\(=16x^2+8x+1+y^2-4y+4\)
\(=\left[\left(4x\right)^2+2.4x.1+1^2\right]+\left[y^2-2.y.2+2^2\right]\)
\(=\left(4x+1\right)^2+\left(y-2\right)^2\)
a) t2 - 8t + x2 - 4x + 20 = ( t2 - 8t + 16 ) + ( x2 - 4x + 4 ) = ( t - 4 )2 + ( x - 2 )2
b) 49t2 + y2 - 10y + 14t + 26 = ( 49t2 + 14t + 1 ) + ( y2 - 10y + 25 ) = ( 7t + 1 )2 + ( y - 5 )2
c) 2x2 + 4y2 - 2x + 4xy + 1 = ( x2 - 2x + 1 ) + ( x2 + 4xy + 4y2 ) = ( x - 1 )2 + ( x + 2y )2 ( thay 2 thành 1 vì 2 khó làm lắm:v )
Câu 1:
a, (x-1).(x2-x+1)
b, (2a+b).(2a-b)
Câu 2:
a,(2x-1).(x2-5x+3)
b,(-x2+4x-1).(-x+4)
c,(-2x-3).(x+4)+(-x+1)
d,(-3).(x+4).(x-7)+2.(x-5).(x+1)
Câu 3:
a,5x2-(2x+1).(x-2)-x.(3x+3)+7
b,(5x-2).(x+1)-(x-3).5x+1-17.(x-2)
Giup mình với
Mình gửi kiểu kia ko được
a. x2 + 6x + 9 = (x + 3)2
b. 25 + 10x + x2 = (5 + x)2
c. x2 + 8x + 16 = (x + 4)2
d. x2 + 14x + 49 = (x + 7)2
e. 4x2 + 12x + 9 = (2x + 3)2
f. 9x2 + 12x + 4 = (3x + 2)2
h. 16x2 + 8 + 1 = (4x + 1)2
i. 4x2 + 12xy + 9y2 = (2x + 3y)2
k. 25x2 + 20xy + 4y2 = (5x + 2y)2
a) \(=\left(x+3\right)^2\)
b) \(=\left(x+5\right)^2\)
c) \(=\left(x+4\right)^2\)
d) \(=\left(x+7\right)^2\)
e) \(=\left(2x+3\right)^2\)
f) \(=\left(3x+2\right)^2\)
h) \(=\left(4x+1\right)^2\)
i) \(=\left(2x+3y\right)^2\)
k) \(=\left(5x+2y\right)^2\)
a) \(x^2-4x+5+y^2+2y=\left(x^2-4x+4\right)+\left(y^2+2y+1\right)\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
b) \(2x^2+y^2-2xy+10x+25=\left(x^2+10x+25\right)+\left(x^2-2xy+y^2\right)\)
\(=\left(x+5\right)^2+\left(x-y\right)^2\)
c) \(2x^2+2y^2=\left(x^2-2xy+y^2\right)+\left(x^2+2xy+y^2\right)=\left(x-y\right)^2+\left(x+y\right)^2\)
\(A=x^2-10x+y^2-6y+34\)
\(=\left(x^2-10x+25\right)+\left(y^2-6y+9\right)\)
\(=\left(x-5\right)^2+\left(y-3\right)^2\)
\(B=x^2-6x+y^2+4y+13\)
\(=\left(x^2-6x+9\right)+\left(y^2+4y+4\right)\)
\(=\left(x-3\right)^2+\left(y+2\right)^2\)
\(C=x^2-2xy+\left(2y\right)^2+2y+1\)
\(=\left(x^2-2xy+y^2\right)+\left(y^2+2y+1\right)\)
\(=\left(x-y\right)^2+\left(y+1\right)^2\)
a/ \(=\left(9x^2+30x+25\right)+\left(x^2+10x+25\right)=\)
\(=\left(3x+5\right)^2+\left(x+5\right)^2\)
b/ \(=\left(16x^2+8x+1\right)+\left(y^2-4y+4\right)=\left(4x+1\right)^2+\left(y-2\right)^2\)
c/