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Câu 2:
#include <bits/stdc++.h>
using namespace std;
double p1,p2;
int i,n;
int main()
{
cin>>n;
p1=1;
p2=1;
for (i=1; i<=n; i++)
{
if (i%2==0) p2=p2*(i*1.0);
else p1=p1*(i*1.0);
}
cout<<fixed<<setprecision(2)<<p1<<endl;
cout<<fixed<<setprecision(2)<<p2;
return 0;
}
a)
program Tinh_S;
var
n, S: integer;
i: integer;
begin
write('Nhap gia tri cua n (30 <= n <= 90): ');
readln(n);
S := 0;
if (n >= 30) and (n <= 90) then
begin
for i := 1 to n do
S := S + i;
writeln('Gia tri cua bieu thuc S la: ', S);
end
else
writeln('Gia tri cua n khong hop le!');
readln;
end.
b)
program Tim_n;
var
n, S: integer;
begin
for n := 30 to 90 do
begin
S := 0;
for i := 1 to n do
S := S + i;
if S > 1000 then
begin
writeln('Gia tri cua n la: ', n);
break;
end;
end;
readln;
end.
a)program Tinh_S;
var n,s,i:longint;
begin
s := 0;
write('Nhap n (30 <= n <= 90): ');
readln(n);
for i := 1 to n do
begin
s := s + i;
end;
writeln('Tong S la: ', s);
end.
b) program Tim_N;
var n,s,i: longint;
begin
s := 0;
n := 1;
while s <= 1000 do
begin
s := s + n;
n := n + 1;
end;
writeln('Gia tri n can tim la: ', n-1);
end.
#include <bits/stdc++.h>
using namespace std;
int n,i;
double s;
int main()
{
cin>>n;
s=1;
for (i=2; i<=n; i++)
{
if (i%2==0) s=s+1/(i*1.0);
else s=s-1/(i*1.0);
}
cout<<fixed<<setprecison(2)<<s;
return 0;
}
uses crt;
var i,n,s:integer;
begin
clrscr;
readln(n);
s:=0;
for i:=1 to n do
s:=s+i*i;
writeln(s);
readln;
end.
Câu 6:
uses crt;
var n,i:integer;
begin
clrscr;
readln(n);
for i:=1 to n do
if n mod i=0 then write(i:4);
readln;
end.
5:
uses crt;
var n,i,dem:integer;
begin
clrscr;
readln(n);
dem:=0;
for i:=0 to n do
if i mod 2=1 then
begin
write(i:4);
dem:=dem+1;
end;
writeln;
writeln(dem);
readln;
end.
#include <bits/stdc++.h>
using namespace std;
long long i,t;
int main()
{
t=0;
for (i=1; i<=20; i++) t=t+i;
cout<<2*t;
return 0;
}
Var i,p:integer;
Begin
i:=0;
p:=1;
While p<=120 do
Begin
i:=i+1;
p:=p*i;
End;
Write('So can tim la ',i);
Readln;
End.
#include <bits/stdc++.h>
using namespace std;
long long i,n;
double p;
int main()
{
cin>>n;
p=0;
for (i=1; i<=n; i++)
p=p+1/(i*1.0);
cout<<p+3*n;
return 0;
}