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a) \(\frac{2}{3} = \frac{4}{6} = \frac{1}{6} + \frac{3}{6} = \frac{1}{6} + \frac{1}{2}\)
b) \(\frac{8}{{15}} = \frac{5}{{15}} + \frac{3}{{15}} = \frac{1}{5} + \frac{1}{3}\)
c) \(\frac{7}{8} = \frac{4}{8} + \frac{2}{8} + \frac{1}{8} = \frac{1}{2} + \frac{1}{4} + \frac{1}{8}\)
d) \(\frac{{17}}{{18}} = \frac{9}{{18}} + \frac{6}{{18}} + \frac{2}{{18}} = \frac{1}{2} + \frac{1}{3} + \frac{1}{9}\).
\(\frac{1}{5}=\frac{1.3}{5.3}=\frac{3}{15}\)
\(\frac{-10}{55}=\frac{-10\div5}{55\div5}=\frac{-2}{11}\)
Vậy ba cặp số phân số bằng nhau sau khi sử dụng tính chất cơ bản
2 .
\(\frac{-12}{-3}=\frac{-12:3}{-3:3}=\frac{-4}{-1};\frac{7}{-35}=\frac{7:7}{-35:7}=\frac{1}{-5};\frac{-9}{27}=\frac{-9:9}{27:9}=\frac{-1}{3}\)
3 .
\(15min=\frac{1}{4}\)giờ
\(90min=\frac{3}{2}\)giờ
\(\frac{1}{3}=\frac{1x8}{3x8}=\frac{8}{24}\)
\(\frac{-2}{3}=\frac{\left(-2\right)x8}{3x8}=\frac{-16}{24}\)
\(\frac{-3}{9}=\frac{-1}{3}=\frac{\left(-1\right)x8}{3x8}=\frac{-8}{24}\)
\(\frac{-4}{-12}=\frac{1}{3}=\frac{1x8}{3x8}=\frac{8}{24}\)
1/3=8/24
-2/3=-16/24
-3/9=-1/3=-8/24
-4/-12=4/12=8/24
chúc ban hoc tốt
a)
i.Ta có: BCNN(12, 30) = 60
60 : 12 = 5; 60 : 30 = 2. Do đó:
\(\frac{5}{{12}} = \frac{{5.5}}{{12.5}} = \frac{{25}}{{60}}\) và \(\frac{7}{{30}} = \frac{{7.2}}{{30.2}} = \frac{{14}}{{60}}.\)
ii.Ta có: BCNN(2, 5, 8) = 40
40 : 2 = 20; 40 : 5 = 8; 40 : 8 = 5. Do đó:
\(\frac{1}{2} = \frac{{1.20}}{{2.20}} = \frac{{20}}{{40}}\)
\(\frac{3}{5} = \frac{{3.8}}{{5.8}} = \frac{{24}}{{40}}\)
\(\frac{5}{8} = \frac{{5.5}}{{8.5}} = \frac{{25}}{{40}}\).
b)
i.Ta có: BCNN(6, 8) = 24
24 : 6 = 4; 24: 8 = 3. Do đó
\(\begin{array}{l}\frac{1}{6} + \frac{5}{8} = \frac{{1.4}}{{6.4}} + \frac{{5.3}}{{8.3}}\\ = \frac{4}{{24}} + \frac{{15}}{{24}} = \frac{{19}}{{24}}.\end{array}\)
ii. Ta có: BCNN(24, 30) = 120
120: 24 = 5; 120: 30 = 4. Do đó:
\(\begin{array}{l}\frac{{11}}{{24}} - \frac{7}{{30}} = \frac{{11.5}}{{24.5}} - \frac{{7.4}}{{30.4}}\\ = \frac{{55}}{{120}} - \frac{{28}}{{120}} = \frac{{27}}{{120}} = \frac{9}{{40}}\end{array}\)
Ta có: \(\frac{1}{{ - 2}} = \frac{{1.( - 1)}}{{ - 2.( - 1)}} = \frac{{ - 1}}{2}\)
\(\frac{{ - 3}}{{ - 5}} = \frac{{ - 3.( - 1)}}{{ - 5.( - 1)}} = \frac{3}{5}\)
\(\frac{2}{{ - 7}} = \frac{{2.( - 1)}}{{ - 7.( - 1)}} = \frac{{ - 2}}{7}\).
\(\dfrac{1}{-2}=\dfrac{-1}{2}\)
\(\dfrac{-3}{-5}=\dfrac{3}{5}\)
\(\dfrac{2}{-7}=\dfrac{-2}{7}\)
2,
\(\frac{1}{2}.1+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+...+\frac{1}{999}.\frac{1}{1000}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}....+\frac{1}{999}-\frac{1}{1000}\)
\(=1-\frac{1}{1000}\)
\(=\frac{999}{1000}\)
\(\frac{-3}{24};\frac{-16}{24};\frac{12}{24};\frac{-1}{24};\frac{-20}{24}\)