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\(\left(m-n\right)^6-6\left(m-n\right)^4+12\left(m-n\right)^2-8=\left[\left(m-n\right)^2-2\right]^3\)
\(\dfrac{8}{27}a^3-\dfrac{8}{3}a^2b+8b^2a-8b^3=\left(\dfrac{2}{3}a-2b\right)^3\)
Chúc bạn học tốt !!
a,16x2-9
=42x2-32
=(4x-3)(4x+3) HĐT thứ 3
b,9a2-25b2
=32a2-52b2
=(3a-5b)(3a+5b) HĐT thứ 3
c,81-y4
=32.32-y2.y2
=(32-y2)
=(3-y)(3+y) HĐT thứ 3
d,(2x+y)2-1
=(2x+y-1)(2x+y-1) HĐT thứ 3
e,(x+y+z)2-(x-y-z)2
cái này là HĐT thứ 8 mở rộng bạn lên mạng tìm nha
a) \(16x^2-9=\left(4x\right)^2-3^2=\left(4x-3\right).\left(4x+3\right)\)
b) \(9a^2-25b^4=\left(3a\right)^2-\left(5b^2\right)^2=\left(3a-5b^2\right).\left(3a+5b^2\right)\)
c) \(81-y^4=9^2-\left(y^2\right)^2=\left(9-y^2\right).\left(9+y^2\right)\)
d)\(\left(2x+y\right)^2-1=\left(2x+y\right)^2-1^2=\left(2x+y-1\right).\left(2x+y+1\right)\)
Bài làm:
a) Sửa đề: \(4x^2-y^2\)
\(=\left(2x\right)^2-y^2\)
\(=\left(2x-y\right)\left(2x+y\right)\)
b) \(a^2+2ab+b^2\)
\(=\left(a+b\right)^2\)
c) \(x^2-2xy+y^2\)
\(=\left(x-y\right)^2\)
d) \(x^2+4xy+4y^2=\left(x+2y\right)^2\)
b) \(a^2+2ab+b^2=\left(a+b\right)^2.\)
c) \(x^2-2xy+y^2=\left(x-y\right)^2.\)
d) \(x^2+4xy+4y=\left(x+2y\right)^2\)
câu a chịu
a/ \(\left(z^3\right)^3-\left(3t^4\right)^3=\left(z^3-3t^4\right)\left(z^6+3z^3t^4+9t^8\right)\)
b/ \(\left(\frac{x}{2}\right)^3-\left(3y^2\right)^3=\left(\frac{x}{2}-3y^2\right)\left(\frac{x^2}{4}+\frac{3}{2}xy^2+9y^4\right)\)
a, b, c, dung hang dang thuc A2-B2 =9A-B) (A+B)
d) a4 - 16 =(a2)2 -42= (a2-4) (a2+4) =(a-2)(a+2) (a2+4)
\(a..9-4x^2=3^2-\left(2x\right)^2=\left(3-2x\right)\left(3+2x\right)\)
\(b..16x^2-25=\left(4x\right)^2-5^2=\left(4x-5\right)\left(4x+5\right)\)
\(c..a^4-16=\left(a^2\right)^2-4^2=\left(a^2-4\right)\left(a^2+4\right)\)
\(d..\left(a+b\right)^2-1=\left(a+b\right)^2-1^2=\left(a+b-1\right)\left(a+b+1\right)\)
k mik đi
a) \(m^2-n^2=\left(m-n\right)\left(m+n\right)\)
b) \(\frac{1}{4}-x^2=\left(\frac{1}{2}-x\right)\left(\frac{1}{2}+x\right)\)
c) \(x^2-6x+9=\left(x-3\right)^2\)
d) \(x^2+10x+25=\left(x+5\right)^2\)
m2 - n2 = ( m - n )( m + n )
1/4 - x2 = ( 1/2 )2 - x2 = ( 1/2 - x )( 1/2 + x )
x2 - 6x + 9 = x2 - 2.3.x + 32 = ( x - 3 )2
x2 + 10x + 25 = x2 + 2.5.x + 52 = ( x + 5 )2
\(a,27-x^3\)
\(=3^3-x^3\)
\(=\left(3-x\right)\left(9+3x+x^2\right)\)
Các câu còn lại lm tương tự nhé.
hok tốt!
a) \(27-x^3=\left(3-x\right)\left(9+3x+x^2\right)\)
b) \(8x^3+0,001=\left(2x+0,1\right)\left(4x^2-0,2x+0,01\right)\)
c) \(\frac{x^3}{125}-\frac{y^3}{27}=\left(\frac{x}{5}-\frac{y}{3}\right)\left(\frac{x^2}{25}+\frac{xy}{15}+\frac{y^2}{9}\right)\)
p/s: chúc bạn học tốt
Bài 1:
a) -16 +(x-3)2
<=> (x-3)2-16
<=> (x-3)2 -42
<=> (x-3-4)(x-3+4)
<=> (x-7)(x+1)
b) 64+16y+y2
<=> y2 + 2.8.y + 82
<=> (y+8)2
c) \(\dfrac{1}{8}-8x^3\)
\(\Leftrightarrow\left(\dfrac{1}{2}\right)^3-\left(2x\right)^3\)
\(\Leftrightarrow\left(\dfrac{1}{2}-2x\right)\left(\dfrac{1}{4}+x+4x^2\right)\)
d)\(x^2-x+\dfrac{1}{4}\)
\(\Leftrightarrow x^2-2.\dfrac{1}{2}.x+\left(\dfrac{1}{2}\right)^2\)
\(\Leftrightarrow\left(x-\dfrac{1}{2}\right)^2\)
e) x4 + 4x2 + 4
<=> (x2)2 + 2.2.x2 +22
<=> (x2 + 2)2
g)\(8x^3+60x^2y+150xy^2+125y^3\)
\(\Leftrightarrow\left(2x+5y\right)^3\)
a) \(m^2-n^2=\left(m-n\right)\left(m+n\right)\)
b) \(\left(x^2+x-1\right)^2-\left(x^2+2x+3\right)^2=\left(x^2+x+1+x^2+2x+3\right)\left(x^2+x+1-x^2-2x-3\right)\)
\(=-\left(2x^2+3x+4\right)\left(x+2\right)\)
d) \(64+16y+y^2=\left(8+y\right)^2\)
c) mk chỉnh đề:
\(16-\left(x-3\right)^2=\left(4+x-3\right)\left(4-x+3\right)=\left(x+1\right)\left(7-x\right)\)
a/ \(a^6+8b^3\)
\(=\left(a^2\right)^3+2^3b^3\)
\(=\left(a^2\right)^3+\left(2b\right)^3\)
\(=\left(a^2+2b\right)\left(a^4-a^22b+4b^2\right)\)
b/ \(z^9-27t^{12}\)
\(=\left(z^3\right)^3-3^3\left(t^4\right)^3\)
\(=\left(z^3\right)^3-\left(3t^4\right)^3\)
\(=\left(z^3-3t^4\right)\left(z^6+z^33t^4+9t^8\right)\)
ARMY