Question

[le trung hieu]

trung hoà 50gam dd hcl 14,6% cần bao nhiêu ml dd koh 0,5M?

Answer 1

[Lê Ng Hải Anh]

Ta có: \(m_{HCl}=50.14,6\%=7,3\left(g\right)\)

\(\Rightarrow n_{HCl}=\dfrac{7,3}{36,5}=0,2\left(mol\right)\)

PT: \(HCl+KOH\rightarrow KCl+H_2O\)

Theo PT: \(n_{KOH}=n_{HCl}=0,2\left(mol\right)\)

\(\Rightarrow V_{ddKOH}=\dfrac{0,2}{0,5}=0,4\left(l\right)=400\left(ml\right)\)

Answer 2

[HT.Phong (9A5)]

KOH + HCl → KCl + H₂O

\(0,146\)   \(0,146\)   \(0,146\)

\(V_{KOH}=\dfrac{n}{CM}=\dfrac{0,146}{0,5}=0,292\left(l\right)=292\left(ml\right)\)