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\(\left(6^{2007}-6^{2006}\right):6^{2006}\\ =6^{2007}:6^{2006}-6^{2006}:6^{2006}\\ =6^{2007-2006}-6^{2006-2006}\\ =6^1-6^0\\ =6-1=5\)
\(\left(9^{2018}-3^{4036}\right):6^{2006}\\ \Rightarrow\left[\left(3^2\right)^{2018}-3^{4036}\right]:6^{2006}\\ \Rightarrow\left(3^{4036}-3^{4036}\right):6^{2006}\\ \Rightarrow0:6^{2006}\\ \Rightarrow0\)
\(=\dfrac{\left(3^2\right)^{2018}-3^{4036}}{6^{2006}}=\dfrac{3^{4036}-3^{4036}}{6^{2006}}=0\)
Bài 1
a, -25 . 63 - 25 . 3
= 25 . (-63) - 25 . 3
= 25 . [(-63) - 3]
= 25 . (-66) = -1650
Bài 2
c, (x + 1)2 = 16
=> (x + 1)2 = 42
=> x + 1 = 4
=> x = 3
d, (-38) - (x - 2) = -16
=> (x - 2) = -38 - (-16)
=> x - 2 = -38 + 16 = -22
=> x = 2 + (-22)
=> x = -20
a)
\(\left(1-\dfrac{1}{5}\right)x\left(1-\dfrac{2}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x\left(1-\dfrac{5}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x0x...x\left(1-\dfrac{9}{5}\right)=0\)
x là nhân nhé :))
b)
\(\dfrac{1}{2}x\dfrac{2}{3}x...x\dfrac{9}{10}\\ =\dfrac{1x2x...x9}{2x3x...x10}=\dfrac{2x3x...x9}{2x3x...x9x10}=\dfrac{1}{10}\)
a/(-100)-12=-100+(-12)=-112
b/x=-18-(-15)=-18+15=-3
c/-14+x=10-(-15)=10+15=25
x=-14-25
x=-39
d.x-(-19)=0+(-11)=-11
x+19=-11
x=-11-19
x=-30
`x + 2 3/4 = 5 2/3`
`=> x + 11/4 = 17/3`
`=> x= 17/3 -11/4`
`=>x=35/12`
__
`x - 1 4/5 = 3 2/7`
`=> x- 9/5 = 23/7`
`=> x= 23/7 +9/5`
`=>x=178/35`
__
`x xx 3 1/2 =4 3/4`
`=> x xx 7/2 =19/4`
`=> x= 19/4 : 7/2`
`=> x= 19/4 xx 2/7`
`=> x= 19/14`
__
`x : 2 2/3 = 4 1/3`
`=> x : 8/3 = 13/3`
`=> x= 13/3 xx 8/3`
`=>x=104/9`
a: =>x+11/4=17/3
=>x=17/3-11/4=68/12-33/12=35/12
b: =>x-9/5=23/7
=>x=23/7+9/5=178/35
c: =>x*7/2=4,75
=>x=19/4:7/2=19/14
d: =>x:8/3=13/3
=>x=13/3*8/3=104/9
a) \(\dfrac{6}{7}+\dfrac{7}{8}=\dfrac{48}{56}+\dfrac{49}{56}=\dfrac{97}{56}\)
b) \(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\)
c) \(\dfrac{2}{3}.\dfrac{4}{9}=\dfrac{8}{27}\)
d) \(\dfrac{1}{5}:\dfrac{2}{7}=\dfrac{1}{5}.\dfrac{7}{2}=\dfrac{7}{10}\)
a: =48/56+49/56
=97/56
b: =12/15-10/15
=2/15
c: =(2*4)/(3*9)=8/27
d: =1/5*7/2=7/10
b: Ta có: \(1992+\left(-53\right)+158+\left(-247\right)+\left(-1592\right)\)
\(=\left(1992-1592\right)+\left(-53-247\right)+158\)
\(=400-300+158=258\)
a. (62007-62006) x 62006
=6x62006=62007