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\(\frac{\left(0,9\right)^5}{\left(0,3\right)^6}=\frac{\left(0,3^2\right)^5}{\left(0,3\right)^6}=\frac{\left(0,3\right)^6\cdot\left(0,3\right)^4}{\left(0,3\right)^6}=\left(0,3\right)^4\)
GIÚP MÌNH VỚI MN ƠIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
\(A=\dfrac{\left(20.5\right)^5.5^5}{100^5}=\dfrac{100^5.3125}{100^5}=3125\)
\(B=\dfrac{\left(0,3.3\right)^5}{\left(0,3\right)^5.0,3}=\dfrac{\left(0,3\right)^5.3^5}{\left(0,3\right)^5.0,3}=\dfrac{3^5}{0,3}=810\)
\(\frac{\left(0,9\right)^5}{\left(0,3\right)^6}=\frac{\left(3.0,3\right)^5}{\left(0,3\right)^6}=\frac{3^5.\left(0,3\right)^5}{\left(0,3\right)^6}=\frac{3^5}{0,3}=\frac{243}{0,3}=810\)
a: =7/3*5/4=35/12
b: =21/53
c:=0,4:0,3=4/3
d: =23/120
e: =3/9=1/3
f: =24/48=1/2
Sửa đề: 0,01+0,02+...+0,09+0,10+...+0,99+1
Số số hạng là (1-0,01):0,01+1=100(số)
Tổng là (1+0,01)*100/2=1,01*50=50,5
Bài làm
\(7+\left(\frac{7}{12}-\frac{1}{2}+3\right)-\left(\frac{1}{12}+5\right)\)
\(=\frac{84}{12}+\left(\frac{7}{12}-\frac{6}{12}+\frac{36}{12}\right)-\left(\frac{1}{12}+\frac{60}{12}\right)\)
\(=\frac{84}{12}+\frac{37}{12}-\frac{61}{12}\)
\(=\frac{60}{12}\)
\(=5\)
# Chúc bạn học tốt #
= \(\frac{\left(0,1.3^2\right)^5}{\left(0,1.3\right)^8}\) = \(\frac{0,1^5.3^{10}}{0,1^8.3^8}\) = \(\frac{9}{0,1^3}\)= 9000
Chúc bạn làm bài tốt
a: \(=\dfrac{5^5\cdot5^{10}\cdot4^5}{5^{10}\cdot2^{10}}=5^5\)
b: \(=\left(\dfrac{0.9}{0.3}\right)^5\cdot\dfrac{1}{0.3}=\dfrac{3^5}{0.3}=810\)
c: \(=\dfrac{2^{12}\cdot3^6+2^3\cdot3^3\cdot2^3\cdot3\cdot5}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}\)
\(=\dfrac{2^{12}\cdot3^6+2^6\cdot3^4\cdot5}{2^{11}\cdot3^{11}\cdot5}\)
\(=\dfrac{2^6\cdot3^4\left(2^6\cdot3^2+5\right)}{2^{11}\cdot3^{11}\cdot5}=\dfrac{1}{2^5}\cdot\dfrac{1}{3^7}\cdot\dfrac{581}{5}=\dfrac{581}{2^5\cdot3^7\cdot5}\)