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VQ
0
NM
26 tháng 6 2016
a) Ta có: \(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}\)
\(=\frac{2.\left(0.2-\frac{1}{7}+\frac{1}{11}\right)}{3.\left(0,2-\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{2}{3}\)
b) Ta có: \(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
\(=\frac{3.\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}\)
\(=\frac{3}{11}\)
Chuk pạn hok tốt!
NA
26 tháng 6 2016
a) \(\frac{0,4-\frac{2}{7}+\frac{2}{11}}{0,6-\frac{3}{7}+\frac{3}{11}}\\ =\frac{\frac{2}{5}-\frac{2}{7}+\frac{2}{11}}{\frac{3}{5}-\frac{3}{7}+\frac{3}{11}}\\ =\frac{2\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}{3\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{11}\right)}\\=\frac{2}{3}\)
b) \(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\\=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\\=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\\=\frac{3}{11}\)
NN
Tính:
0,4(3) + 0,6(2) . \(2\frac{1}{2}\).[(\(\frac{1}{2}+\frac{1}{3}\)) : 0,5(8)] : \(\frac{50}{53}\)
1
HT
11 tháng 12 2015
0,4(3) + 0,6(2). \(2\frac{1}{2}\).\(\left[\left(\frac{1}{2}+\frac{1}{3}\right):0,5\left(8\right)\right]:\frac{50}{53}\)
\(=\frac{13}{30}+\frac{28}{45}.\frac{5}{2}.\left[\frac{5}{6}:\frac{53}{90}\right]:\frac{50}{53}\)
\(=\frac{13}{30}+\frac{28}{45}.\frac{5}{2}.\frac{75}{53}:\frac{50}{53}\)
\(=\frac{13}{30}+\frac{7}{3}\)
\(=\frac{83}{30}\)
NT
1
11 tháng 9 2017
\(\left(\frac{2}{3}\right)^3=\frac{8}{27}\)
\(\left(-2\frac{3}{4}\right)^2=\frac{121}{16}\)
\(\left(0,6\right)^4=\frac{81}{625}\)
\(\left(-\frac{1}{2}\right)^4=\frac{1}{16}\)
\(\left(-\frac{1}{2}\right)^5=-\frac{1}{32}\)
11 tháng 9 2017
\(\left(\frac{2}{3}\right)^3=\frac{2^3}{3^3}=\frac{8}{27}\)
\(\left(-2\frac{3}{4}\right)^2=\left(-\frac{11}{4}\right)^2=\frac{121}{16}\)
\(\left(0,6\right)^4=0,1296\)
\(\left(-\frac{1}{2}\right)^4=\frac{1}{16}\)
\(\left(-\frac{1}{2}\right)^5=\frac{1}{32}\)
18 tháng 12 2016
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
K
2 tháng 7 2015
a) \(\left|1,5x\right|-\left|0,6\right|=\left(-2\right)+\left|0,4\right|\)
\(\left|1,5x\right|-0,6=\left(-2\right)+0,4\)
\(\left|1,5x\right|-0,6=-1,6\)
\(\left|1,5x\right|=-1,6+0,6\)
\(\left|1,5x\right|=-1\)
\(\Rightarrow\) x không tồn tại
b) \(\left|3x+1\right|=2-\left|-\frac{4}{5}\right|\)
\(\left|3x+1\right|=2-\frac{4}{5}\)
\(\left|3x+1\right|=\frac{6}{5}\)
\(\Rightarrow3x+1\in\left\{\frac{6}{5};-\frac{6}{5}\right\}\)
\(\Rightarrow3x\in\left\{\frac{1}{5};\frac{-11}{5}\right\}\)
\(\Rightarrow x\in\left\{\frac{1}{15};\frac{-11}{15}\right\}\)
c)\(\left|1-2x\right|+4=\left|-10\frac{1}{2}\right|-\frac{1}{2}\)
\(\left|1-2x\right|+4=10\frac{1}{2}-\frac{1}{2}\)
\(\left|1-2x\right|+4=10\)
\(\left|1-2x\right|=10-4\)
\(\left|1-2x\right|=6\)
\(\Rightarrow1-2x\in\left\{6;-6\right\}\)
\(\Rightarrow2x\in\left\{-5;7\right\}\)
\(\Rightarrow2x\in\left\{-\frac{5}{2};\frac{7}{2}\right\}\)
d)\(\left|x+\frac{7}{3}\right|-\left|\frac{1}{3}\right|=0\)
\(\left|x+\frac{7}{3}\right|-\frac{1}{3}=0\)
\(\Rightarrow\left|x+\frac{7}{3}\right|=\frac{1}{3}\)
\(\Rightarrow x+\frac{7}{3}\in\left\{\frac{1}{3};\frac{-1}{3}\right\}\)
\(\Rightarrow x\in\left\{-2;\frac{-8}{3}\right\}\)
2 tháng 7 2015
|1,5x|-|0,6|=(-2)+|0,4|
|1,5x|-0=(-2)+0,4
|1,5x|=-2+(0,4+0,6)
|1,5x|=-2+1=-1
mà GTTT của 1 số luôn luôn là số nguyên dương =>x\(\in\phi\)
b)|3x+1|=2-|4/5|
|3x+1|=2-4/5
|3x+1|=6/5
=>3x+1=6/5 hay 3x+1=-6/5
3x=6/5-1 hay 3x=-6/5-1
3x=1/5 hay 3x=-11/5
x=1/5:3 hay x=-11/5:3
x=1/15 hay x=-11/15
c)|1-2x|+4=|-10/1/2|-1/2
|1-2x|=-21/2-1/2-4
|1-2x|=-15
=>1-2x=15 hay 1-2x=-15
2x=1-15 hay 2x=1-(-15)
2x=-14 hay 2x=16
x=14/2 hay x=16/2
x=7 hay x=8
d)|x+7/3|-|1/3|=0
|x+7/3|-1/3=0
|x+7/3|=0+1/3
|x+7/3|=1/3
=>x+7/3=1/3 hay x+7/3=-1/3
x=1/3-7/3 hay x=-1/3-7/3
x=-6/3=-2 hay x=-8/3