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a) \(\dfrac{-5}{11}+\left(\dfrac{-6}{11}+1\right)\)
\(=\dfrac{-5}{11}+\left(\dfrac{-6}{11}+\dfrac{11}{11}\right)\)
\(=\dfrac{-5}{11}+\dfrac{5}{11}\)
\(=0\)
b) \(\dfrac{2}{3}+\left(\dfrac{5}{7}+\dfrac{-2}{3}\right)\)
\(=\dfrac{2}{3}+\dfrac{-2}{3}+\dfrac{5}{7}\)
\(=0+\dfrac{5}{7}\)
\(=\dfrac{5}{7}\)
c) \(\left(\dfrac{-1}{4}+\dfrac{5}{8}\right)+\dfrac{-3}{8}\)
\(=\dfrac{-1}{4}+\dfrac{-3}{8}+\dfrac{5}{8}\)
\(=\dfrac{-2}{8}+\dfrac{-3}{8}+\dfrac{5}{8}\)
\(=0\)
d) \(\dfrac{3}{4}.\dfrac{7}{25}+\dfrac{3}{4}.\dfrac{18}{25}\)
\(=\dfrac{3}{4}.\left(\dfrac{7}{25}+\dfrac{18}{25}\right)\)
\(=\dfrac{3}{4}.1\)
\(=\dfrac{3}{4}\)
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(E=\frac{45^2.20^4.18^2}{180^3}\)
=> \(E=\frac{\left(3^2.5\right)^2.\left(2^2.5\right)^4.\left(3^2.2\right)^2}{\left(2^2.3^2.5\right)^3}\)
=> E = \(\frac{3^4.5^2.2^8.5^4.3^4.2^2}{2^6.3^6.5^3}\)
=> E = \(\frac{3^8.5^6.2^{10}}{2^6.3^6.5^3}\)
=> E = \(3^2.5^3.2^4=18000\)
= \(\frac{45^2.4^4.5^49^2.2^2}{45^2.5.9.4^3}=4.5^3.9.2^2=18000\)
em zì ơi t.i.c.k a với nhé
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F=(3/1.8+3/8.15+...+3/106.113)-(25/50.55+25/55.60+...+25/95.100) (1)
Đặt:
A=(3/1.8+3/8.15+3/15.22+...+3/106.113)
=3/7.(1-1/8+1/8-1/15+...+1/106-1/113)
=3/7.(1-1/113)
=3/7.112/113
=336/791. (2)
B=25/50.55+25/55.60+...+25/95.100
=25/5.(1/50-1/55+1/55-1/60+...+1/95-1/100)
=5.(1/50-1/100)
=1/20 (3)
Thay (2),(3) vào (1) ta được:
F=336/791-1/20
=5929/6720.
![](https://rs.olm.vn/images/avt/0.png?1311)
câu 2: \(S=\frac{25^{28^{ }}+25^{24}+...+25^2+25^2+1}{25^{28}.25^2+25^{24}.25^4+...+25^2+1}\)
rút gọn ta được
\(S=\frac{1}{25^4+1}\)
\(\frac{3}{4}\cdot\frac{7}{25}+\frac{3}{4}\cdot\frac{18}{25}=\frac{3}{4}\left(\frac{7}{25}+\frac{18}{25}=\frac{3}{4}\cdot1=\frac{3}{4}\right)\)
3/4.7/25+3/4.18/25
= 3/4.(7/25+18/25)
= 3/4.25/25
= 3/4.1
= 3/4