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a, (2x-3)3 = -64
=> (2x-3)3 = -43
=> 2x-3=-4
=> 2x = -1
=> x = -1 : 2
=> x = -1/2
b, (2x-3)2 =25
=> (2x-3)2 =5^2
=> 2x-3 = 5
=> 2x = 8
=> x = 4
c, (3x-4)2 =36
=> (3x-4)2 =62
=> 3x-4 = 6
=> 3x = 10
=> x = 3.(3)
d, 2x+1 = 64
=> 2x+1 = 26
=> x+1 = 6
=> x = 5
\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)
\(=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)
\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)
\(=\frac{2^{40}}{2^{30}}=2^{10}\)
\(\frac{8^{20}+4^{20}}{4^{25}+64^5}\)
\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)
\(=\frac{2^{60}+2^{40}}{2^{25}+2^{30}}\)
\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{25}\left(1+2^5\right)}\)
\(=\frac{2^{15}\left(2^{20}+1\right)}{1+2^5}\)
\(=\frac{2^{35}+2^{15}}{1+2^5}\)
Ta có: \(\frac{4^6.25^5-2^{12}.25^4}{2^{12}.5^8-10^8.64}=\frac{2^{12}.5^{10}-2^{12}.5^8}{2^{12}.5^8-2^8.5^8.2^6}\)
\(=\frac{2^{12}.\left(5^{10}-5^8\right)}{2^{12}.5^8-2^{14}.5^8}\)
\(=\frac{2^{12}.5^8.\left(5^2-1\right)}{5^8.\left(2^{12}-2^{14}\right)}\)
\(=\frac{2^{12}.5^8.24}{5^8.2^{12}.\left(1-2^2\right)}\)
\(=\frac{24}{-3}\)
\(=-8\)
Học "tuốt" nha^^
a
(4x+7)2 = 25/36
(4x+7)2 = (5/6)2
==> 4x+7=5/6
4x=5/6-7=-37/6
x=-37/6:4=-37/24
b
(5+2x)3 = 8
(5+2x)3 = 23
==> 5+2x=2
2x=2-5=-3
x=-3:2=-1,5
c
3x.9=243
3x.32=35
3x=35:32
3x=33
3x=27 ==> x=27:3=9
d
42x = (-64).(-4)
42x = 43.41 = 44
==> 2x = 4
x = 4:2=2
Tick giúp mình nhe ahihi ^_^
\(25^3:64=25^3:4^3=\left(25:4\right)^3=6,25^3\)
253:64 = 15625 : 64 = 15625/64 nha