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\(\dfrac{2006\times2005-1}{2004\times2006+2005}=\dfrac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}\)
\(=\dfrac{2004\times2006+2006-1}{2004\times2006+2005}=\dfrac{2004\times2006+2005}{2004\times2006+2005}\)
\(=1\)
\(18\times\left(\dfrac{19191919+88888}{21212121+99999}\right)=18\times\left(\dfrac{19}{21}+\dfrac{8}{9}\right)\)
\(=18\times\dfrac{113}{63}=\dfrac{226}{7}=32\dfrac{2}{7}\)
\(\dfrac{{21}}{{10}} = 2,1;\dfrac{{ - 35}}{{10}} = - 3,5;\dfrac{{ - 125}}{{100}} = - 1,25;\)\(\dfrac{{ - 89}}{{1000}} = - 0,089\)
\(\begin{array}{l}\dfrac{{17}}{{10}} = 1,7\\\dfrac{{34}}{{100}} = 0,34\\\dfrac{{25}}{{1000}} = 0,025\end{array}\)
2/
a/ \(\dfrac{7}{10}=\dfrac{7.15}{10.15}=\dfrac{105}{150}\)
\(\dfrac{11}{15}=\dfrac{11.10}{15.10}=\dfrac{110}{150}\)
-Vì \(\dfrac{105}{150}< \dfrac{110}{150}\)(105<110)nên \(\dfrac{7}{10}< \dfrac{11}{15}\)
b/ \(\dfrac{-1}{8}=\dfrac{-1.3}{8.3}=\dfrac{-3}{24}\)
-Vì \(\dfrac{-3}{24}>\dfrac{-5}{24}\left(-3>-5\right)\)nên\(\dfrac{-1}{8}>\dfrac{-5}{24}\)
c/\(\dfrac{25}{100}=\dfrac{25:25}{100:25}=\dfrac{1}{4}\)
\(\dfrac{10}{40}=\dfrac{10:10}{40:10}=\dfrac{1}{4}\)
-Vì \(\dfrac{1}{4}=\dfrac{1}{4}\)nên\(\dfrac{25}{100}=\dfrac{10}{40}\)
a/ \(\dfrac{7}{10}< \dfrac{11}{15}\)
c/ \(\dfrac{25}{100}=\dfrac{10}{40}\)
Dùng hỗn số làm trung gian nhé! Mình quên không viết vào đề
\(\frac{45}{10}=\frac{9}{2}=4\frac{1}{2}=4+\frac{1}{2}=4+0,5=4,5\)
\(\frac{834}{10}=\frac{417}{5}=83\frac{2}{5}=83+\frac{2}{5}=83+0,4=83,4\)
\(\frac{1954}{100}=\frac{977}{50}=18\frac{7}{50}=18+\frac{7}{50}=18+0,14=18,14\)
\(\frac{2167}{1000}=2,167\)
\(\frac{2020}{10000}=0,202\)
\(\dfrac{-4}{50}\text{=}\dfrac{-2}{25}\)
\(\dfrac{6}{25}\text{=}\dfrac{6}{25}\)
\(\dfrac{-27}{54}\text{=}\dfrac{-1}{2}\)
\(\dfrac{-18}{-75}\text{=}\dfrac{6}{25}\)
\(\dfrac{28}{-56}\text{=}-\dfrac{1}{2}\)
suy ra chỉ có phân số \(\dfrac{-4}{50}\) là không bằng phân số nào trong các phân số còn lại
c1: \(\dfrac{27}{10}+\dfrac{291}{100}+\dfrac{38}{100}+\dfrac{547}{1000}+\dfrac{839}{10000}\)
= 2.7 + 2.91 +0.38 + 0.547 +0.0839
=6.6209
c2: ghi lại đề = \(\dfrac{27000}{10000}+\dfrac{29100}{10000}+\dfrac{3800}{10000}+\dfrac{5470}{10000}+\dfrac{839}{10000}\)
=\(\dfrac{27000+29100+3800+5470+839}{10000}\) =6.6209