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11 tháng 8 2018

\(\left(5-\frac{43}{10}\right)-\left(\frac{42}{19}-\left(\frac{7}{2}-\frac{59}{10}\right)\right)+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}-\left(\frac{42}{19}-\frac{7}{2}+\frac{59}{10}\right)+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}-\frac{42}{19}+\frac{7}{2}-\frac{59}{10}+\frac{42}{19}+\frac{59}{10}+\frac{4}{5}\)

\(=5-\frac{43}{10}+\frac{7}{2}+\frac{4}{5}\)

\(=5+\frac{35}{10}+\frac{8}{10}-\frac{43}{10}=5\)

22 tháng 6 2019

1. Q=165+247+528+125+315

= 100+60+5+200+40+7+500+20+8+100+20+5+300+10+5

= ( 100+200+500+100+300) + ( 60+40+20+20+10 ) +( 5+7+8+5+5 )

= 1200+150+30

=1280

R=1234+5678+8+80

=1000+200+30+4+5000+600+70+8+8+80

= ( 1000+5000) + ( 200+600 ) + (30+70+80) + ( 4+8+8)

=6000+800+180+20

=7000

22 tháng 6 2019

còn câu 2 mk lười lắm , bạn nhờ ngừi khác nha ^^ nhớ t i c k nha

22 tháng 6 2019

Bài 1

Tính : Q=165+247+528+125+315 

=(165+125)+(247+315+528)

=290+1090

= 1380

R=1234+5678+8+80

=(1234+6)+(5678+2)+80

= 1240+5680+80

= (1240+60)+(5680+20)

=1300+5700=7000

22 tháng 6 2019

Bài 2:

A= 243-97=(243+7)-(97-7)=250-90=160

B= 400-42-58=400-(42+58)=400-100=300

C=600-67-33=600-(67+33)=600-100=500

D=200-24-46=200-(24+46)=200-70=130

E=400-5-6-7-8=400-(5+6+7+8)=400-26=374

F= 764-115-268-43-32-20-85-37

=764-(115+85)-(268+32)-(43+37)-20

=764-200-300-80-20

=164

G=350-7-18-52-48-72

=350-(18+72)-(52+48)-7

=350-90-100-7

=160-7

=153

28 tháng 6 2019

a) Ta có:

C = 5/18 + 8/19 - 7/21 + (-10/36 + 11/19 + 1/3) - 5/8

C = 5/18 + 8/19 - 1/3 - 5/18 + 11/19 + 1/3 - 5/8

C = (5/18 - 5/18) + (8/19 + 11/19) - (1/3  - 1/3) - 5/8

C = 1 - 5/8

c = 3/8

b) F = 15/14 - (17/23 - 80/87 + 5/4) + (17/23 - 15/14 + 1/4)

F = 15/14 - 17/23 + 80/87 - 5/4 + 17/23 - 15/14 + 1/4

F = (15/14 - 15/14) - (17/23 - 17/23) + 80/87 - (5/4 - 1/4)

F = 80/87 - 1

F = -7/87

c) G = 1/25 - 4/27 + (-23/27 + -1/25 - 5/43) + 5/43 - 4/7

G = 1/25 - 4/27 - 23/27 - 1/25 - 5/43 + 5/43 - 4/7

G = (1/25 - 1/25) - (4/27 + 23/27) - (5/43 - 5/43) - 4/7

G = -1 - 4/7 = -11/7

5 tháng 7 2016

a)×+1/ 53 + ×+2 /52 + ×+3/ 51+3 = 0

\(\Rightarrow\frac{x+1}{53}+1+\frac{x+2}{52}+1+\frac{x+3}{51}+1+\frac{3\left(x+54\right)}{\left(x+54\right)}=0\)

\(\Rightarrow\frac{x+54}{53}+\frac{x+54}{52}+\frac{x+54}{51}+\frac{x+54}{\frac{1}{3}\left(x+54\right)}=0\)

\(\Rightarrow\left(x+54\right)\left(\frac{1}{53}+\frac{1}{52}+\frac{1}{51}+\frac{1}{\frac{1}{3}\left(x+54\right)}\right)=0\)

\(\Rightarrow x+54=0\).Do \(\frac{1}{53}+\frac{1}{52}+\frac{1}{51}+\frac{1}{\frac{1}{3}\left(x+54\right)}\ne0\)

=>x=-54

b)×-2/ 72 + ×-3/ 71 + ×-4/ 70 -3 = 0

\(\Rightarrow\frac{x-2}{72}-1+\frac{x-3}{71}-1+\frac{x-4}{70}-1-\frac{3\left(x-74\right)}{x-74}=0\)

\(\Rightarrow\frac{x-74}{72}+\frac{x-74}{71}+\frac{x-74}{70}-\frac{x-74}{\frac{1}{3}\left(x-74\right)}=0\)

\(\Rightarrow\left(x-74\right)\left(\frac{1}{72}+\frac{1}{71}+\frac{1}{70}-\frac{1}{\frac{1}{3}\left(x-74\right)}\right)=0\)

\(\Rightarrow x-74=0\).Do \(\frac{1}{72}+\frac{1}{71}+\frac{1}{70}-\frac{1}{\frac{1}{3}\left(x-74\right)}\ne0\)

=>x=74

c)×+5/ 81 + ×+4/ 41 + ×-7/ 31 + 6 = 0

\(\Rightarrow\frac{x+5}{81}+1+\frac{x+4}{41}+2+\frac{x-7}{31}+3+\frac{6\left(x+86\right)}{x+86}=0\)

\(\Rightarrow\frac{x+86}{81}+\frac{x+86}{41}+\frac{x+86}{31}+\frac{x+86}{\frac{1}{6}\left(x+86\right)}=0\)

\(\Rightarrow\left(x+86\right)\left(\frac{1}{81}+\frac{1}{41}+\frac{1}{31}+\frac{1}{\frac{1}{6}\left(x+86\right)}\right)=0\)

\(\Rightarrow x+86=0\).Do \(\frac{1}{81}+\frac{1}{41}+\frac{1}{31}+\frac{1}{\frac{1}{6}\left(x+86\right)}\ne0\)

=>x=-86

d)tương tự nhé

20 tháng 10 2021

\(\Rightarrow4A=4+4^2+4^3+...+4^{100}\\ \Rightarrow4A-A=\left(4+4^2+4^3+...+4^{100}\right)-\left(1+4+4^2+...+4^{99}\right)\\ \Rightarrow3A=4^{100}-1< 4^{100}=B\\ \Rightarrow A< \dfrac{B}{3}\)

\(Q=165+247+528+125+315\)

\(=\left(247+528+125\right)+\left(165+315\right)\)

\(=900+480\)

\(=1280\)

\(R=1000+200+30+4+5000+600+70+8+80\)

\(=\left(1000+5000\right)+\left(200+600\right)+\left(30+70+80\right)+\left(4+8+8\right)\)

\(=6000+800+180+20\)

\(=6000+\left(800+100\right)+\left(80+20\right)\)

\(=6000+900+100\)

\(=7000\)