Question

[Nguyễn Huyền Trang]

tính tổng avf hiệu các đa thức sau

G(x) = 21x^2 + 1 + 17x và H(x) = -2+ 6x^3-12x^2-8

M(x) = 7x^5 + 1 + 17x^4 - 2 và N(x) = 6x^4 - 12x^2 - 23x^4 + x 

Answer 1

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`G(x)+H(x)=(21x^2+1+17x)+(-2+6x^3-12x^2-8)`

`=21x^2+1+17x-2+6x^3-12x^2-8`

`= 6x^3+(21x^2-12x^2)+17x+(1-2-8)`

`= 6x^3+9x^2+17x-9`

`G(x)-H(x)=(21x^2+1+17x)-(-2+6x^3-12x^2-8)`

`= 21x^2+1+17x+2-6x^3+12x^2+8`

`= -6x^3+(21x^2+12x^2)+17x+(1+2+8)`

`= -6x^3+33x^2+17x+11`

`----`

`M(x)+N(x)=(7x^5 + 1 + 17x^4 - 2)+(6x^4 - 12x^2 - 23x^4 + x)`

`= 7x^5 + 1 + 17x^4 - 2+6x^4 - 12x^2 - 23x^4 + x`

`= 7x^5+(17x^4+6x^4-23x^4)-12x^2+x+(1-2)`

`= 7x^5-12x^2+x-1`

`M(x)-N(x)=(7x^5 + 1 + 17x^4 - 2)-(6x^4 - 12x^2 - 23x^4 + x)`

`= 7x^5 + 1 + 17x^4 - 2-6x^4 + 12x^2 + 23x^4 - x`

`= 7x^5+(17x^4-6x^4+23x^4)+12x^2-x+(1-2)`

`= 7x^5+34x^4+12x^2-x-1`