Question

[Ánh Right]

Tính:

Q=2002:[\(\dfrac{0.4-\dfrac{2}{9}+\dfrac{2}{11}}{1,4-\dfrac{7}{9}+\dfrac{7}{11}}\).\(\dfrac{-1\dfrac{1}{6}+0,875-0,7}{\dfrac{1}{3}-0,25+\dfrac{1}{5}}\)]

Answer 1

[Nguyễn Lê Phước Thịnh]

\(Q=2002:\left[\dfrac{\dfrac{2}{5}-\dfrac{2}{9}+\dfrac{2}{11}}{\dfrac{7}{5}-\dfrac{7}{9}+\dfrac{7}{11}}\cdot\dfrac{\dfrac{-7}{6}+\dfrac{7}{8}-\dfrac{7}{10}}{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}\right]\)

\(=2002:\left(\dfrac{1}{7}\cdot\dfrac{\dfrac{-7}{2}\left(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}\right)}{\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{5}}\right)\)

\(=2002:\left(\dfrac{1}{7}\cdot\dfrac{-7}{2}\right)=2002:\dfrac{-1}{2}=-4004\)