\(1/1*2+2/2*4+3/4*7+...+10/46*56\)

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28 tháng 3 2018

\(\frac{1}{1\cdot2}+\frac{2}{2\cdot4}+\frac{3}{4.7}+..........+\frac{10}{46.56}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{3}-\frac{1}{7}+........+\frac{1}{46}-\frac{1}{56}\)

\(=1-\frac{1}{56}\)

\(=\frac{55}{56}\)

2 tháng 5 2017

Bài 1:

a)

\(\dfrac{x-1}{9}=\dfrac{8}{3}\\ \Leftrightarrow\dfrac{x-1}{9}=\dfrac{24}{9}\\ \Leftrightarrow x-1=24\\ x=24+1\\ x=25\)

b)

\(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{8}\\ \dfrac{3x}{7}+1=\dfrac{-1}{8}\cdot\left(-4\right)\\ \dfrac{3x}{7}+1=\dfrac{1}{2}\\ \dfrac{3x}{7}=\dfrac{1}{2}-1\\ \dfrac{3x}{7}=\dfrac{-1}{2}\\ 3x=\dfrac{-1}{2}\cdot7\\ 3x=\dfrac{-7}{2}\\ x=\dfrac{-7}{2}:3\\ x=\dfrac{-7}{6}\)

c)

\(x+\dfrac{7}{12}=\dfrac{17}{18}-\dfrac{1}{9}\\ x+\dfrac{7}{12}=\dfrac{5}{6}\\ x=\dfrac{5}{6}-\dfrac{7}{12}\\ x=\dfrac{1}{4}\)

d)

\(0,5x-\dfrac{2}{3}x=\dfrac{7}{12}\\ \dfrac{1}{2}x-\dfrac{2}{3}x=\dfrac{7}{12}\\ x\cdot\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{7}{12}\\ \dfrac{-1}{6}x=\dfrac{7}{12}\\ x=\dfrac{7}{12}:\dfrac{-1}{6}\\ x=\dfrac{-7}{2}\)

e)

\(\dfrac{29}{30}-\left(\dfrac{13}{23}+x\right)=\dfrac{7}{46}\\ \dfrac{29}{30}-\dfrac{13}{23}-x=\dfrac{7}{46}\\ \dfrac{277}{690}-x=\dfrac{7}{46}\\ x=\dfrac{277}{690}-\dfrac{7}{46}\\ x=\dfrac{86}{345}\)

f)

\(\left(x+\dfrac{1}{4}-\dfrac{1}{3}\right):\left(2+\dfrac{1}{6}-\dfrac{1}{4}\right)=\dfrac{7}{46}\\ \left(x-\dfrac{1}{12}\right):\dfrac{23}{12}=\dfrac{7}{46}\\ x-\dfrac{1}{12}=\dfrac{7}{46}\cdot\dfrac{23}{12}\\ x-\dfrac{1}{12}=\dfrac{7}{24}\\ x=\dfrac{7}{24}+\dfrac{1}{12}\\ x=\dfrac{3}{8}\)

g)

\(\dfrac{13}{15}-\left(\dfrac{13}{21}+x\right)\cdot\dfrac{7}{12}=\dfrac{7}{10}\\ \left(\dfrac{13}{21}+x\right)\cdot\dfrac{7}{12}=\dfrac{13}{15}-\dfrac{7}{10}\\ \left(\dfrac{13}{21}+x\right)\cdot\dfrac{7}{12}=\dfrac{1}{6}\\ \dfrac{13}{21}+x=\dfrac{1}{6}:\dfrac{7}{12}\\ \dfrac{13}{21}+x=\dfrac{2}{7}\\ x=\dfrac{2}{7}-\dfrac{13}{21}\\ x=\dfrac{-1}{3}\)

h)

\(2\cdot\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|-\dfrac{3}{2}=\dfrac{1}{4}\\ 2\cdot\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{1}{4}+\dfrac{3}{2}\\ 2\cdot\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{7}{4}\\ \left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{7}{4}:2\\ \left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=\dfrac{7}{8}\Rightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{8}\\\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{-7}{8}\end{matrix}\right.\\ \dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{8}\\ \dfrac{1}{2}x=\dfrac{7}{8}+\dfrac{1}{3}\\ \dfrac{1}{2}x=\dfrac{29}{24}\\ x=\dfrac{29}{24}:\dfrac{1}{2}\\ x=\dfrac{29}{12}\\ \dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{-7}{8}\\ \dfrac{1}{2}x=\dfrac{-7}{8}+\dfrac{1}{3}\\ \dfrac{1}{2}x=\dfrac{-13}{24}\\ x=\dfrac{-13}{24}:\dfrac{1}{2}\\ x=\dfrac{-13}{12}\)

i)

\(3\cdot\left(3x-\dfrac{1}{2}\right)^3+\dfrac{1}{9}=0\\ 3\cdot\left(3x-\dfrac{1}{2}\right)^3=0-\dfrac{1}{9}\\ 3\cdot\left(3x-\dfrac{1}{2}\right)^3=\dfrac{-1}{9}\\ \left(3x-\dfrac{1}{2}\right)^3=\dfrac{-1}{9}:3\\ \left(3x-\dfrac{1}{2}\right)^3=\dfrac{-1}{27}\\ \left(3x-\dfrac{1}{2}\right)^3=\left(\dfrac{-1}{3}\right)^3\\ \Leftrightarrow3x-\dfrac{1}{2}=\dfrac{-1}{3}\\ 3x=\dfrac{-1}{3}+\dfrac{1}{2}\\ 3x=\dfrac{1}{6}\\ x=\dfrac{1}{6}:3\\ x=\dfrac{1}{18}\)

30 tháng 1 2017

a) \(2\left(x-3\right)-3\left(x-1\right)=2x+6\)

\(\Leftrightarrow2x-6-3x+3=2x+6\)

\(\Leftrightarrow-3x=9\Leftrightarrow x=-3\)

Vậy x=-3

b) \(2\left(x+7\right)-4\left(x-2\right)=10\)

\(\Leftrightarrow2x+14-4x+8=10\)

\(\Leftrightarrow-2x=-12\Leftrightarrow x=-6\)

Vậy x=-6

c) \(10-\left(1-x\right)^2=6\Leftrightarrow\left(1-x\right)^2=4\)

\(\Leftrightarrow\left[\begin{matrix}1-x=-2\\1-x=2\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy x=3 hoặc x=-1

d)\(\left(x-3\right)^3-\left[\left(-2\right)^3+2^3\right]\left(1+3+5+7+...+2001\right)=-512\)

\(\Leftrightarrow\left(x-3\right)^3=-512\)

\(\Leftrightarrow x-3=-8\Leftrightarrow x=-5\)

Vậy x=-5

30 tháng 1 2017

Xin lỗi vì đã cướp "hàng" của bác ạ ^^! Hehe leu!! #Nguyễn Huy Thắng

21 tháng 3 2017

1:

a)10/20-15/20+16/20=-5/20+16/20

=11/20.

b)2/3+8/3:8/5=2/3+5/3

=7/3.

2:a)Ta có:

2x=1/4=3/4

2x=4/4=1

x=1:2

x=0,5

b)x:(2/12-1/12)=-3/8.

x:1/12=-3/8.

x=-3/8x1/12.

x=-1/32.

29 tháng 6 2018

a) 31 . 65 + 31 . 35 - 500

=31(65+35)-500

=31..100-500

=3100-500

=2600

29 tháng 6 2018

a, 31.56+31.35-500

=31(65+35)-500

=3100-500

=2600

5 tháng 7 2018

a) x=7 và 8

b) x+1 và 2

c) 1/4

Quên rùi!!!

Cách tiểu học :

a) \(3\frac{9}{10}>2\frac{9}{10}\) ( Vì phần nguyên 3 > 2, phần phân số bằng nhau )

b) \(5\frac{1}{10}=\frac{51}{10}\), \(2\frac{9}{10}=\frac{29}{10}\)\(\frac{51}{10}>\frac{29}{10}\)

nên : \(5\frac{1}{10}>2\frac{9}{10}\)

c) \(3\frac{4}{10}=3\frac{2}{5}\) ( vì phần nguyên \(3=3\) và phần phân số \(\frac{4}{10}=\frac{2}{5}\) )

d) \(3\frac{4}{10}=3\frac{2}{5}\) ( vì phần nguyên \(3=3\) và phần phân số \(\frac{4}{10}=\frac{2}{5}\) )

4 tháng 8 2019

Nguyễn Ngọc Thiện làm cách THCS nha

20 tháng 1 2019

a) -5(x - 3) - 2(5 - 3x) = -(x - 1)

=> -5x + 15 - 10 + 6x = -x + 1

=> x + 5 = -x + 1

=> x + x = 1 - 5

=> 2x = -4

=> x = -4 : 2

=> x = -2

20 tháng 1 2019

\(-5\left(x-3\right)-2\left(5-3x\right)=-\left(x-1\right)\)

\(\Leftrightarrow-5x+15-10+6x=-x+1\)

\(\Leftrightarrow x+5=1-x\)

\(\Leftrightarrow2x=-4\)

\(\Leftrightarrow x=-4\div2\)

\(\Leftrightarrow x=-2\)