Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
b. \(\dfrac{4.2.3.5.2.6.2.5.3}{4.3.4.5.6.4.5.6}=\dfrac{1}{4}\)
c. \(\dfrac{17.2.101.2005}{17.2.101.2.2005}=\dfrac{1}{2}\)
d. \(\dfrac{2.3.4.2.11.13.17}{3.11.4.4.17.13.2}=\dfrac{1}{2}\)
a)\(\dfrac{4\times6\times10\times12\times15}{4\times12\times5\times24\times30}=\dfrac{2}{2\times2\times2}=\dfrac{2}{8}=\dfrac{1}{4}\)
b)\(\dfrac{34\times101\times2005}{17\times202\times4010}=\dfrac{2}{2\times2}=\dfrac{2}{4}=\dfrac{1}{2}\)
c)\(\dfrac{6\times8\times11\times13\times17}{33\times16\times17\times26}=\dfrac{6}{3\times2\times2}=\dfrac{1}{2}\)
a,=3/13.17/29.29/34
=3/13.1/2
=3/26
b,=(4/21+25/42).19/33
=11/14.19/33
=19/42
`a, = 3/13 xx (17/29 xx 29/34)`
`= 3/13 xx 1/2`
`= 3/26`.
`b, = 19/33(4/21 + 25/42)`
`= 19/33 xx ( 33/42 )`
`= 19/42`
33/15 x 35/21 x 63/14 x 9/30
= 11/5 x 5/3 x 9/2 x 3/10
= 99/20
= \(\frac{33}{15}\)x \(\frac{5}{3}\)x \(\frac{9}{2}\)x \(\frac{3}{10}\)
= \(\frac{11}{3}\)x \(\frac{9}{2}\)x \(\frac{3}{10}\)
= \(\frac{33}{2}\)x \(\frac{3}{10}\)
= \(\frac{99}{20}\)
a)
`3/5xx3/2`
`=3/5xx2/3`
`=2/5`
b)
`3/7:3/14`
`=3/7xx14/3`
`=2`
c)
`5/7xx7/10`
`=1/2`
d)
`5/11xx33/15`
`=5/11xx11/5`
`=1`
\(a,\dfrac{3}{5}:\dfrac{3}{2}=\dfrac{3}{5}\times\dfrac{2}{3}=\dfrac{6}{15}=\dfrac{2}{5}\)
\(b,\dfrac{3}{7}:\dfrac{3}{14}=\dfrac{3}{7}\times\dfrac{14}{3}=\dfrac{42}{21}=42:21=2\)
\(c,\dfrac{5}{7}\times\dfrac{7}{10}=\dfrac{35}{70}=\dfrac{1}{2}\)
\(d,\dfrac{5}{11}\times\dfrac{33}{15}=\dfrac{165}{165}=165:165=1\)
Lời giải:
\(\frac{15}{17}\times \frac{45}{33}-\frac{15}{17}\times \frac{12}{33}=\frac{15}{17}\times (\frac{45}{33}-\frac{12}{33})=\frac{15}{17}\times \frac{33}{33}=\frac{15}{17}\times 1=\frac{15}{17}\)
a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)
\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)
=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)
b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)
Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)
c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)
\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)
=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)
d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)
\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6
=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)
x * 17 + x * 33 = 150
x * ( 17 + 33 ) = 150
x * 50 = 150
x = 150 : 50
x = 3
x : 14 - x : 10 = 306
x : ( 14 - 10 ) = 306
x : 4 = 306
x = 306 x 4
x = 1224
x*17+x*33=150
<=>x*(17+33)=150
<=>x*50=150
=>x=150:50
=>x=3
X:14-X:10=306
<=>X:(14-10)=306
<=>X:4=306
=>X=306*4
=>X=1224