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212 = ( 20 + 1 )2 = 202 + 2.20.1 + 12 = 400 + 40 + 1 = 441
1992 = ( 200 - 1 )2 = 2002 - 2.200.1 + 12 = 40 000 - 400 + 1 = 39 601
299.301 = ( 300 - 1 )( 300 + 1 ) = 3002 - 12 = 90 000 - 1 = 89 999
312 = ( 30 + 1 )2 = 302 + 2.30.1 + 12 = 900 + 60 + 1 = 961
992 = ( 100 - 1 )2 = 1002 - 2.100.1 + 12 = 10 000 - 200 + 1 = 9801
62.58 = ( 60 + 2 )( 60 - 2 ) = 602 - 22 = 3600 - 4 = 3596
1992 = (200 – 1)2 = 2002 – 2.200 + 1 = 40000 – 400 + 1 = 39601
a) \(52^2\)
\(=\left(50+2\right)^2\)
\(=50^2+2\cdot2\cdot50+2^2\)
\(=2500+200+4\)
\(=2704\)
b) \(98^2\)
\(=\left(100-2\right)^2\)
\(=100^2-2\cdot100\cdot2+2^2\)
\(=10000-400+4\)
\(=9604\)
`a, 52^2 = (50+2)^2 = 2500 + 200 + 4 = 2704`
`b, 98^2 = (100-2)^2 = 100^2 - 2 . 100 . 2 + 4 = 10000 - 400 + 4`
`= 9604`
a) \(82\cdot78\)
\(=\left(80+2\right)\cdot\left(80-2\right)\)
\(=80^2-2^2\)
\(=6400-4\)
\(=6396\)
b) \(87\cdot93\)
\(=\left(90-3\right)\left(90+3\right)\)
\(=90^2-3^2\)
\(=8100-9\)
\(=8091\)
c) \(125^2-25^2\)
\(=\left(125-25\right)\left(125+25\right)\)
\(=100\cdot150\)
\(=15000\)
`a, 38 . 42 = (40-2)(40+2) = 1600 - 4 = 1596`.`
`b, 102^2 = (100+2)^2 = 10000 + 400 + 4 = 10404`
`c, 198^2 = (200-2)^2 = 40000 - 800 + 4 = 39204`
`d, 75^2 - 25^2 = (75+25)(75-25) = 100. 50 = 5000`
3A:
a: \(75\cdot20.9+5^2\cdot20.9\)
\(=20.9\cdot100\)
=2090
b: \(86\cdot15+150\cdot1.4\)
\(=86\cdot15+15\cdot14\)
\(=15\cdot100=1500\)
c: \(93\cdot32+14\cdot16\)
\(=93\cdot32+32\cdot7\)
=3200
Bài 2.
a) 1013 = (100+1)3 = 1003+3.1002.1+3.100.12+13
= 1000000+30000+300+1 = 1030301
b) 2993 = (300-1)3 = 3003-3.3002.1+3.300.12-13
= 27000000 - 270000 + 900 -1 = 26730899
c) 993 = (100-1)3 = 1003-3.1002.1+3.100.12-1
= 1000000 - 30000 + 300 -1 = 970299
\(1,\\ b,A=\left(u-v\right)^3+3uv\left(u+v\right)\\ A=u^3-3u^2v+3uv^2-v^3+3u^2v+3uv^2=u^3-v^3\\ c,6\left(c-d\right)\left(c+d\right)+2\left(c-d\right)^2-\left(c-d\right)^3\\ =6c^2-6d^2+2c^2-4cd+2d^2-c^3+3c^2d-3cd^2+d^3\\ =8c^2-c^3-4d^2-4cd+3c^2d-3cd^2+d^3\)
\(2,\\ a,101^3=\left(100+1\right)^3\\ =100^3+3\cdot10000\cdot1+3\cdot100\cdot1+1\\ =1000000+30000+300+1=1030301\\ b,299^3=\left(300-1\right)^3\\ =300^3-3\cdot90000\cdot1+3\cdot300\cdot1-1\\ =27000000-270000+900-1\\ =26730899\\ c,99^3=\left(100-1\right)^3\\ =100^3-3\cdot10000\cdot1+3\cdot100\cdot1-1\\ =1000000-30000+300-1=970299\)
Bài 1:
a.
$=(x^3+2^3)-(x^3-2)=2^3+2=10$
b.
$=(x^2+10x+25)-4x(4x^2+12x+9)-(2x-1)(x^2-9)$
$=x^2+10x+25-16x^3-48x^2-36x-(2x^3-18x-x^2+9)$
$=-18x^3-46x^2-8x+16$
2.
a.
$301^2=(300+1)^2=300^2+2.300+1=90000+600+1$
$=90601$
b.
$198^2=(200-2)^2=4(100-1)^2=4(100^2-2.100+1)$
$=4(10000-200+1)=4.9801=39204$
c.
$93.107=(100-7)(100+7)=100^2-7^2$
$=10000-49=9951$
d.
$127^2+146.127+73^2$
$=127^2+2.73.127+73^2$
$=(127+73)^2=200^2=40000$
a) 21 2 = ( 20 + 1 ) 2 = 20 2 + 20.20 + 1 = 441.
b) 62.58 = (60 + 2).(60 – 2) = 60 2 – 2 2 = 3600 – 4 = 3596.