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791:789+5.52-124
=791:789+5.25-124
=791-89+125-124
=72+125-124
=49+125-124
=174-124
=50
4.15+28:7-620:618
=60+4-620-18
=64-62
=64-36
=28
(32+23):7
=(9+8):7
=17:7
=17/7
1125:1123-35:(110+23)-60
=1125:1123-35:(1+8)-60
=1125:1123-35:9-60
=1125:1123-35:33-60
=1125-23-35-3-60
=112-32-60
=121-9-60
=112-60
=52
\(\frac{5.6+5.7}{5.8+20}\)và \(\frac{8.9-4.15}{12.7-180}\)
Ta có : \(\frac{5.6+5.7}{5.8+20}=\frac{30+35}{40+20}=\frac{65}{60}=\frac{13}{12}\)
\(\frac{8.9-4.15}{12.7-180}=\frac{72-60}{84-180}=\frac{12}{-96}=\frac{-1}{8}\)
+) Tìm \(12=2^2.3\)
\(8=2^3\)
\(MC=BCNN\left(12,18\right)=2^3.3=24\)
Khi đó : \(\frac{13}{12}=\frac{13.2}{12.2}=\frac{26}{24}\)
\(\frac{-1}{8}=\frac{-1.3}{8.3}=\frac{-3}{24}\)
p/s : kham khảo
\(=\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{20}-\dfrac{1}{21}=\dfrac{1}{3}-\dfrac{1}{21}=\dfrac{6}{21}=\dfrac{2}{7}\)
\(\dfrac{5\cdot6+5\cdot7}{5\cdot8+20}=\dfrac{5\cdot6+5\cdot7}{5\cdot4\cdot2+5\cdot4}=\dfrac{5\cdot\left(6+7\right)}{5\cdot4\cdot\left(2+1\right)}=\dfrac{5\cdot13}{5\cdot4\cdot3}=\dfrac{13}{4\cdot3}=\dfrac{13}{12}\)
\(\dfrac{5.6+5.7}{5.8+20}\)
=\(\dfrac{5.\left(6+7\right)}{5.\left(8+4\right)}\)
=\(\dfrac{5.13}{5.12}\)
=\(\dfrac{13}{12}\)
Ta có:
\(A=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{19}.3^{19}.2^9-7.2^{29}.3^{18}}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}\left(2.5-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)
\(=\frac{2^{29}.3^{18}}{2^{28}.3^{18}}=2\)
k nha