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\(\frac{2^3.9^4+9^3.45}{9^2.10-9^2}=\frac{9^3\left(72+45\right)}{9^3}=72+45=117\)
\(\left(2^3.9^8.5\right):\left(9^2.\left(10-1\right)\right)\)
\(=2^3.9^8.5:9^3\)
\(=2^3.9^5.5\)
\(\left(2^3.9^4.9^3.45\right):\left(9^2.10-9^2\right)\)
(=) \(\left(2^3.3^8.3^6.5.3^2\right):9^2\left(10-1\right)\)
(=) \(\left(2^3.3^{15}.5\right):3^4.3^2\)
(=) \(2^3.3^9.5\)
\(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)
\(=\left(2^3.9^4+9^3.\left(9.5\right)\right):\left[9^2.\left(10-1\right)\right]\)
\(=\left[2^3.9^4+9^4.5\right]:\left(9^2.9\right)\)
\(=9^4.\left(2^3+5\right):9^3\)
\(=\left(2^3+5\right).\left(9^4:9^3\right)\)
\(=\left(8+5\right).9\)
\(=13.9\)
\(=117\)
(23 . 94 + 93 . 45) : (92 . 10 - 92)
= (23 . 94 + 94 . 5): [92 . (10 - 1)]
= 94 (23 + 5) : [92 . (10 - 1)]
= 94 . 13 : 93
= 9 . 13
= 117.
Vậy.....
\(=9^3\left(2^3\cdot9+45\right):\left[9^2\left(10-1\right)\right]=9^3\cdot\left(72+45\right):9^3=117\)
\(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)=\left(2^3.9^4+9^3.9.5\right):\left(9^2.9\right)=\left(9^4\left(2^3+5\right)\right):9^3=9^4.13:9^3=9.13=117\)
đúng cho mk nha Nguyễn Ngọc Thuỳ Vy
\(\frac{2^3.9^4+9^3.45}{9^2.10-9^2}=\frac{9^3\left(2^3.8+45\right)}{9^2\left(10-1\right)}=\frac{9^3.\left(64+45\right)}{9^2.9}=\frac{9^3.109}{9^3}=109\)