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\(A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Leftrightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
\(A=\frac{4}{1.3.5}+\frac{4}{3.5.7}+\frac{4}{5.7.9}+\frac{4}{7.9.11}+\frac{4}{9.11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(\Rightarrow A=\frac{1}{1.3}-\frac{1}{11.13}=\frac{1}{3}-\frac{1}{143}=\frac{140}{429}\)
32,48 : 0,25 + 67,52 x 4
= ( 32,48 + 67,52) : ( 0,25 x4)
= 100 : 1
= 100
(dấu . là dấu nhân )
a, \(\frac{3}{2}\cdot\frac{4}{7}+\frac{3}{7}\cdot\frac{3}{2}\)
= \(\frac{3}{2}\left(\frac{4}{7}+\frac{3}{7}\right)\)
=\(\frac{3}{2}\cdot\frac{7}{7}=\frac{3}{2}\)
b, \(\frac{12}{5}\cdot4-4\cdot\frac{7}{5}\)
=\(4\left(\frac{12}{5}-\frac{7}{5}\right)=4\cdot\frac{5}{5}=4\)
c, \(\frac{5}{11}:\frac{1}{2}+\frac{6}{11}:\frac{1}{2}\)
=\(2\left(\frac{5}{11}+\frac{6}{11}\right)=2\cdot\frac{11}{11}=2\)
a;3/2x(4/7+3/7)
=3/2x1
=3/2
b;12/5x4-4x7/5
=4x(12/5-7/5)
=4x1
=4
c;5/11:1/2+6/11:1/2
=1/2:(5/11+6/11)
=1/2:1
=1/2
\(\frac{6}{7}.\frac{11}{5}+\frac{11}{5}.\frac{4}{7}-\frac{2}{3}\)
=\(\left(\frac{6}{7}+\frac{4}{7}\right).\frac{11}{5}-\frac{2}{3}\)
=\(\frac{10}{7}.\frac{11}{5}-\frac{2}{3}\)
=\(\frac{52}{21}\)
25-2 : (3/5-1/2) + (5/2 +1/5 * 1/4 )
= 25 - 2 : 1/10 + (5/2 + 1/20)
= 25 - 20 + 51/20
= 5 + 51/20
= \(5\frac{51}{20}\)
( 3/10+ 4/5 *1/2 ) : (17/9 -4/3 : 3)
= (3/10 + 2/5) : (17/9 - 4/9)
= (-1/10) : 13/9
= -9/130
a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
số số hạng là:
(50-1)+1=50(số)
tổng là:
(50+1)x50:2=1275
có số cặp là:50:2=25(cặp)
tổng của dãy số trên là:(50+1) x 25=1275
đáp số:1275
\(\frac{1}{5}+\frac{3}{7}+\frac{4}{5}+\frac{11}{7}\)
\(=\left(\frac{1}{5}+\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{11}{7}\right)\)
\(=1+2\)
\(=3\)
\(67,52-15,39+32,48-22,13\)
\(=52,13+10,35\)
\(=62,48\)
1/5 +3/7+4/5+11/7
= 1/5+4/5+3/7+11/7
= 5/5=+ 11/7
= 1 + 11/7
= 18/7