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tham khảo
Đặt A = 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
A x 3 = 3 x (1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729)
= 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243
A x 3 - A = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 - (1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729)
= 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 - 1/3 - 1/9 - 1/27 - 1/81 - 1/243 - 1/729
= 1 - 1/729
A x 2 = 728/729
A = 364/729
-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1+20
=(-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1-1)+20
=-20+20
=0
nhớ ck cho tớ đó
M=\(\frac{1}{1\cdot2}\)- \(\frac{1}{2\cdot3}\)+ \(\frac{1}{2\cdot3}\) - \(\frac{1}{3\cdot4}\) +..........+ \(\frac{1}{10\cdot11}\) - \(\frac{1}{11\cdot12}\)
= \(\frac{1}{2}\) - \(\frac{1}{11\cdot12}\)
=\(\frac{65}{132}\)
a) \(a+1-a+1+99\)
\(=\left(a-a\right)+\left(1+1\right)+99\)
\(=2+99\)
\(=101\)
b) \(2010:1-2010:10:3\)
\(=2010:1-\left(2010:10\right):3\)
\(=2010-201:3\)
\(=2010-67\)
\(=1943\)
a) \(\frac{1}{2}\times\frac{12}{13}+\frac{1}{3}\times\frac{12}{13}+\frac{1}{4}\times\frac{12}{13}\)
= (1/2 + 1/3 + 1/4) x 12/13
= 13/12 x 12/13
= 1
b) (1 - 1/2 ) x (1 - 1/3) x (1 - 1/4) x ( 1 - 1/5)
= 1/2 x 2/3 x 3/4 x 4/5
= 1/5
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 10
= 1 x 10
= 10
ai thấy đúng bấm !