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\(A=1-2-3+4+5-6-7+8...+993-994-995+996+997\)
\(A=\left(1-2-3+4\right)+\left(5-6-7+8\right)...+\left(993-994-995+996\right)+997\)
\(A=0+0+...+0+997=997\)
\(\frac{1}{10}.\frac{1}{11}+\frac{1}{11}.\frac{1}{12}+\frac{1}{12}.\frac{1}{13}+....+\frac{1}{20}.\frac{1}{21}\)
\(=\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+....+\frac{1}{20}-\frac{1}{21}\)
\(=\frac{1}{10}-\frac{1}{21}\)
\(=\frac{11}{210}\)
a) 8/3 x 2/5 x 3/8 x 10 x 19/92
= ( 8/3 x 3/8 ) x ( 2/5 x 10 ) x 19/92
= 1 x 4 x 19/92
= 4 x 19/92 = 76/92 = 19/23
b) N = 5/7 x 5/11 + 5/7 x 2/11 - 5/7 x 14/11
= 5/7 x ( 5/11 + 2/11 - 14/11 )
= 5/7 x ( -7/11 )
= -5/11
\(A=\left(\frac{1}{10}-1\right).\left(\frac{1}{11}-1\right)....\left(\frac{1}{100}-1\right)\))
\(A=\frac{-9}{10}.\frac{-10}{11}...\frac{-99}{100}\) ( lẻ thừa số nguyên âm)
\(A=\frac{-9}{100}\)
\(A=\left(\frac{1}{10}-1\right)\left(\frac{1}{11}-1\right)...\left(\frac{1}{100}-1\right)\)
\(\Rightarrow A=-\frac{9}{10}.\frac{-10}{11}...\frac{-99}{100}\)
\(\Rightarrow-A=\frac{9}{10}.\frac{10}{11}...\frac{99}{100}\)
\(\Rightarrow-A=\frac{9.10.11...99}{10.11...99.100}\)
\(\Rightarrow-A=\frac{9}{100}\)
\(\Rightarrow A=-\frac{9}{100}\)
993 x 11 + 77
=993 x 11 + 7x 11
= 11 x ( 993 + 7 )
= 11x 1000
= 11000
ĐÚng cho mình nha