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( 42 x 43 + 43 x 57 + 43 ) - 360 : 4
= 43 x ( 42 + 57 + 1 ) - 90
= 43 x 100 - 90
= 4300 - 90
= 4210
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\(2018\times\frac{3}{4}+2018\times\frac{1}{4}-2018\)
\(=2018\times\left(\frac{3}{4}+\frac{1}{4}-1\right)\)
\(=2018\times0=0\)
B-a:tương tự bài A
b,\(\frac{14}{18}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)
\(=\frac{7}{9}\times\frac{8}{5}-\frac{7}{9}\times\frac{3}{5}\)
\(=\frac{7}{9}\times\left(\frac{8}{5}-\frac{3}{5}\right)\)
\(=\frac{7}{9}\times1=\frac{7}{9}\)\
thanks
B-a,\(\frac{3\times125+3\times125}{6\times43+6\times57}=\frac{2\times3\times125}{6\times\left(43+57\right)}\)
\(=\frac{3\times250}{6\times100}=\frac{5}{2\times2}=\frac{5}{4}\)
thanks
![](https://rs.olm.vn/images/avt/0.png?1311)
43*42+57*43+43
= 43 * ( 42 + 57 + 1)
= 43 * 100
= 4300
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số số hạng có trong biểu thức trên là:
(58 - 40 ) : 1 + 1 = 19
=>( 40 - 41 ) + ( 42 - 43 ) + ... + ( 56 - 57 ) + 58
=> (-1) x [( 19 - 1 ) : 2 ] + 58
=> (-1) x 9 + 58
=> (-9) + 58
=> 49
HT~~~
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\(2022\times57+2022\times42+2022=2022\times\left(57+42+1\right)=2022\times\left(57+43\right)=2022\times100=202200.\)
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289 x 57 + 311 x 45 + 289 x 43 + 311 x 55
= 289 x ( 57 + 43 ) + 311 x ( 45 + 55 )
= 289 x 100 + 311 x 100
= ( 289 + 311 ) x 100
= 600 x 100
= 60000
\(289x57+311x45+289x43+311x55\)\(=289x\left(57+43\right)+311x\left(45+55\right)\)
\(=289x100+311x100=100x\left(289+311\right)\)\(=100x600=60000\)
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42 x 15 + 57 x 15 + 15
= ( 42+57+1 ) x 15
= 100 x 15
= 1500
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