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a) \(\frac{-3}{16}+\frac{-7}{16}+\frac{6}{-16}\)
\(=-\frac{3}{16}+-\frac{7}{16}+\frac{-6}{16}\)
\(=\frac{\left(-3\right)+\left(-7\right)+\left(-6\right)}{16}\)
\(=\frac{-16}{16}=-1\)
b) \(\frac{2}{5}-\frac{1}{7}+\frac{7}{10}\)
\(=\frac{28}{70}-\frac{10}{70}+\frac{49}{70}\)
\(=\frac{28-10+49}{70}\)
\(=\frac{67}{70}\)
c) \(3+\frac{1}{3}-2\frac{1}{2}\)
\(=\frac{3}{1}+\frac{1}{3}-\frac{5}{2}\)
\(=\frac{18}{6}+\frac{2}{6}-\frac{15}{6}\)
\(=\frac{18+2-15}{6}\)
\(=\frac{5}{6}\)
d) \(-\frac{3}{5}-\left(-\frac{2}{15}\right)\)
\(=-\frac{3}{5}+\frac{2}{15}\)
\(=\frac{-9}{15}+\frac{2}{15}\)
\(=-\frac{7}{15}\)
\(\frac{-3}{16}\)+(\(\frac{-7}{16}\) ) +(\(\frac{6}{-16}\))
=\(\frac{-3-7-6}{16}\)
=\(\frac{-16}{16}\)= \(-1\)
\(\frac{2}{5}\)\(-\)\(\frac{1}{7}\)+\(\frac{7}{10}\)
=\(\frac{9}{35}\)+\(\frac{7}{10}\)
=\(\frac{67}{70}\)
3+ \(\frac{1}{3}\)\(-\) \(\frac{21}{2}\)
=\(\frac{18+2-63}{6}\)
=\(\frac{-43}{6}\)
\(\frac{-3}{5}\)\(-\)(\(\frac{-2}{15}\))
=\(\frac{-3}{5}\)+\(\frac{2}{15}\)
=\(\frac{-9+2}{15}\)
=\(\frac{-7}{15}\)
số số hạng là :
(2002-1):1+1=2002
tổng đó là :
(2002+1)x2002:2=2005003
b)
số số hạng là :
(2014-2):4+1=504
tổng đó là :
( 2014 + 2 ) x 504 : 4 = 254016
câu b cho sửa lại
số các số hạng:
(2014-2):4+1=504
tổng các số hạng:
(2014+2).504:2=508032
a) \(6-2\left(x+4\right)=-4\)
\(\Leftrightarrow6-2x-8=-4\)
\(\Leftrightarrow-2-2x=-4\)
\(\Leftrightarrow-2x=-4+2\)
\(\Leftrightarrow-2x=-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
b) tự làm.
c) \(2x-15:5=-7\)
\(\Leftrightarrow2x-7,5=-7\)
\(\Leftrightarrow2x=-7+7,5\)
\(\Leftrightarrow2x=0,5\)
\(\Leftrightarrow x=0,25\)
\(\Leftrightarrow x=\dfrac{1}{4}\)
Vậy \(x=\dfrac{1}{4}\)
d) \(231-\left(x-6\right)=1339:13\)
\(\Leftrightarrow231-x+6=103\)
\(\Leftrightarrow237-x=103\)
\(\Leftrightarrow237-x+6=103\)
\(\Leftrightarrow-x=103-237\)
\(\Leftrightarrow-x=-134\)
\(\Leftrightarrow x=134\)
e) đề j mà có 2 dấu bằng >> sai :v
f) \(28-x^3=1\)
\(\Leftrightarrow-x^3=1-28\)
\(\Leftrightarrow-x^3=-27\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
g) \(\left(x+2\right)^3=27\)
\(\Leftrightarrow\left(x+2\right)^3=3^3\)
\(\Leftrightarrow x+2=3\)
\(\Leftrightarrow x=3-2\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
h) \(81-\left(x-5\right)^2=56\)
\(\Leftrightarrow-\left(x-5\right)^2=56-81\)
\(\Leftrightarrow-\left(x-5\right)^2=-25\)
\(\Leftrightarrow\left(x-5\right)^2=25\)
\(\Leftrightarrow x-5=\pm5\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)
Vậy \(x_1=0;x_2=10\)
j) \(x^2=9\)
\(\Leftrightarrow x=\pm3\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x_1=-3;x_2=3\)
l) tự làm.
1. Số số hạng tổng S là:
(2016-3):3+1=672
Tổng S là:
(3+2016).672:2=678384
3.
231-(x-6)=1339:13
231-(x-6)=103
x-6=231-103
x-6=128
x=128+6
x=134
a) \(6-2x-8=-4\Leftrightarrow2x=2\Leftrightarrow x=1\)
b) \(6⋮x\Rightarrow x=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)
c) \(2x-3=-7\Leftrightarrow2x=-4\Leftrightarrow x=-2\)
d) \(231-x+6=103\Leftrightarrow x=124\)
e) hình như sai đề
f) \(x^3=27\Leftrightarrow x=3\)
g) \(x+2=3\Leftrightarrow x=1\)
h) \(\left(x+5\right)^2=25\Leftrightarrow x+5=5\Leftrightarrow x=0\)
i) \(x^2=9\Leftrightarrow\orbr{\begin{cases}x=-3\\x=3\end{cases}}\)
j) \(14⋮\left(x+3\right)\Rightarrow x=\left\{-17;-10;-5;-4;-2;4;11\right\}\)
A) Ta có: 28 x ( 231 + 69) + 72 x ( 231 + 69)
= ( 28 + 72 ) x ( 231 + 69)
= 100 x 300
= 30 000
b) 2017 - { 52 x 22 - 11 [ 72 - 5 x 23 + 8 x (112 - 121) ] }
= 2017 - { 100 - 11 [ 49 - 40 + 8 x 0 ] }
= 2017 - { 100 - 1 [ 9 + 0 ]
= 2017 - { 100 - 1 x 9 }
= 2017 - { 99 x 9 }
= 2017 - 891
= 1126
c) 10 - { [ ( x : 3 + 17) : 10 + 2 x 24 ] : 10 } = 5
=> { [( x : 3 + 17 ) : 10 + 2 x 16 ] : 10 } = 10 - 5 = 5
=> [ ( x : 3 + 17) : 19 + 32 ] = 5 x 10 = 50
=> ( x : 3 + 17 ) : 19 = 50 - 32 = 18
=> x : 3 + 17 = 18 x 19 = 342
=> x : 3 = 342 - 17 = 325
=> x = 325 x 3
=> x = 975
Vậy x = 975
tôi nhầm ddcj chưa!!