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Câu A là :2x19x6+3x37x4+44x12=228+444+528=1200
Câu B là:18x15+35+15x32+35x49=270+35+480+1715=(1715+35)+(270+480)=1750+750=1500
2.19.6 + 3.37.4 + 44.12
= 12 .19 + 12.37 + 44.12
= 12.(19+37+44)
= 12.100 = 1200
![](https://rs.olm.vn/images/avt/0.png?1311)
2.9.6+3.37.4+44.12
=2.6.9+3.4.37+44.12
=12.9+12.37+44.12
=12. (9+37+44)
=12.90
=1080
2.9.6+3.37.4+44.12
=2.3.3.3.2+3.37.4+44.4.3
=4.3.3.3+3.4.37+44.3.4
=3.4.(3.3+37+44)
=12.80
=960
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3.7.11}{44.12}=\frac{3.7.11}{4.11.3.4}=\frac{7}{4.4}=\frac{7}{16}\)
\(\frac{22+77}{7.5.11}=\frac{99}{7.5.11}=\frac{9.11}{7.5.11}=\frac{9}{35}\)
\(\frac{3.7.11}{44.12}=\frac{3.7.11}{11.4.3.4}=\frac{7}{4^2}\)
\(\frac{22+77}{7.5.11}=\frac{11\left(2+7\right)}{35.11}\frac{9}{35}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 37.12=37.3.4=111.4=444
b, 15873.21= 15873. 7. 3= 111111. 3= 333333
a, Ta có: 37 . 3 = 111
mà \(12=3.4\)
\(\Rightarrow37.12=37.3.4=111.4=444\)
b, Ta có: 15873.7 = 111111
mà \(21=7.3\)
\(\Rightarrow15873.21=15873.7.3=111111.3=333333\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{49.51}\right)\)
\(A=\frac{3}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
Vậy \(A=\frac{25}{17}\)
Chúc bạn học tốt ~
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
\(B=\frac{21}{4}\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\frac{4}{21}\)
\(B=\left(\frac{21}{4}.\frac{4}{21}\right).33\)
\(B=33\)
\(C=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)
\(C=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(C=\frac{1}{2}\left(1-\frac{1}{99}\right)\)
\(C=\frac{1}{2}.\frac{98}{99}\)
\(C=\frac{49}{99}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Số các số hạng là :
( 100 - 2 ) : 2 + 1 = 50 ( số )
Tổng các số trên là :
50 x ( 100 + 2 ) : 2 = 2550
Đáp số : 2550
Mình nhanh nhất
So cac so hang la: (100-2):2+1=50 (so)
*(so lon nhat - so be nhat) : khoang cach +1 hay (so cuoi - so dau): khoang cach + 1
Tong cua day la: (100+2)x50:2=2550
*(so cuoi + so dau) x so so hang : 2
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 3 :
A = 26 + 27 + 28 + 29 + 30 + 31 + 32 + 33
=> A = ( 33 + 26 ) . 8 : 2 = 236
Vậy A = 236
\(\text{#Hok tốt!}\)
a) 2 . 31 . 12 + 4 . 6 . 42 + 8 . 27 . 3
= 24 . 31 + 24 . 42 + 24 . 27
= 24 . ( 31 + 42 + 27 )
= 24 . 100
= 2400
Đáp số: 1200