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1X3X5+2X6X10+4X12X20+7X21X35 /1X5X7+2X10X14+4X20X28+7X35X49
=3+6+12+21 /7+14+28+49
=42 /98=3/7
Bài này chỉ có thể tính bình thường đc thôi ak, nếu muốn lời giải chuẩn thì tham khảo nhé!
\(\frac{1x3x5+2x6x10+4x12x20+7x21x35}{1x5x7+2x10x14+4x20x28+7x35x49}\)
Nhận xét:
a)Phần tử số:
2x6x10= (1 x 2) x (3x2) x (5x2) = (2x2x2) x (1x3x5)
4x12x20= (1x4) x (3x4) x (5x4) = (4x4x4) x (1x3x5)
7x21x35= (1x7) x (3x7) x (5x7) = (7x7x7) x (1x3x5)
b)Phần mẫu số:
2x10x14= (1x2) x (5x2) x (7x2) = (2x2x2) x (1x5x7)
4x20x28= (1x4) x (5x4) x (7x4) = (4x4x4) x (1x5x7)
7x35x49= (1x7) x (5x7) x (7x7) = (7x7x7) x (1x5x7)
Vậy:
\(\frac{1x3x5+2x6x10+4x12x20+7x21x35}{1x5x7+2x10x14+4x20x28+7x35x49}\)
\(=\frac{\left(1x3x5\right)+\left(2x2x2\right)x\left(1x3x5\right)+\left(4x4x4\right)x\left(1x3x5\right)+\left(7x7x7\right)x\left(1x3x5\right)}{\left(1x5x7\right)+\left(2x2x2\right)x\left(1x5x7\right)+\left(4x4x4\right)x\left(1x5x7\right)+\left(7x7x7\right)x\left(1x5x7\right)}\)
\(=\frac{\left(1x3x5\right)x\left(1+2x2x2+4x4x4+7x7x7\right)}{\left(1x5x7\right)x\left(1+2x2x2+4x4x4+7x7x7\right)}\)
\(=\frac{1x3x5}{1x5x7}\)\(=\frac{3}{7}\)
\(\frac{1.3.5+2.6.10+4.12.20+7.21.35}{1.5.7+2.10.14+4.20.28+7.35.49}=\frac{3.5+\left(4.12.4\right)5+\left(2.6.2\right).5+\left(7.21.7\right).5}{5.7+\left(2.2.14\right).5+\left(4.4.28\right).5+\left(7.7.49\right).5}\)
Ta có:
1×3×5 + 2×6×10 + 4×12×20 + 7×21×35/1×5×7 + 2×10×14 + 4×20×28 + 7×35×49
= 1×3×5×(1x1x1 + 2×2×2 + 4×4×4 + 7×7×7)/1×5×7×(1×1×1 + 2×2×2 + 4×4×4 + 7×7×7)
= 3/7 = 300/700 = 1 - 400/700
308/708 = 1 - 400/708
Vì 400/700 > 400/708
=> 1 - 400/700 < 1 - 400/708
=> 3/7 < 308/708
So sánh vs 308/708 hợp lí hơn đó bn
So sánh phần thiếu để =1
Nếu > thì <
< thì >
Chứ bạn đằn nhiều quá
Làm VD 1 câu nhé:\(\frac{1992}{1993}=1-\frac{1}{1993};\frac{1994}{1995}=1-\frac{1}{1995}\)
Vì \(\frac{1}{1993}>\frac{1}{1995}\Rightarrow\frac{1992}{1993}< \frac{1994}{1995}\)
A= 2006*2010-2005 / 2007*2009-2008
A=4032060-2005 / 4032063-2008
A=4030055/4030055
A=1
\(\dfrac{2007\times2006-1}{2005\times2007+2006}\)
\(=\dfrac{2007\times2006-1}{\left(2006-1\right)\times2007+2006}\)
\(=\dfrac{2007\times2006-1}{2006\times2007-2007+2006}\)
\(=\dfrac{2007\times2006-1}{2006\times2007-\left(2007-2006\right)}\)
\(=\dfrac{2007\times2006-1}{2007\times2006-1}\)
\(=1\)
\(\dfrac{2007x2006-1}{2005x2007+2006}\)
\(=\dfrac{2007x\left(2005+1\right)-1}{2005x2007+2006}\)
\(=\dfrac{2007x2005+2007-1}{2005x2007+2006}\)
\(=\dfrac{2007x2005+2006}{2005x2007+2006}=1\)
A, chờ tí nha
B, rút gọn phân số ta được
= 27 . \(\frac{17}{27}\)- \(\frac{37}{36}\)
= 17 - \(\frac{36}{37}\)= \(\frac{649}{36}\)
a: \(\dfrac{2007\times2009-1}{2006+2007\times2008}\)
\(=\dfrac{\left(2008-1\right)\times\left(2008+1\right)-1}{2008-2+2008\left(2008-1\right)}\)
\(=\dfrac{2008^2-1-1}{2008-2+2008^2-2008}\)
\(=\dfrac{2008^2-2}{2008^2-2}=1\)
b: \(\dfrac{1\times5\times18+2\times10\times30+3\times15\times54}{1\times5\times7+2\times10\times14+3\times15\times21}\)
\(=\dfrac{1\times5\times6\left(1+2\times2\times6+3\times3\times9\right)}{1\times5\times7\left(1+2\times2\times2+3\times3\times3\right)}\)
\(=\dfrac{6}{7}\times\dfrac{106}{36}=\dfrac{106}{7}\times\dfrac{1}{6}=\dfrac{53}{21}\)