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\(A=\frac{199}{200}+\frac{200}{201}+\frac{201}{202}< \frac{199}{200+201+202}+\frac{200}{200+201+202}+\frac{201}{200+201+202}\)
A \(< \frac{199+200+201}{200+201+202}=B\)
\(A< B\)
Ta có: \(A=\frac{199}{200}+\frac{200}{201}+\frac{201}{202}< \frac{199}{200+201+202}+\frac{200}{200+201+202}+\frac{201}{200+201+202}< \)
\(< \frac{199+200+201}{200+201+202}\)
Vậy A < B
ỦNG HỘ TỚ NHA
\(\frac{199}{200}>\frac{199}{200+201+202}\)
\(\frac{200}{201}>\frac{200}{200+201+202}\)
\(\frac{201}{202}>\frac{201}{200+201+202}\)
=>\(A>B\)
Do \(\frac{199}{200}\)> \(\frac{199}{200+201+202}\), \(\frac{200}{201}\)>\(\frac{200}{200+201+202}\),\(\frac{201}{202}\)>\(\frac{201}{200+201+202}\)nên A>B
a) 126+ (-29)+ 2004+ (-106)
= [126+ (-106)] +2004+ (-29)
= 20+ 2004- 29
= 2024-29
= 1995
b) (-199)+ (-200)+ (-201)
= -(199+200+201)
= -600
a) 126 + (-20) + 2004 + (-106)
= [126 + (-20) + (-106)] + 2004
= 0 + 2004
= 2004
b) (-199) + (-200) + (-201)
= [(-199) + (-201)] + (-200)
= (-400) + (-200)
= -600
a) -37+1526-(213-37)
=-37+1526-213+37
=[(-37)+37]+1526-213
=1313
b) 2.37+(29-137)-53:19
=74-108-
2. a) \(3^{200}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=\left(2^3\right)^{100}=8^{100}\)
Vì \(9^{100}>8^{100}\Rightarrow3^{200}>2^{300}\)
b) \(71^{50}=\left(71^2\right)^{25}=5041^{25}\)
\(37^{75}=\left(3^3\right)^{25}=27^{25}\)
Vì \(5041^{25}>27^{25}\Rightarrow71^{50}>37^{75}\)
c) \(\frac{201201}{202202}=\frac{201201:1001}{202202:1001}=\frac{201}{202}\)
\(\frac{201201201}{202202202}=\frac{201201201:1001001}{202202202:1001001}=\frac{201}{202}\)
Vì \(\frac{201}{202}=\frac{201}{202}\Rightarrow\frac{201201}{202202}=\frac{201201201}{202202202}\)
Đáp án D
Ta có:
199 + 36 + 201 + 184 + 37 = 199 + 201 + 36 + 184 + 37 = 400 + 220 + 37 = 620 + 37 = 657