Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) 89 658 : x = 293
x = 89 658 : 293
x = 306
b) 54 322 : x =346
x = 54 322 : 346
x = 157
c)106 141 : x =413
x = 106 141 : 413
x = 257
a) 89 658 : x = 293
x = 89 658 : 293
x = 306
Vậy x = 306
b) 54 322 : x = 346
x = 54 322 : 346
x = 157
Vậy x = 157
c) 106 141 : x = 413
x = 106 141 : 413
x = 257
Vậy x = 257
\(35136\div18=1952\)
\(53278\div34=1567\)
\(703665\div57=12345\)nha do ko đặt tính đc thông cảm
\(35136:18=1952\)
\(911950:25=36478\)
\(53278:34=1567\)
\(703665:57=12345\)
Bạn thông cảm nhé vì không đặt tính được
Bài 1:
a, \(\frac{1}{7}+3+\frac{5}{6}=\frac{1}{7}+\frac{3}{1}+\frac{5}{6}=\frac{6}{42}+\frac{126}{42}+\frac{35}{42}=\frac{167}{42}\)
b, \(\frac{4}{7}+\frac{5}{9}+4=\frac{4}{7}+\frac{5}{9}+\frac{4}{1}=\frac{36}{63}+\frac{35}{63}+\frac{252}{63}=\frac{323}{63}\)
2.3.4.8.50.25.125
= 30000000
5,72.11 + 5,72.88 +5,72
= 572
\(\text{[ 1 + 2 + 3 +4 + ........ + 999 + 1000 +1001 ] x [ [ 456 x 9 + 456 ] : [4570 -10 ] ] }\)
\(=\left[\frac{1001+1}{2}\right].\)\(\left[456.\left(9+1\right):4560\right]\)
\(=501.1\)
\(=501\)
chúc bạn học tốt
a) \(D=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+...+\frac{1}{512}+\frac{1}{1024}\)
=> \(2D=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...++\frac{1}{256}+\frac{1}{512}\)
=> \(2D-D=\left(1+\frac{1}{2}+...+\frac{1}{512}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\right)\)
=> \(D=1-\frac{1}{1024}\)
b) \(Đ=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{18.19}+\frac{1}{19.20}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\)
\(=1-\frac{1}{20}=\frac{19}{20}\)
a) D=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\dots+\frac{1}{512}+\frac{1}{1024}.\)
\(D=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\dots+\frac{1}{512}-\frac{1}{1024}\)
\(D=1-\frac{1}{1024}\)
\(D=\frac{1023}{1024}\)
\(Đ=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\dots+\frac{1}{18\cdot19}+\frac{1}{19\cdot20}\)
\(Đ=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\dots+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\)
\(Đ=1-\frac{1}{20}\)
\(Đ=\frac{19}{20}\)
Phần c như kiểu sai đề chỗ cuối hay sao ấy.
a,3/7+4/5+4/7.
= ( 3/7 + 4/7 ) + 4/5
= 1 + 4/5
= 9/5
b,6/11+1/3+5/11
= ( 6/11 + 5/11 ) + 1/3
= 1 + 1/3
= 4/3
#hien#