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a) \(\frac{2}{5}+\frac{9}{15}=\frac{2}{5}+\frac{3}{5}=\frac{5}{5}=1\)
b) \(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{7}{6}\)
c) \(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{12}{8}=\frac{3}{2}\)
d) \(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{19}{42}\)
a) \(\frac{2}{5}+\frac{9}{15}\)=\(\frac{2}{5}+\frac{3}{5}=\frac{2+3}{5}=1\)
b)\(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{2+5}{6}=\frac{7}{6}\)
c)\(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{7+5}{8}=\frac{12}{8}=\frac{3}{2}\)
d)\(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{12+7}{42}=\frac{19}{42}\)

23568 x 4 + 23568 x 5 + 23568 = 23568 x (4 + 5 + 1) = 23568 x 10 = 235680
23568x4+23568x5+23568
=23568x(4+5+1)
=23568x10
=235680

a)2/5+3/5 = 1
b)7/8+5/8 = 12/8= 3/2
c) 1/2+1/3 = 5/6
d) 2/7+1/6= 19/42
a, 2/5 + 9/15 28/32 + 45/72 b, 4/8 + 8/24 8/28 + 5/30
= 2/5 + 3/5 = 7/8 + 5/8 = 1/2 + 1/3 = 2/7 + 1/6
= 1. = 3/2. = 5/6. = 19/42.
k cho mik nha !


\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{72}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{8.9}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{9}\)
\(=1-\frac{1}{9}\)
\(=\frac{8}{9}\)

y : 2 + 450 : 5 - 202 , với y = 240
Thay vào , ta có :
240 : 2 + 450 : 5 - 202
= 120 + 450 : 5 - 202
= 120 + 90 - 202
= 210 - 202
= 8
Vậy với y = 240 giá trị biểu thức trên = 8
Thay y=240 ta được:
240 : 2 + 450 : 5 -202
= 120 + 90 - 202
= 210 - 202
= 8

240 : 2 + 450 : 5 - 202
= 120 + 90 - 202
=210 - 202
= 8


Câu 1:\(\frac{12}{23}\times\frac{9}{28}+\frac{11}{23}\times\frac{9}{28}\)
\(=\frac{9}{28}\times\left(\frac{12}{23}+\frac{11}{23}\right)\)
\(=\frac{9}{28}\times\frac{23}{23}\)
\(=\frac{9}{28}\times1\)
\(=\frac{9}{28}\)
Câu 2:
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)
\(=\left(3+2+2+3\right)+\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)\)
\(=10+\frac{9}{9}\)
\(=10+1\)
\(=11\)
\(\frac{12}{23}x\frac{9}{28}+\frac{11}{23}x\frac{9}{28}=\)\(\left(\frac{12}{23}+\frac{11}{23}\right)x\frac{9}{28}\)\(=\) \(1x\frac{9}{28}=\frac{9}{28}\)
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)\(=\) \(\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)+\left(3+2+3+2\right)\)\(=\) \(1+3+2+3+2=\)\(11\)
Giúp m nhé
450 x ( 72 + 28 )
= 450 x 100
= 45 000