Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a , 42 + 44 + 46 + 48 + 50
= (42 + 48) + (44 + 46) + 50
= 90 + 90 + 50
= 180 + 50
= 230
b ,
150 . 250 . 400 . 800
= (150 . 800) . (250 . 400)
= (150 . 2 . 400) . (250 . 400)
= (300 . 400) . (250 . 400)
= 120 000 . 100 000
= 12 000 000 000.
a) \(5^6.4^3.19=5^6.\left(2^2\right)^3.19=\left(5.2\right)^6.19=1000000.19=19000000\)
b)\(123.25^4.16^2=123.5^8.2^8=123.\left(5.2\right)^8=123.10^8=123.100000000=12300000000\)
c) \(73.5^{12}.8^4=73.5^{12}.\left(2^3\right)^4=73.\left(5.2\right)^{12}=73.10^{12}=73.1000000000000=73000000000000\)
d)\(1111.8^4.25^7=1111.\left(2^3\right)^4.\left(5^2\right)^7=1111.2^{12}.5^{14}=\left(1111.25\right).\left(2.5\right)^{12}=27775.10^{12}\)
\(=27775.1000000000000=27775000000000000\)
a)56x43=1000000
1000000x19=19000000
b) 12300000000
c) 73000000000000
d) Ko ra đc
2/5 . A = 2/10.12 + 2/12.14 + ....... + 2/998.1000
= 1/10 - 1/12 + 1/12 - 1/14 + ..... + 1/998 - 1/1000
= 1/10 - 1/1000 = 99/1000
=> A = 99/1000 : 2/5 = 99/400
Tk mk nha
Mình làm tắt cũng dc nhé có gì ko dc hỏi mình nhé
Ta có:A=(5/10-5/12):2+(5/12-2/14):2+...+(5/998-5/1000):2
suy ra A=5/10-5/1000=99/200
\(\text{a)}\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(4^2-2^4\right)\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left[\left(2^2\right)^2-2^4\right]\)
\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(2^4-2^4\right)\)
\(=\left(2^{17}-17^2\right)\left(9^{15}-15^9\right).0\)
\(=0\)
\(\text{b)}\left(7^{1997}-7^{1995}\right):\left(7^{1994}.7\right)=\frac{7^{1997}-7^{1995}}{7^{1994}.7}=\frac{7^{1995}\left(7^2-1\right)}{7^{1995}}=7^2-1=48\)
\(A=\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}+\frac{1}{132}+\frac{1}{156}\)
\(=\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}+\frac{1}{11.12}+\frac{1}{12.13}\)
\(=\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}+\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}\)
\(=\frac{1}{7}-\frac{1}{13}\)
\(=\frac{6}{91}\)
\(A=\frac{1}{7\times8}+\frac{1}{8\times9}+\frac{1}{9\times10}+...+\frac{1}{13\times14}\)
\(=\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{13}-\frac{1}{14}\)
\(=\frac{1}{7}-\frac{1}{14}=\frac{1}{14}\)
2B= 2 + 22+.......+250+251
2B - B= (2+22+.......+251) - (1+2+......+250)
B=251-1
a) 252525.4 – 999999 = 25.10101.4 – 99.10101 = 10101.(100 – 99) = 10101
b) 250025.4 – 500050.2 = 25.4.10001 – 50.2.10001 = 100.10001 – 100.10001 = 0