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ĐỀ SAI TỚ ĐOÁN PHẢI LÀ 1.2+2.3+3.4+....+99.100
3S=1.2.3+2.3.3+3.4.3+....+99.100.3
3S=1.2.3+2.3.(4-1)+3.4(5-2)+.....+99.100(101-98)
3S=1.2.3+2.3.4-2.3.1+......+99.100.101-98.99.100
3S=99.100.101
\(S=\frac{99.100.101}{3}\)
\(S=333300\)
\(3^{2018}\left(3^{20}:\left(3^8\cdot3^{11}\right)+2\cdot3\right)=3^{2018}\left(3^{20}:3^{19}+2\cdot3\right)\)
\(=3^{2018}\left(3+2\cdot3\right)=3^{2018}\cdot9=3^{2018}\cdot3^2\)
\(=3^{2020}\)
Trả lời
\(\frac{31}{17}+\left(\frac{-5}{13}\right)+\left(\frac{-8}{13}\right)-\frac{4}{17}\)
\(=\left(\frac{31}{17}-\frac{4}{17}\right)+\left[\left(\frac{-5}{13}\right)+\left(\frac{-8}{13}\right)\right]\)
\(=\frac{27}{17}+\left(\frac{-13}{13}\right)\)
\(=\frac{27}{17}+\left(-1\right)\)
\(=\frac{10}{17}\)
\(\frac{31}{17}+\frac{-5}{13}+\frac{-8}{13}-\frac{4}{17}\)
\(=\left(\frac{31}{17}-\frac{4}{17}\right)+\left(\frac{-5}{13}+\frac{-8}{13}\right)\)
\(=\frac{27}{13}+\frac{-13}{13}\)
\(=\frac{27}{13}+\left(-1\right)\)
\(=\frac{10}{17}\)
\(=\frac{22}{25}\cdot\frac{5}{11}-\frac{22}{25}\cdot\frac{8}{9}-\frac{8}{9}\cdot\frac{27}{4}+\frac{8}{9}\cdot\frac{22}{25}\)
\(=\frac{2}{5}-6=-\frac{28}{5}\)
a) \(5^6.4^3.19=5^6.\left(2^2\right)^3.19=\left(5.2\right)^6.19=1000000.19=19000000\)
b)\(123.25^4.16^2=123.5^8.2^8=123.\left(5.2\right)^8=123.10^8=123.100000000=12300000000\)
c) \(73.5^{12}.8^4=73.5^{12}.\left(2^3\right)^4=73.\left(5.2\right)^{12}=73.10^{12}=73.1000000000000=73000000000000\)
d)\(1111.8^4.25^7=1111.\left(2^3\right)^4.\left(5^2\right)^7=1111.2^{12}.5^{14}=\left(1111.25\right).\left(2.5\right)^{12}=27775.10^{12}\)
\(=27775.1000000000000=27775000000000000\)
a)56x43=1000000
1000000x19=19000000
b) 12300000000
c) 73000000000000
d) Ko ra đc
Đặt A = 1.2.3.4.5.6.7.8
Từ đề bài, ta có:
A .9 - A - A .8
= A ( 9-1-8)
= A . 0
= 0
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