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Bài 1:
a) 19/27+9/7+6/27+5/7+2/7
= (19/27+6/27) + (9/7+5/7+2/7)
=1 + 16/7
=23/7
b) 2/7 + 27/48 + 7/16 +45/63
= (2/7 + 45/63) + (27/48 +7/16)
= (2/7 + 5/7) + ( 9/16 + 7/16)
= 1 + 1
=2
c) Tính bằng cách bình thường
Bài 2:
6/11 + x = 1
x = 1-6/11
x = 5/11
Bài làm
a) \(\frac{19}{27}+\frac{9}{7}+\frac{6}{27}+\frac{5}{7}+\frac{2}{7}\)
\(=\frac{27}{27}+\frac{16}{7}\)
\(=1+\frac{16}{7}\)
\(=\frac{7}{7}+\frac{16}{7}\)
\(=\frac{23}{7}\)
b) \(\frac{2}{7}+\frac{27}{48}+\frac{7}{16}+\frac{45}{63}\)
\(=\left(\frac{18}{63}+\frac{45}{63}\right)+\left(\frac{27}{48}+\frac{21}{48}\right)\)
\(=\frac{63}{63}+\frac{48}{48}\)
\(=1+1\)
\(=2\)
c) \(\frac{17}{23}+\left(\frac{4}{7}-\frac{6}{13}\right)\)
\(=\frac{17}{23}+\left(\frac{52}{91}-\frac{42}{91}\right)\)
\(=\frac{17}{23}+\frac{10}{91}\)
\(=\frac{1547}{2093}+\frac{230}{2093}\)
\(=\frac{1770}{2093}\)
Bài 2
\(\frac{6}{11}+x=1\)
\(x=1-\frac{6}{11}\)
\(x=\frac{11}{11}-\frac{6}{11}=\frac{5}{11}\)
Vậy \(x=\frac{5}{11}\)
Sky Nguyễn
\(\dfrac{14}{9}-\dfrac{1}{6}-\dfrac{1}{3}-\dfrac{1}{2}+\dfrac{4}{9}\\ =\left(\dfrac{14}{9}+\dfrac{4}{9}\right)-\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)\\ =\dfrac{18}{9}-\left(\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\right)\\ =2-\dfrac{6}{6}\\ =2-1\\ =1\)
\(\dfrac{18}{45}=\dfrac{2}{5}\dfrac{63}{81}=\dfrac{7}{9}\) minh chi co the lam the nay thoi vi minh dang co viec gap
Tính hợp lý:
2 x 144 x 18 + 4 x 41 x 9 + 3 x 15 x 12=?
Help me! Mình đang cần ngay trong ngày hôm nay!
2 x 144 x 18 + 4 x 41 x 9 + 3 x 15 x 12
=36x144+36x41+36x15
=36x(144+41+15)
=36x200
=7200
HT
A) 2424 : 8 : 3
= 303 : 3
= 101
B) (360 x 25 x 12 ) : 24
= 360 x 25 x 12 : 24
= 360 : 24 x 25 x 12
= 15 x 300
= 4 500
C) ( 750 x 360 x 56 ) : ( 25 x 12 x 7 )
=>\(\frac{750x360x56}{25x12x7}\)
= \(30x30x8\)
= \(900x8\)
=\(7200\)
a. \(678\times\left(276+49\right)-678\times\left(149+76\right)\)
\(=678\times\left[\left(276+49\right)-\left(149+76\right)\right]\)
\(=678\times\left(276+49-149-76\right)\)
\(=678\times\left(200-100\right)\)
\(=67800\)
b. \(23\times157+15\times46-28\times87\)
\(=3611+690-2436\)
\(=1865\)
c. \(12:\left\{390:\left[500-\left(125+35\times7\right)\right]\right\}\)
\(=12:\left\{390:\left[500-\left(125+245\right)\right]\right\}\)
\(=12:\left\{390:\left[500-370\right]\right\}\)
\(=12:\left\{390:130\right\}\)
\(=12:3\)
\(=4\)