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2 tháng 4 2021
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
2 tháng 4 2021
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
W
4 tháng 3 2020
1/ 35. 18 – 5. 7. 28
= 35.(18-28)
=35.-10
=-350
2/ 45 – 5. (12 + 9)
=5.(9-12-9)
=5.-12
=-60
3/ 24. (16 – 5) – 16. (24 - 5)
= 24.16-24.5-16.24+16.5
=-24.5+16.5
=(-24+16).5
=-8.5
=-40
8 tháng 8 2019
a) \(\frac{-1}{2}+\frac{-1}{9}-\frac{-3}{5}+\frac{1}{2006}-\frac{-2}{7}-\frac{7}{18}+\frac{4}{35}\)
\(=\left(\frac{-1}{2}-\frac{1}{9}-\frac{7}{18}\right)+\left(\frac{3}{5}+\frac{4}{35}\right)+\frac{1}{2006}\)
\(=\left(\frac{-9}{18}-\frac{2}{18}-\frac{7}{18}\right)+\left(\frac{21}{35}+\frac{4}{35}\right)+\frac{1}{2006}\)
\(=\left(\frac{-9-2-7}{18}\right)+\left(\frac{21+4}{35}\right)+\frac{1}{2006}\)
\(=\left(\frac{-18}{18}\right)+\left(\frac{25}{35}\right)+\frac{1}{2006}\)
\(=\left(-1\right)+\frac{5}{7}+\frac{1}{2006}\)\(=\frac{-4005}{14042}\)
b) \(\frac{1}{3}-\frac{3}{4}+\frac{3}{5}+\frac{1}{2007}-\frac{1}{36}+\frac{1}{15}-\frac{2}{9}\)
\(=\left(\frac{1}{3}+\frac{1}{2007}-\frac{2}{9}\right)-\left(\frac{3}{4}+\frac{1}{36}\right)+\left(\frac{3}{5}+\frac{1}{15}\right)\)
\(=\left(\frac{669}{2007}+\frac{1}{2007}-\frac{446}{2007}\right)-\left(\frac{27}{36}+\frac{1}{36}\right)+\left(\frac{9}{15}+\frac{1}{15}\right)\)
\(=\frac{224}{2007}-\frac{28}{36}+\frac{10}{15}\)
\(=\frac{224}{2007}-\frac{1561}{2007}+\frac{1338}{2007}\)\(=\frac{1}{2007}\)
L
11 tháng 5 2020
Trả lời :
\(a,\frac{3}{2}\times\left(\frac{5}{7}-\frac{4}{3}\right)-\frac{4}{3}\times\left(\frac{5}{7}-\frac{3}{2}\right)\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{3}{2}\times\frac{4}{3}-\frac{4}{3}\times\frac{5}{7}+\frac{4}{3}\times\frac{3}{2}\)
\(=\frac{3}{2}\times\frac{5}{7}-\frac{4}{3}\times\frac{5}{7}\)
\(=\frac{5}{7}\times\left(\frac{3}{2}-\frac{4}{3}\right)\)
\(=\frac{5}{42}\)
b, Tương tự câu a. Kết quả \(=-\frac{3}{7}\)
17 tháng 8 2018
\(D=\dfrac{1}{2}+\dfrac{-1}{5}+\dfrac{-5}{7}+\dfrac{1}{6}+\dfrac{-3}{35}+\dfrac{1}{3}+\dfrac{1}{41}\)
\(D=\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{3}\right)+\left(\dfrac{-1}{5}+\dfrac{-5}{7}+\dfrac{-3}{35}\right)+\dfrac{1}{41}\)
\(D=1+-1+\dfrac{1}{41}\)
\(D=0+\dfrac{1}{41}\)
\(D=\dfrac{1}{41}\)
22 tháng 8 2022
\(C=\left(\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}\right)+\left(\dfrac{-3}{4}+\dfrac{-1}{36}+\dfrac{-2}{9}\right)+\dfrac{1}{57}\)
\(=\dfrac{5+9+1}{15}+\dfrac{-27-1-8}{36}+\dfrac{1}{57}\)
=1/57
\(E=\left(-\dfrac{1}{2}-\dfrac{1}{9}-\dfrac{7}{18}\right)+\left(\dfrac{3}{5}+\dfrac{4}{35}+\dfrac{2}{7}\right)+\dfrac{1}{127}=\dfrac{1}{127}\)
6 tháng 8 2019
\(\frac{3}{5}-\frac{1}{9}-\frac{1}{2}-\frac{1}{127}+\frac{7}{18}+\frac{4}{35}+\frac{2}{7}\)=\((\frac{1}{9}-\frac{1}{2}+\frac{7}{18})+(\frac{3}{5}+\frac{2}{7}+\frac{4}{35})+\frac{1}{127}\)=\(0+1+\frac{1}{127}\)=\(1+\frac{1}{127}=\frac{128}{127}\)
Ta có: \(\frac{-1}{2}+\frac{3}{5}+\frac{-1}{9}+\frac{1}{127}+\frac{-7}{18}+\frac{4}{35}+\frac{2}{7}\)
\(=\left(\frac{3}{5}+\frac{2}{7}+\frac{4}{35}\right)+\left(\frac{-1}{2}+\frac{-1}{9}+\frac{-7}{18}\right)+\frac{1}{127}\)
\(=\left(\frac{21}{35}+\frac{10}{35}+\frac{4}{35}\right)+\left(\frac{-9}{18}+\frac{-2}{18}+\frac{-7}{18}\right)+\frac{1}{127}\)
\(=\frac{35}{35}+\frac{-18}{18}+\frac{1}{127}\)
\(=1+\left(-1\right)+\frac{1}{127}\)
\(=\frac{1}{127}\)