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15 tháng 11 2021

Tính hợp lí:

b) 42. 3 - 7 . [(-34) + 18]

= 7. 6. 3 – 7. [(-34) + 18]

= 7. 18 – 7. [(-34) + 18] 

= 7. [18 - (- 34) – 18]

= 7. [(18 – 18) + 34]

= 7. (0 + 34)

= 7. 34

= 238.

19 tháng 2 2022

\(B=\dfrac{-1}{9}+\dfrac{8}{7}+\dfrac{10}{9}+\dfrac{-29}{7}\\ B=\left(\dfrac{-1}{9}+\dfrac{10}{9}\right)+\left(\dfrac{8}{7}+\dfrac{-29}{7}\right)\\ B=1+\dfrac{-11}{7}=1\dfrac{-11}{7}\)

19 tháng 2 2022

B=\(-\dfrac{1}{9}+\dfrac{8}{7}+\dfrac{10}{9}+\dfrac{-29}{7}\)

\(B=\left(-\dfrac{1}{9} +\dfrac{10}{9}\right)+\left(\dfrac{8}{7}-\dfrac{29}{7}\right)\)

\(B=1+\left(-3\right)\)

\(B=-2\)

28 tháng 11 2021

\(B=-\left(1+4+7+...+100\right)\\ B=-\dfrac{\left(100+1\right)\left[\left(100-1\right):3+1\right]}{2}=-\dfrac{101\cdot34}{2}=-1717\\ C=10+10+10+10-103=50-103=-53\)

Bạn có thể viết rõ ra ko chứ ntn tớ ko nhìn được

15 tháng 11 2021

=(13-13).(23-17)

=0.6

=0

15 tháng 11 2021

ảo

16 tháng 5 2018

Cho A = 1.2 + 2.3 + ...+ 99.100

=> 3A = 1.2 .3 + 2.3.3 + ...+ 99.100.3

3A = 1.2.( 3-0) + 2.3.(4-1) + ....+ 99.100.( 101 - 98)

3A = 1.2.3 + 2.3.4 - 1.2.3 + ...+ 99.100.101 - 98.99.100

3A = ( 1.2.3 + 2.3.4 + 99.100.101) - ( 1.2.3 + ....+ 98.99.100)

3A = 99.100.101

=> A = 99.100.101 . 1/3

thay A vào B

\(B=(\frac{99.100.101.\frac{1}{3}}{99.100.101}):\frac{1}{3}\)

\(B=\frac{1}{3}:\frac{1}{3}\)

\(B=1\)

16 tháng 5 2018

\(B=\left(\frac{1.2+2.3+...+99.100}{99.100.101}\right)\div\frac{1}{3}\)

\(\text{Đặt}:C=1.2+2.3+...+99.100\)

\(\Rightarrow3C=1.2.3+2.3.3+...+99.100.3\)

\(\Rightarrow3C=1.2.3+2.3.\left(4-1\right)+...+99.100.\left(101-98\right)\)

\(\Rightarrow3C=1.2.3+2.3.4+...+99.100.101\)

\(\Rightarrow3C=\left(1.2.3+2.3.4+...+99.100.101\right)\)\(-\)\(\left(1.2.3+2.3.4+....+98.99.100\right)\)

\(\Rightarrow3C=99.100.101\)

\(\Rightarrow C=\frac{99.100.101}{3}\)

Thay C vào biểu thức B ta được : 

\(B=\left(\frac{\frac{99.100.101}{3}}{99.100.101}\right)\div\frac{1}{3}=\frac{1}{3}\div\frac{1}{3}=1\)

Vậy B= \(1\)

1: =66+34-73-27+99=99

2: =54-45+30-54-30+5=-40

3: =42-56+33-33+56-42=0

4: =50-47-50+18+47-18=0

5: =10-28+30-4=2-4+10=12-4=8

25 tháng 1 2022

\(\text{1.-(-66)+34+(-73)-27+99}.\)

\(=66+34-73-27+99=100-100+99=-99.\)

\(\text{2.54-(45-30+54)-30+5}.\)

\(54-45+30-54-30+5=\left(54-54\right)+\left(-45+5\right)+\left(30-30\right)=-40.\)

\(\text{3.42-56+33-(33-56+42)}.\)

\(=42-56+33-33+56-42=\left(42-42\right)+\left(-56+56\right)+\left(33-33\right)=0.\)

\(\text{4.50-(47+50-18)+(47-18)}.\)

\(=50-47-50+18+47-18=\left(50-50\right)+\left(-47+47\right)+\left(18-18\right)=0.\)

\(\text{5.10-(28-30+4)}.\)

\(=10-28+30-4=10+30-20-8-4=20-12=8.\)

\(\text{6.-(-73)+(44-94+27)+94}.\)

\(=73+44-94+27+94=\left(73+27\right)+\left(-94+94\right)+44=100+44=144.\)

5 tháng 8 2023

\(27.332+93.43+57.61+69.57\\ =27.332+93.43+57.\left(61+69\right)\\ =27.332+93.43+57.130\\ =8964+3999+7410=20373\\ 34.75+75.66-65.100\\ =\left(34+66\right).75-65.100\\ =100.75-65.100\\ =100.\left(75-65\right)\\ =100.10=1000\\ \left(456.11+912\right).37:13:74\\ =5928:13:\left(74:37\right)\\ =456:2=228\\ 6^2:4.3+2.5^2\\ =36:4.3+2.25\\ =9.3+50=27+50=77\\ 5.4^2-18:3^2\\ =5.16-18:9\\ =80-2=78\\\left[\left(315+372\right).3+\left(372+315\right).7\right]:\left(26.13+74.14\right)\\ =687.\left(3+7\right):\left(338+1036\right)\\ 687.10:1374\\ =6870:1374=5\\ 12:\left\{390:\left[500-\left(125+35.7\right)\right]\right\}\\ =12:\left[390:\left(500-370\right)\right]\\ =12:\left(390:130\right)=12:3=4\\ 192000-\left(1500.2+1800.3+1800.2:3\right)\\ =192000-\left(3000+5400+1200\right)\\ =192000-9600=182400\)

AH
Akai Haruma
Giáo viên
6 tháng 2

Lời giải:
a.

$21\times 23-3\times 7\times (-17)$

$=21\times 23-21\times (-17)$

$=21\times 23+21\times 17=21\times (23+17)=21\times 40$

$=840$

b.

$42\times 3-7\times [(-34)+18]$

$=7\times 18-7\times (-16)$

$=7\times 18+7\times 16=7\times (18+16)=7\times 34=238$

c.

$=142\times 32+32\times (-7)-13\times 32$

$=32\times (142-7-32)=32\times 103=3296$

d.

$=13\times [(23-17)-(23+17)]$

$=13\times (23-17-23-17)=13\times (-34)=-442$

17 tháng 8 2023

\(a,\dfrac{2}{7}+\dfrac{5}{7}.\dfrac{7}{10}-\dfrac{1}{14}\)

\(=\dfrac{1}{7}.2+\dfrac{1}{7}.5.\dfrac{7}{10}-\dfrac{1}{7}.\dfrac{1}{2}\)

\(=\dfrac{1}{7}.\left(2+\dfrac{35}{10}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.\left(\dfrac{4}{2}+\dfrac{7}{2}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.5=\dfrac{5}{7}\)

\(b,\left(3\dfrac{1}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\left(\dfrac{7}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{7}{34}.\dfrac{5}{7}\)

\(=\dfrac{7}{34}.\left(\dfrac{17}{6}-\dfrac{5}{7}\right)\)

\(=\dfrac{7}{34}.\dfrac{89}{42}=\dfrac{89}{204}\)

a: =2/7-1/14+5/10

=2/7-1/14+1/2

=4/14-1/14+7/14

=10/14=5/7

b: =(7/2-2/3)*7/34-5/34

\(=\dfrac{21-4}{6}\cdot\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\dfrac{7}{6}\cdot\dfrac{1}{2}-\dfrac{5}{34}=\dfrac{7}{12}-\dfrac{5}{34}=\dfrac{89}{204}\)