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a)
\(-68+\left(-72\right)+2017+\left(-28\right)+168.\)
\(=\left(-68+168\right)+\left(-28-72\right)+2017.\)
\(=\left(168-68\right)+\text{ }\left[-\left(72+28\right)\right]+2017.\)
\(=100+\left(-100\right)+2017.\)
\(=100-100+2017.\)
\(=2017\)
b)
\(\left|-28\right|+\left(129-182+99\right)\)\(-\left(129+199-182\right)\)
\(=28+129-182+99\)\(-129-199+182.\)
\(=28+\left(129-129\right)+\left(182-182\right)\)\(-\left(199-99\right)\)
\(=28+0+0-100.\)
\(=-\left(100-28\right)\)
\(=-72\)
c)
\(17\left(-83\right)+18\times83.\)
\(=-17\left(83\right)+18\left(83\right)\)
\(=83\left[18+\left(-17\right)\right]\)
\(=83\left(18-17\right)\)
\(=83\left(1\right)\)
\(=83\)
d)
\(2018^0-\left(15^2\div\left[175+\left(2^3\times5^2-6\times25\right)\right]\right).\text{ }\)
\(=1-\left(15^2\div\left[175+\left(8\times25-6\times25\right)\right]\right)..\)
\(=1-\left(15^2\div\left[175+\left(25\left[8-6\right]\right)\right]\right)\)
\(=1-\frac{15^2}{175+\left(25\times2\right)}.\)
\(=1-\frac{15^2}{175+50}\)
\(=1-\frac{225}{225}\)
\(=1-1\)
\(=0\)
Học tốt
a: \(=-25\cdot4-27=-100-27=-127\)
b: \(=-65:\left(-13\right)-25\cdot4=5-100=-95\)
c: \(=100\cdot\left(-47\right)+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
d: \(=\left[\left(-3\right)^{13}:3^{10}-73\right]:\left(-5\right)^2-14\)
\(=\left(-100\right):25-14=-4-14=-18\)
\(125-\left(-75\right)+32-\left(48+32\right)\)
\(=125-\left(-75\right)+32-80\)
\(=125+75+32-80\)
\(=200+32-80\)
\(=232-80\)
\(=152\)
\(-63+415-37-115\)
\(=352-57-115\)
\(=315-115\)
\(=200\)
\(13.\left(-2\right)^2+37.4+4.\left(-150\right)\)
\(=13.2^2+37.4+4.-150\)
\(=13.4+37.4+4.-150\)
\(=4.\left(13+37+-150\right)\)
\(=4.-100\)
\(=-400\)
\(-15.x+4=79\)
\(\Leftrightarrow-15.x=79-4\)
\(\Leftrightarrow-15.x=75\)
\(\Leftrightarrow x=75:-15\)
\(\Leftrightarrow x=-5\)
Vậy \(x=-5\)
\(15-\left(2+x\right)=23\)
\(\Leftrightarrow2+x=15-23\)
\(\Leftrightarrow2+x=-8\)
\(\Leftrightarrow x=-8-2\)
\(\Leftrightarrow x=-10\)
Vậy \(x=-10\)
\(\left(x+2\right)\left(x^2-1\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2-1^2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)=0\)
\(\Leftrightarrow x=\pm1\)
Vậy \(x\in\left\{\pm1\right\}\)
\(56:\left|x-4\right|=7\)
\(\Leftrightarrow\left|x-4\right|=56:7\)
\(\Leftrightarrow\left|x-4\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=8\\x-4=-8\end{cases}\Leftrightarrow\orbr{\begin{cases}x=8+4\\x=-8+4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=12\\x=-4\end{cases}}}\)
Vậy \(x\in\left\{12;-4\right\}\)
1 Tính nhanh
a) \(-14+12+\left(-12\right)\left(2^3-7\right)\)
\(=-14+\left[12+\left(-12\right)\right].1\)
\(=-14+0.1\)
\(=-14+0=-14\)
b) \(\left(-5\right)+2\left(-15\right)-\left(-3\right)+\left|-10\right|\)
\(=\left(-5\right)+\left(-30\right)-\left(-3\right)+10\)
\(=\left(-35\right)-\left(-3\right)+10\)
\(=\left(-32\right)+10\)
\(=-22\)
c) \(68.\left(12+32\right)-32.\left(68-12\right)\)
\(=68.44-32.56\)
\(=2992-1792\)
\(=1200\)
d) \(89-\left(-43\right)-32\)
\(=132-32\)
\(=100\)
e) \(-12.\left(-6\right)^2+\left(-4\right)^3.12\)
\(=-12.36+64.12\)
\(=\left(-12+12\right).\left(36+64\right)\)
\(=0+100\)
\(=100\)
a) Giải ko đc. Kiểm tra lại đề
b) 27.15 + 85.27 - 16.12
= 27(15 + 85) - 16.(10 + 2)
= 27.100 - [(16 . 10)+(16 . 2)
= 2700 - [160 + 32]
= 2700 - 192 = 2508
c) (-12) + 83 + (-48) + 17
= [(-12) + (-48)] + (83 + 17)
= [-70] + 100 = 100 - 70 = 30
MAY MẮN NHÉ!
\(a.\left(-83\right)+302+83\\ =\left(-83+83\right)+302\\ =0+302\\ =302\\ b.14.\left(-7\right)-216:2\\ =-98-108\\ =-206\\ c.56.\left(-32\right)+\left(-68\right).56\\ =56.\left[\left(-32\right)+\left(-68\right)\right]\\ =57.\left(-100\right)\\ =-5700\\ d.2^3-6.\left[25-\left(33-28\right)^2\right]\\ =8-6\left[25-5^2\right]\\ =8-6\left[25-25\right]\\ =8-6.0\\ =8-0\\ =8\\ e.15.\left(-6\right)-420:\left(-4\right)\\ =-90-\left(-105\right)\\ =-90+105\\ =15\)
\(f.63.\left(-52\right)+\left(-48\right).63\\ =63.\left[\left(-52\right)+\left(-48\right)\right]\\ =63.\left(-100\right)\\ =-6300\)